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  • 2 answers

Aadya Singh ? 6 years ago

After 3rd line, there is.. (10-10)(10+10)/10(10-10)

Aadya Singh ? 6 years ago

LHS = 0/0
=> [(10)^2 - (10)^2]/ (100-100)
=> (10-10)(10+10)/ (100-100)
=> (10+10)/10 [since, (10-10) get cancelled by each other]
=> 20/10
=> 2 = RHS
Hence, it's prove...?
  • 3 answers

Yogita Ingle 6 years ago

The factors of 45 are: 1, 3, 5, 9, 15, 45

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

Then the greatest common factor is 1.

Aadya Singh ? 6 years ago

1

Ruchi Agarwal 6 years ago

10
  • 1 answers

Deep Singh 6 years ago

LHS={(sin Φ+cos Φ)+1}{(sin Φ+cos Φ)-1}(sec Φ*cosec Φ)={(sin Φ + cos Φ)^2 -1}(sec Φ*cosec Φ)=(sin^2Φ+cos^2Φ+2sinΦcosΦ-1)(secΦ*cosecΦ)=(2sinΦcosΦ)(1/cosΦsinΦ)=2=RHS
  • 1 answers

Anwesha Boruah 6 years ago

1)total number of outcomes=365 No of favourable outcomes=364 P(they have the different birthday)=364/365 2)total no.of outcomes=365 No of favourable outcome=1 P(same birthday)=1/365
  • 2 answers

Raghav Juyal 6 years ago

thanks

Ayush Pandey 6 years ago

There are 52 cards in a deck of cards. 26 red card and 26 black card. Red card has two sub division - heart (13) and diamond (13). Black card has also two sub division - spade (13) and club (13). Each sub division has three face cards (king,queen and jack) , one ace and 9 number card (2,3,4,.......,10)
  • 5 answers
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Yogita Ingle 6 years ago

101 × 102  = (100 + 1) 102

= 100 (102) + 1(102)

= 10200 + 102

= 10302

10,302

Mayank Kapoor 6 years ago

10302
  • 2 answers

Abbinav Tiwari 6 years ago

3

Raj Patel 6 years ago

SecA=3/2=H/B By Pythagoras theorem, H^2=P^2+B^2 9=P^2+4 P^2=9-4 P^2=5 P=√5 Therefore, According to the question, 2*2/3-(√5/2)^2/(√5/3) 4/3-(5/4)/(5/9) Now by taking LCM u can get the correcy answer!
  • 2 answers

Payal.. ? 6 years ago

4.6 Empirical Relation Between Mean, Median And Mode A distribution in which the values of mean, median and mode coincide (i.e. mean = median = mode) is known as a symmetrical distribution. Conversely, when values of mean, median and mode are not equal the distribution is known as asymmetrical or skewed distribution.
What??
  • 1 answers

Ayush Pandey 6 years ago

Empirical relation for mode, median and mean is given by :- Mode = 3(median) _ 2(mode) Hope this will help you.....
  • 2 answers

Apoorv Darshan 6 years ago

2

Deep Singh 6 years ago

65=13*5 117=3*3*13 Hcf of 65 and 117 is 13 Since, 65m-117=13 =>m=130/65 Therefore, m = 2.
  • 3 answers

Ram ? 6 years ago

3 and 2

Parthiv Patel 6 years ago

The no is 2 or 3.

Roman? Reigns? 6 years ago

No.s are 2+3=5 and reciprocal 1/2+1/3=5/6
  • 2 answers

Riya Rathore 6 years ago

Pi r square upon 4

Hardik Shivam 6 years ago

1/4 pi r square
  • 2 answers

Arnav Bharti 6 years ago

I hope that answer is correct.???

Arnav Bharti 6 years ago

0=5+x/2(mid point theorem since Q is equidistant therefore the ratio will be 1:1) = X=-5 Now , distance between QR=0+(-5)/2(mid point theorem QR=-5/2 And,. Dis. Btw. PR=5+(-5)/2 PR=0
  • 1 answers
Given.....sn=sn To find ............an Since sn=sn an=an an=a+(n-1)d Also........ s(n)-s(n-1) ~it depends on the number of terms(n) ?????
  • 1 answers

Abhinav ? 6 years ago

1.732
  • 1 answers

Bhavya Bhardwaj 6 years ago

2πr=44 r=7 Q÷360×π×r×r 90÷360×22÷7×49 =77÷2=38.5
  • 2 answers

Deep Singh 6 years ago

x^2-(α+β)x+αβ=x^2-(-3+4)x+(-3)*4 =x^2-x-12 Therefore, the quadratic equation is x^2-x-12.

Arpit Maurya 6 years ago

x+3x+4
  • 1 answers

Yogita Ingle 6 years ago

Given AB is the tower.

P and Q are the points at distance of 4m and 9m respectively.

From fig, PB = 4m, QB = 9m.

Let angle of elevation from P be α and angle of elevation from Q be β.

Given that α and β are supplementary. Thus, α + β = 90

In triangle ABP,

tan α = AB/BP – (i)

In triangle ABQ,

tan β = AB/BQ

tan (90 – α) = AB/BQ (Since, α + β = 90)

cot α = AB/BQ

1/tan α = AB/BQ

So, tan α = BQ/AB – (ii)

From (i) and (ii)

AB/BP = BQ/AB

AB^2 = BQ x BP

AB^2 = 4 x 9

AB^2 = 36

Therefore, AB = 6.

Hence, height of tower is 6m.

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