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  • 5 answers

Pk . 6 years ago

Hamne apko galat answer diya hai......???don't mind......kal apke room pe aa ke sahi batayenge.

Pk . 6 years ago

Gupta g boliya....kaha hai abhi motihari ki Ramgarhwa......name mat lijiya ga mera....aap agar pahchan gay ho to call kijiya

Pk . 6 years ago

Abhishek bhai shantiniketan ke.... ka hal ba????

Pk . 6 years ago

Draw a perpendicular on hypotenous of a right angle triangle and similar both new triangle to the main triangle.......hope this help you

Vanshika . 6 years ago

Friend u will find it in the Google in much easier wayy
  • 54 answers
Bye sis gn,st ,tc
Byeee yll
Ok jaisi aapki marji
Meko padhna hh kl subha.... speech bolni hh momday ko usski bhi taiyari krni hh...
..kl to sunday h phir itni jaldi
Chalo bhai byee...ab apko pta chal hi gya hoga ki m itni late tk kyu jagi hui hu...byee
Ya
???...ap bhi toh ho..
Aap bhi to ho future IAS
Bilkul btaungi..
Aap jab yaha aayengi n to batana mai aunga aapse milne
Okh..
Ok ..kl batana
Pta nahi vo kha rehte hh..
Aapka bhai h n...vaise kaha h aapke papa ji ke frnd
Nahi..m kisi ko nahi janti wha..but papa k frnd hh wha
Allahabad me koi h kya aapka
Butter ???
Bilkul acchi ..ejdm butter ki tarah
Ji nahi..mera admission 10 k bad hi ho jayega...allahabad ya Udaypur m se kahi hoga...
Bhai apki padhai kesi chal rahi hh
Ok aap 2021 me aana ok
Hmm ... Shayad aa skti hu
Aap ek kaam krna..aap allahabad aa jana mai yaha aapki help bhi kr dunga
Ha ji
M bhi delhi ki soch rahi thi...but wha k mahol achcha nahi hh.. issliye m Udaypur jaungi...
Ohhh
Ha ji ..but socha h graduation ke baad delhi jauu
Mene bhi unstall krdiya...
Bhai ...ias ki achchi padhai toh wha bhi hoti hh....toh ap wahi padhoge
Maine usse uninstall kr diya
Wese aplog abhi bhi brainly chlate ho???...

Kuhu Vats 6 years ago

Ok bhai
Ha sis
Means allahbad n..
Hm..mene sci ,sst ,maths teeno m likha hh???
Me from prayagraj..up

Kuhu Vats 6 years ago

Anekesh m ganganagar se hu or aap
Are suhu...related t ur maths
Aisa ni h honey sid..aaj mera net ni chal raha h
Hn...bhai..apne booa tha n easy or hard wala toh kr liya likh liya mene....
Merko ignore kr rhe ho.. M ab tumse baat ni krungi.. Bye ????????????tum,shrrya,aadya mere aane p humesha dukhi hi hote Ho
Kya..
Vaise kuhu sis aap kaha se ho
Sis maine jo tumhe bataya tha voa pada

Kuhu Vats 6 years ago

Good
Ok sis ab ni puchuga ..
Mt pucho...?

Kuhu Vats 6 years ago

Prayer krugi aapke liye bhai
Are sis gussa mt hob..maine to bs generally hi pucha h
Ankesh Ese mt bolo aap... Be positive
Same situation merko Shivam ne bhi di thi
M thappad mr dungi...agr aesa kuch bola toh...?
Dua
  • 2 answers

Aashish Gaurav 6 years ago

Cos theta / sin theta - sin theta/ cos theta = (Cos ^ theta - sin^ theta )/sin theta cos theta =[cos^ theta -(1- sin^ theta)] / sin theta cos theta = (2 cos^ theta -1)/ sin theta cos theta

Aashish Gaurav 6 years ago

LHS
  • 6 answers

Riddhi Gaur 6 years ago

sorry, typing mein galti ho gayi thi first wale mein (1+cos theta)
RHS=[1/sin -cos/sin]. ||. [1-cos/sin]². ||. (1-cos)(1-cos)/1²-cos². ||. (1-cos)(1-cos)/(1+ cos)(1-cos). ||. 1-cos/1+cos. ||.

