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  • 1 answers

Yogita Ingle 6 years, 3 months ago

Formula of first n terms in AP = {tex}S_n = \frac{n}{2}(2a+(n-1)d){/tex}

Substitute n = 7

So,{tex} S_7 = \frac{7}{2}(2a+6d){/tex}

{tex}49 = \frac{7}{2}(2a+6d){/tex}

{tex}49 \times \frac{2}{7} = 2a+6d{/tex}

14= 2a+6d

Substitute n = 17

{tex}S_{17} = \frac{17}{2}(2a+16d){/tex}

{tex}289 = \frac{17}{2}(2a+16d){/tex}

{tex}289 \times \frac{2}{17} = 2a+16d{/tex}

34= 2a+16d

34= 2a+10d+6d

Using A

34= 14+10d

20 = 10d

d=2

Substitute the value of d in A

14= 2a+12

2= 2a

a=1

So, {tex} S_n = \frac{n}{2}(2(1)+(n-1)2){/tex}

{tex}S_n = \frac{n}{2}(2+(n-1)2){/tex}

 

  • 1 answers

Yogita Ingle 6 years, 3 months ago

The given points are (7, 2) and (-1, 0)

The slope of the line is given by

{tex}m=\frac{y_2-y_1}{x_2-x-1}{/tex}

Substituting the values

{tex}m=\frac{0-2}{-1-7}\\\\m=\frac{-2}{-8}\\\\m=\frac{1}{4}{/tex}

Point slope form of a line is given by

{tex}y-y_1=m(x-x_1)\\\\y-2=\frac{1}{4}(x-7)\\\\4y-8=x-7\\\\4y=x+1{/tex}

 

  • 3 answers

Madhu Sharma 6 years, 3 months ago

No

Miss .K ?? 6 years, 3 months ago

a+(n-1)d =-150 11+(n+1)(-3)=-150 11-3n+3=-150 14-3n=-150 -3n=-150-14 -3n=-164 n =164/3. No, 150 is not the the term of ap

Munesh Gupta 6 years, 3 months ago

Lol
  • 1 answers

Yogita Ingle 6 years, 3 months ago

First term =a
second term =b
last term =c
common difference=(b-a)
tn =a+(n-1) d

c=a+(n-1) d

(c-a)=(n-1)(b-a)

(c-a)/(b-a)+1=n

( c+b-2a)/(b-a)=n--------------------(1)
now ,
we know sum of n terms=n/2 (first term+last term)
put equation (1)value
= (b+c-2a)/(b-a)(a+c)
hence Sn=[(b+c-2a)(c+a)/(b-a)]

  • 8 answers

Omm Upadhyay 6 years, 3 months ago

1

Nitin Raghuvanshi 6 years, 3 months ago

0

Aarohi Jha 6 years, 3 months ago

Probability of an impossible event is 0.

Parishi Thada 6 years, 3 months ago

0

Amit Bhatia 6 years, 3 months ago

0

Rishu Raj 6 years, 3 months ago

P(T)=0,when T is an impossible event

?Urstruley Ashu? 6 years, 3 months ago

0

Abhinav ? 6 years, 3 months ago

0
  • 7 answers

Omm Upadhyay 6 years, 3 months ago

No on read mathematics ncert not other book ??

Neel Mistry 6 years, 3 months ago

Hii

Rishu Raj 6 years, 3 months ago

Prepare hard and learn all formula first . Then understand what question says.????

?Urstruley Ashu? 6 years, 3 months ago

Practice more in maths text book

Diksha ? 6 years, 3 months ago

Practice and just practice?first ncert clear kr lo then alag kuch krna

Priyanshu Kumar ????? 6 years, 3 months ago

Practice

Nasim Bukhari 6 years, 3 months ago

10 hours study
  • 1 answers

Abhinav ? 6 years, 3 months ago

Where are the shapes??
  • 1 answers

Aarthy Kamaraj 6 years, 3 months ago

You can get all sample papers from www.cbse.online
  • 4 answers

Khushi Singh 6 years, 3 months ago

Bata nhi shakte par.hint to kar shakte ho?

