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  • 2 answers
In linear equation higher degree =1 and in Quadratic equation higher degree =2

Unnati Agarwal 6 years ago

By the highest power
  • 4 answers

Arun Kirar 6 years ago

Zeroes are + - root 2

Arun Kirar 6 years ago

Sorry my answer is wrong

Unnati Agarwal 6 years ago

4n square + 8 hai naa

Arun Kirar 6 years ago

Zero of this polynomial is only -1 .
  • 1 answers

Yogita Ingle 6 years ago

Let the two similar triangles ABC and DEF in which AP and DQ are the medians respectively.

we have to prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.

If ΔABC~ΔDEF

{tex}⇒ \frac{ar(BCA)}{ar(EFD)}=\frac{AB^2}{DE^2} {/tex} →   (1)

As ΔABC~ΔDEF

{tex}\frac{AB}{DE}=\frac{BC}{EF}=\frac{2BP}{2EQ}{/tex}

Hence,{tex} \frac{AB}{DE}=\frac{BP}{EQ}{/tex}

In ΔABP and ΔDEQ

{tex}\frac{AB}{DE}=\frac{BP}{EQ}{/tex}

∠B=∠E   (∵ΔABC~ΔDEF)

By SAS rule, ΔABP~ΔDEQ

{tex}⇒ \frac{AB}{DE}=\frac{AP}{DQ}{/tex}

Squaring, we get

{tex}\frac{AB^2}{DE^2}=\frac{AP^2}{DQ^2} {/tex}  →  (2)

Comparing (1) and (2), we get

{tex}\frac{ar(BCA)}{ar(EFD)}=\frac{AP^2}{DQ^2} {/tex} 

Hence, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.

 

 

  • 2 answers

Praduman Bhatia 6 years ago

Yes answer not possible

Sanskar Malviya 6 years ago

Answer not possible
  • 2 answers

Parveen Boora 6 years ago

Smallest prime no.=2 ". Composite no. = 4 HCF = 2

Aadya Singh ? 6 years ago

Smallest prime number = 2
Smallest composite number = 4.
So, HCF = 2.
  • 1 answers

Yogita Ingle 6 years ago

Let the speed of the stream be x km/hr
Then,
Speed downstream = (15 + x) km/hr
Speed upstream = (15 - x) km/hr

∴ 30/(15+x) + 30/ (15−x) = 4 1/2
⇒ 900/(225−x2)  =9/ 2
⇒ 9x2 = 225
⇒x2 = 25
⇒x = 5km/hr

  • 2 answers

Sneha Tyagi 6 years ago

Let root 5 is a rational no. Root 5=p/q (where p and q are co prime) P=root5 q Squaring both side P^2=5q^2 (let eqn. I) 5 is a factor of q^2 5 is a factor of q also , P= 5c for some integer c Put the value of eqn. ( 1 ) 5p^2=(5c)^2 5p^2=25c^2 P^2=5c^2 5 is a factor of p^2 5 is a factor of p also, (Where p and q are integers ) Therefore , our assumption is wrong Root 5 is irrational no.

Yogita Ingle 6 years ago

let root 5 be rational
then it must in the form of p/q [q is not equal to 0][p and q are co-prime]
root 5=p/q
=> root 5 × q = p
squaring on both sides
=> 5 ×q ×q = p ×p  ------> 1
p ×p is divisible by 5
p is divisible by 5
p = 5c  [c is a positive integer] [squaring on both sides ]
p ×p = 25c ×c  --------- > 2
sub p ×p in 1
5 ×q ×q = 25 ×c ×c
q ×q = 5 ×c ×c
=> q is divisble by 5
thus q and p have a common factor 5
there is a contradiction
as our assumsion p &q are co prime but it has a common factor
so √5 is an irrational

  • 2 answers

Yogita Ingle 6 years ago

Integral coordinates are coordinates that are whole numbers. Integral coordinates cannot be fractional or have decimals.

Harbeer Lakra 6 years ago

Taman lakra
  • 19 answers
Hii sis

Kashvi ? 6 years ago

Hn bhai sunao...
Sunado bhaiya ?
Aap itna maths se darti ho meri story sunogi maths ke saath wali to aapko bhi aachi lgegi

Kashvi ? 6 years ago

Chalo m beech beech m ati rahungi...ap so jao...ab subha padhna...byee...
Ok ji

Kashvi ? 6 years ago

Okk bhai padhlo aur so jana....apka kl hindi k exam h all the best subha jaldi udhna hh toh so jao...okk ji..
Thanks sis

Kashvi ? 6 years ago

Bura nahi lga...ap bhai ho ap nahi bologe meko toh kon bolega??
Ni hindi taiyaar h n..to socha sci hi padh lu

Kashvi ? 6 years ago

Ohh...toh hindi padho yll...hindi k paper m sci mt likh kr ana...bro..??
Ohh sorry sis ..agar bura lga ho to
Mera kl hindi h
Yrr vo aaj science complete krni h

Kashvi ? 6 years ago

Bhai jagrata kesa????
Wait kro aap unka
Pta nhi ?
Ya
Who?? Aditi?

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