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Ask QuestionPosted by Aosen Aier 5 years, 11 months ago
- 0 answers
Posted by Harsha Nayak 5 years, 11 months ago
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Posted by Ahmed Raza 5 years, 11 months ago
- 2 answers
Yogita Ingle 5 years, 11 months ago
x2 - 5x + 6 = 0
x2 - 3x -2x + 6 = 0
x(x - 3) - 2(x- 3) = 0
(x - 3) = 0 or x - 2 = 0
x = 3 or x = 2
Posted by Ahmed Raza 5 years, 11 months ago
- 1 answers
Yogita Ingle 5 years, 11 months ago
x2 - 5x + 6 = 0
x2 - 3x -2x + 6 = 0
x(x - 3) - 2(x- 3) = 0
(x - 3) = 0 or x - 2 = 0
x = 3 or x = 2
Posted by Masoom Siddique 5 years, 11 months ago
- 2 answers
Satyam Kumar 5 years, 11 months ago
Yogita Ingle 5 years, 11 months ago
Given √2 is irrational number.
Let √2 = a / b wher a,b are integers b ≠ 0
we also suppose that a / b is written in the simplest form
Now √2 = a / b ⇒ 2 = a2 / b2 ⇒ 2b2 = a2
∴ 2b2 is divisible by 2
⇒ a2 is divisible by 2
⇒ a is divisible by 2
∴ let a = 2c
a2 = 4c2 ⇒ 2b2 = 4c2 ⇒ b2 = 2c2
∴ 2c2 is divisible by 2
∴ b2 is divisible by 2
∴ b is divisible by 2
∴a are b are divisible by 2 .
this contradicts our supposition that a/b is written in the simplest form
Hence our supposition is wrong
∴ √2 is irrational number.
Posted by Laxman Laxman 5 years, 11 months ago
- 2 answers
Swastik Shukla 5 years, 11 months ago
Yogita Ingle 5 years, 11 months ago
The formula used to find the distance between two points is
{tex}d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2} } Where,d = distance = 5\\(x1, y1) = First set of points, i.e A= (0,0)\\(x2, y2) = Second set of points i.e B= (x,-4)d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2} } \\ 5 = \sqrt{(x-0)^{2}+(-4-0)^{2} } \\\\5 = \sqrt{(x)^{2}+(-4)^{2} }\\\\Squaring both sides\\\\25 = x^{2} + 16\\\\25-16 = x^{2}\\\\9 = x^{2}\\\\x = 3{/tex}
Posted by Laxman Laxman 5 years, 11 months ago
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Posted by Vijay Rathore??? 5 years, 11 months ago
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Posted by Naman Yadav 5 years, 11 months ago
- 1 answers
Posted by Hitesh Jaiswal 5 years, 11 months ago
- 1 answers
Vijay Rathore??? 5 years, 11 months ago
Posted by Rohit Rajput 5 years, 11 months ago
- 1 answers
Satish Patel 4 years, 11 months ago
Posted by Amar Arpit 5 years, 11 months ago
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Posted by Asit Chakrabortty 5 years, 11 months ago
- 1 answers
Yogita Ingle 5 years, 11 months ago
Let us find HCF of 52 and 117 by Euclid's division algorithm.
Since 117>52
117 = 52 × 2 + 13
52 = 13 × 4 + 0
Therefore HCF (52, 117) = 13
Now, 13 = 52×(-2) + 117×1
13 = 52x + 117y where X = -2 and y = 1
Posted by Tanya Singh 5 years, 11 months ago
- 1 answers
Gaurav Seth 5 years, 11 months ago
In order to prove that the sum of angles of a triangle is 180, you must know the theorems of angles of a triangle.
We know that, alternate interior angles are of equal magnitude.
This'll help us get the answer. Let us assume a triangle ABC. Now we have to substitute the angles.
∠PAB + ∠BAC + ∠CAQ = 180°. where PQ line parallel to side BC touching vertex A.
∠PAB = ∠ABC & ∠CAQ = ∠ACB BECAUSE alternate interior angles are congruent..
Hence we get, ∠ABC + ∠BAC + ∠ACB = 180° [Proved]
Posted by Sanjana Pal 5 years, 11 months ago
- 2 answers
Sudhanshu Shivam 5 years, 11 months ago
Posted by Shivangi Meena 5 years, 11 months ago
- 4 answers
Posted by Vijay Rathore??? 5 years, 11 months ago
- 1 answers
Gaurav Seth 5 years, 11 months ago
Let first term be a and common difference be d.
pth term = a + (p-1)d = q -----(i)
qth term = a + (q-1)d = p -----(ii)
(ii) - (i) gives
(q - p)d = p - q or d = -1
(i) gives a = q - (p-1)d = q - (p-1)(-1) = q + p - 1
Hence,
nth term = a + (n-1)d = q + p -1 + (n-1)(-1) = q + p -1 + n +1 = p + q - n
Posted by Vijay Rathore??? 5 years, 11 months ago
- 1 answers
Gaurav Seth 5 years, 11 months ago
Given ratio of sum of n terms of two AP’s = (7n+1):(4n+27)
Let’s consider the ratio these two AP’s mth terms as am : a’m →(2)
Recall the nth term of AP formula, an = a + (n – 1)d
Hence equation (2) becomes,
am : a’m = a + (m – 1)d : a’ + (m – 1)d’
On multiplying by 2, we get
am : a’m = [2a + 2(m – 1)d] : [2a’ + 2(m – 1)d’]
= [2a + {(2m – 1) – 1}d] : [2a’ + {(2m – 1) – 1}d’]
= S2m – 1 : S’2m – 1
= [7(2m – 1) + 1] : [4(2m – 1) +27] [from (1)]
= [14m – 7 +1] : [8m – 4 + 27]
= [14m – 6] : [8m + 23]
Thus the ratio of mth terms of two AP’s is [14m – 6] : [8m + 23].
Posted by Raj Varshney 5 years, 11 months ago
- 1 answers
Vijay Rathore??? 5 years, 11 months ago
Posted by Tanya Singh 5 years, 11 months ago
- 2 answers
Posted by Rekha Devi 5 years, 11 months ago
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Posted by Pankaj Yadav 5 years, 11 months ago
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Posted by Sharique Alam 5 years, 11 months ago
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Posted by Deepanshu Saini 5 years, 11 months ago
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Posted by Raj Mishra 5 years, 11 months ago
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Posted by Yuvraj Singh Rajput 5 years, 11 months ago
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??Rupi.... ..?? 5 years, 11 months ago
Posted by Megha Danu 5 years, 11 months ago
- 1 answers
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