Kuhu Vats 6 years ago

To phir question ko vasi likh kr bejo m solve kr dugi
Yes kuhu is right

Kuhu Vats 6 years ago

May b ek me minus ki jgh plus aaye ga

Kuhu Vats 6 years ago

Riddhi may b aapka question glt h
  • 2 answers
Area of right triangle=1/2×base×height
For Equilateral triangle=√3/4(side)²
  • 1 answers

Pk . 6 years ago

Multiply kar do yrr....
  • 1 answers

Aashish Gaurav 6 years ago

Total salary for first 3 years= (36× 320) =11520 Salary after 12 years = 360 +(12-1)40 =360+440=800 =Total Salary after 3 years and so on for 12 years = 360 × 12+400× 12 ans so on =12× (360+400...) =12×[12/2× {360+(12-1) ×40} =12×[6×(360+440)] =12×6×800 =57600 Let the remaining months of service be x. Now (57600+11520+ 800×x)/36+144+x =698 (69120+800x)/180+x=698 69120+800x= 698×180+698x 102x=56520 x=554 46 years Now his entire service life is 3+12+46=61years
  • 1 answers

Shreya ... 6 years ago

LHS = (Tan thetha+sin theta)^2 - (Tan thetha+sin theta)^2
RHS=4√mn
4√(tan thetha+sin theta)(tan theta-sin theta)
4√(tan^2theta-sin^2theta)
4.√(sin^2theta/cos^2theta-sin^2theta)
4.√sin^2theta-sin^2theta cos^2theta/cos theta = 4.sin theta/cos theta.1√1-cos^2 theta= 4tan.√sin^2 theta = 4 tan theta sin theta.
  • 1 answers

Pk . 6 years ago

Arithmetic progression is the sequence of numbers. Such that the difference between two consecutive number is constant.
  • 1 answers

Sia ? 4 years, 8 months ago

NOT POSSIBLE

  • 2 answers

Abhi Sharma 6 years ago

Hey

Isha Kashyap 6 years ago

Please send basic sample paper
  • 1 answers

Abhinav ? 6 years ago

Basic paper..?? Sample paper aap website se download kr lo..
  • 10 answers

Jayesh King 6 years ago

I am teacher not your age

Riddhi Gaur 6 years ago

Aadya Singh is right
Name mt change krna...achcha naam h apka...???

Aadya Singh ? 6 years ago

Vo to sab mere name ki spelling galat likhate h....to mai kya karu...?
??... spelling hi glt hh aadya singh ki toh...

Aadya Singh ? 6 years ago

Is it right...???

Aadya Singh ? 6 years ago

Circumference of outer circular track = 396
2×22/7×R = 396
R = 396×7/44
R = 63 m. So, Outer radius = 63m.
Now, the circumference of inner radius = (396-44)
2×22/7× r = 352
r = 352×7/44
r = 56m . So, Inner radius = 56m.
Hence, Width of the track = (Outer radius - Inner radius )= (63-56)m = 7m

Aadya Singh ? 6 years ago

By the way...aapko.solution bhi chahiye ya only answer...?

Aadya Singh ? 6 years ago

Aap gyi kya preeti ji..??

Aadya Singh ? 6 years ago

Mere liye itna specially kyu h..?? ?
  • 1 answers

Yogita Ingle 6 years ago

Radius = 70 cm.

No of revolution = 250 / min

No of revolution = 250 × 60 / hour

Now, Circumference = 2 π r

⇒ 2 × 22 / 7 × 70

⇒ 44 × 10

⇒ 440 cm

We have ,

{tex}\sf no \: of \: revolution = \frac{distance}{circumference} \\ \\ \sf \implies distance = 250 \times 60 \times 440 \\ \\ \sf \implies distance = 660000 \: cm \\ \\ \sf \implies distance = \frac{6600000}{100000}km \\ \\ \sf \therefore distance = 66 \: km{/tex}

Speed = distance / time

⇒ speed = 66 km / 1 hour

⇒ speed = 66 km/hr.

  • 3 answers

Yogita Ingle 6 years ago

Let the two consecutive integers be x and x + 1.
Then according to the question, we have:

x2 + (x + 1)2 = 365

⇒ x2 + x2 + 2x + 1 - 365 = 0

⇒ 2x2 + 2x - 364 = 0

⇒ 2(x2 + x - 182) = 0

⇒x2 + x - 182 = 0

⇒x2 + 14x - 13x - 182 = 0

  ⇒ (x + 14) (x - 13) = 0

⇒ x = -14 or x = 13

Since the integers are positive, so neglecting x = -14 , we have x = 12.

Hence 13, 14 are two consecutive positive integers.

Nivesh Rawat 6 years ago

Thanks??

Aadya Singh ? 6 years ago

14 and 13.
  • 1 answers

Aashish Gaurav 6 years ago

For unique solution 2/k should not be equal to 1/8 So except 16 we can put any value
  • 4 answers

Anil Talan 6 years ago

158

Mosin Beg 6 years ago

Here d= 5 but if we take añ as a and a as añ Then d=-5 An=a+(n-1)d =253+19(-5) =253+(-95) =253-95 =158

Aashish Gaurav 6 years ago

T²0= 253+(20-1)×(-5) =253-95 =158

Aashish Gaurav 6 years ago

158
  • 2 answers

Aashish Gaurav 6 years ago

Sorry only a/c should not be equal to b/d

Aashish Gaurav 6 years ago

a/b and b/d and c/a are not be equal to one another

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