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Pk . 6 years ago
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Posted by Ankesh ..?? Now I Am Fully Ready? 6 years ago
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☃️? Queen ?☃️ 6 years ago
☃️? Queen ?☃️ 6 years ago
Ankesh ..?? Now I Am Fully Ready? 6 years ago
Ankesh ..?? Now I Am Fully Ready? 6 years ago
☃️? Queen ?☃️ 6 years ago
Ankesh ..?? Now I Am Fully Ready? 6 years ago
☃️? Queen ?☃️ 6 years ago
Ankesh ..?? Now I Am Fully Ready? 6 years ago
☃️? Queen ?☃️ 6 years ago
Ankesh ..?? Now I Am Fully Ready? 6 years ago
☃️? Queen ?☃️ 6 years ago
Honey... ??#Girl 6 years ago
Ankesh ..?? Now I Am Fully Ready? 6 years ago
Posted by Lucifer ? Morningstar? 6 years ago
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Posted by Lucifer ? Morningstar? 6 years ago
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Shreya ... 6 years ago
RHS=4√mn
4√(tan thetha+sin theta)(tan theta-sin theta)
4√(tan^2theta-sin^2theta)
4.√(sin^2theta/cos^2theta-sin^2theta)
4.√sin^2theta-sin^2theta cos^2theta/cos theta = 4.sin theta/cos theta.1√1-cos^2 theta= 4tan.√sin^2 theta = 4 tan theta sin theta.
Posted by Mahek Mb 6 years ago
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Posted by Jayesh King 6 years ago
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Aadya Singh ? 6 years ago
Aadya Singh ? 6 years ago
2×22/7×R = 396
R = 396×7/44
R = 63 m. So, Outer radius = 63m.
Now, the circumference of inner radius = (396-44)
2×22/7× r = 352
r = 352×7/44
r = 56m . So, Inner radius = 56m.
Hence, Width of the track = (Outer radius - Inner radius )= (63-56)m = 7m
Posted by Jayesh King 6 years ago
- 1 answers
Yogita Ingle 6 years ago
Radius = 70 cm.
No of revolution = 250 / min
No of revolution = 250 × 60 / hour
Now, Circumference = 2 π r
⇒ 2 × 22 / 7 × 70
⇒ 44 × 10
⇒ 440 cm
We have ,
{tex}\sf no \: of \: revolution = \frac{distance}{circumference} \\ \\ \sf \implies distance = 250 \times 60 \times 440 \\ \\ \sf \implies distance = 660000 \: cm \\ \\ \sf \implies distance = \frac{6600000}{100000}km \\ \\ \sf \therefore distance = 66 \: km{/tex}
Speed = distance / time
⇒ speed = 66 km / 1 hour
⇒ speed = 66 km/hr.
Posted by Nivesh Rawat 6 years ago
- 3 answers
Yogita Ingle 6 years ago
Let the two consecutive integers be x and x + 1.
Then according to the question, we have:
x2 + (x + 1)2 = 365
⇒ x2 + x2 + 2x + 1 - 365 = 0
⇒ 2x2 + 2x - 364 = 0
⇒ 2(x2 + x - 182) = 0
⇒x2 + x - 182 = 0
⇒x2 + 14x - 13x - 182 = 0
⇒ (x + 14) (x - 13) = 0
⇒ x = -14 or x = 13
Since the integers are positive, so neglecting x = -14 , we have x = 12.
Hence 13, 14 are two consecutive positive integers.
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