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Posted by Vaishnavi Gawade 6 years, 3 months ago
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Yogita Ingle 6 years, 3 months ago
The median for the coordinates of intersection point of less than ogive and more than ogive will be-
The median of grouped data is the x-coordinate of the point of intersection of the two ogives. Here, the ‘less than ogive’ and ‘more than ogive’ intersect at (13.5, 20).
so, median = 13.5
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Aadya Singh ? 6 years, 3 months ago
Sec^2A - (tan^2 - 2tanA+ 1)
Sec^2A - tan^2A + 2tanA - 1
1+2tanA -1
Now, LHS = RHS. So, it's prove..
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Parul Ailawadi 6 years, 3 months ago
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Abhinav ? 6 years, 3 months ago
Abhinav ? 6 years, 3 months ago
Abhinav ? 6 years, 3 months ago
Abhinav ? 6 years, 3 months ago
Abhinav ? 6 years, 3 months ago
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??????? ? 6 years, 3 months ago
Posted by Manjeet Kumar Kushwaha 6 years, 3 months ago
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Yogita Ingle 6 years, 3 months ago
Distance of a point P (a, b) from X-axis is |b| and from Y-axis is |a|.
Therefore, the distance of point P(-3, -4) from X-axis is 4 (as distance is never negative).
Posted by Raushan Raj Yarav Groups Yadav 6 years, 3 months ago
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Posted by Kunwar Singh Negi 6 years, 3 months ago
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Yogita Ingle 6 years, 3 months ago
speed of aircraft= x
Distance = 2800 km
Time = Distance / Speed = 2800/x
Given:
The speed has reduced by 100 and time is reduced by 30 min
New speed = (x – 100)
That is, 30 min = 30/60 hr = (1/2) hr
Time taken= 2800/(x – 100) hr
=2800/(x – 100)
= (2800/x) + (1/2)
2800/(x-100) -` (2800/x) = 1/2
x² - 100x - 560000 = 0
x² - 800x + 700x - 560000 = 0
x(x - 800) + 700(x - 800) = 0
(x + 700) (x - 800) = 0
SO,
x = - 700 or 800
Thus original duration of the flight = 2800/800 = 7/2 hours
OR = 3 hr 30 mins
Posted by Suniksha Bhatia 6 years, 3 months ago
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Posted by Suniksha Bhatia 6 years, 3 months ago
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Posted by Sam Kd 6 years, 3 months ago
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Aadya Singh ? 6 years, 3 months ago
Smallest composite number = 4
So, LCM = 20...

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??????? ? 6 years, 3 months ago
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