Viswajeet Sharma 6 years, 3 months ago

Waise ek hint de sakte gau

Viswajeet Sharma 6 years, 3 months ago

Thoda long solution hi isiliye issme nhi bana sakte

Viswajeet Sharma 6 years, 3 months ago

Isse aap net mau giigle pe search kar lo
  • 1 answers

Palak Verma 6 years, 3 months ago

a7=1/9 a+6d=1/9 let it be eq 1 a9=1/7 a+8d=1/7 let it be eq 2 Now substitute both by elimination method you will get value of a and d Then put it in a+62d You will get your answer
  • 1 answers

Khushi Singh 6 years, 3 months ago

3x² - 5x+2 3x²-3x-2x+2 3x(x-1) -2(x-1) (X-1)(3x-1) X=1 x =1/3
  • 2 answers

Mr Gayab 6 years, 3 months ago

Only write construction

?Raj ? 6 years, 3 months ago

I can't draw it here please write your question on google you will get your ans
  • 3 answers

Khushi Singh 6 years, 3 months ago

Let 5√3 be a rational number. a/b=5√3 a/5b=√3 a/5b is a rational number.So,√3 is also a rational number. But the fact is that √3 is a irrational number. 5√3 be an irrational number.

Sambhav Maheshwari 6 years, 3 months ago

prove that 5√3 is irrational no Let 5√3 is rational number. 'a' and 'b' are two co-prime factor. a/b = 5√3 a/5b=√3 : Here a/5b are a rational Number. : √3 is also a rational Number. :: but it is contradiction because we know that √3 is irrational number. : :5√3 is a irrational number.

☣️Roman ☣️ 6 years, 3 months ago

Watch the example given on the ncert book?
  • 1 answers

Nitish Vishwakarma 6 years, 3 months ago

We know that in triangle ABC Angle (A + B + C) = 180 Transfer angle on right side, Angle(A+B) = 180- Angle C Dividing 2 on both side , we get Angle(A+B)/2 = 90 - Angle C/2 Multiply sin on both side sin A+B/2 = sin(90-C/2) sin A + B/2 = cos C/2
  • 2 answers

Sambhav Maheshwari 6 years, 3 months ago

a + 2d +a + 6d=6 2a + 8d=6 Divide by 2 a + 4d = 3 (1) (a + 2d) (a + 6d) = 8. (2) From (1) a =3-4d Put the value of a in eq(2) (3-4d +2d) (3-4d + 6d) = 8 (3-2d) (3 +2d) =8 (3)^2 - (2d)^2 =8 9 - 4d = 8 -4d= 8-9 d= 1/4 Put the value of d in eq(1) a= 3 - 4(1/4) a= 3 -1 a=2 Sn =n/2(2a + (n - 1)d) S16= 16/2(2(2) + (16 -1)1/4) S16=8(4 +15/4) =8( 16+15/4) =8(31/4) =2(31) =62 ans

Viswajeet Sharma 6 years, 3 months ago

76
  • 2 answers

#Army #Bts 6 years, 3 months ago

Thank you so much ?

Parul Ailawadi 6 years, 3 months ago

d=7-(2p-1)=7-2p+1=8-2p d=(11p/2)-7 =(11p-14)/2 Therefore, 8-2p=(11p-14)/2 16-4p=11p-14 16+14=11p+4p 30=15p 30/15=p p=2
  • 2 answers

Rishu Raj 6 years, 3 months ago

Value of X=1and Y=1

Shiven Handa 6 years, 3 months ago

8x+7y/xy=15 and 7x-2y/xy=5 8x+7x=15 and 7x-2x=5 15x=15 and 5x=5 x=1 and x=1 Putting x=1 in eq.(1) 8x+7y/xy=15 8x+7y=15xy 8×1+7y=15×1×y 8+7y=15y 8=15y-7y 8=8y y=1 Hence x=1 and y=1 .
  • 3 answers

Rishu Raj 6 years, 3 months ago

Let,A(4,-6) ,B(0,y) and C(-7,-4). AB=X1=4,Y1=-6 ,BC=X1=0,Y1=Y X2=0,Y2=y , X2=-7,Y2=-4 AB=BC (0-4) ² +(Y-6)²=(-7-0)²+(-4-Y)² 16+Y²+36+2×Y×6=49 +16+y²-2×-4×-y 16+y²+36+12y=49+16+y²+8y 52+y²+12y=55+ý²-8y

Piyush Meena 6 years, 3 months ago

Pg 166 example 9

Piyush Meena 6 years, 3 months ago

You can take help from book

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