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  • 1 answers

Pk . 6 years, 3 months ago

17/15
  • 2 answers

Poonam Sinha 6 years, 2 months ago

x+10-2x=3x+2-x-10 and solve it answer will be 6

Pk . 6 years, 3 months ago

6
  • 2 answers

Sandesh Patil 6 years, 2 months ago

Thanks

Pk . 6 years, 3 months ago

27 th
  • 2 answers

Neha Kumari 6 years, 3 months ago

And bisect each other at o p (x y)=-2+x/2;-1+3/2=-2+x/2;2/2=-2+x/2;1 From point A and C since pxy is the mid point of AC From point B and D p(xy )=3+1/2;y+0/2=2;y+0/2 -2+x/2=2 Y+0/2=1 On. Solving this equation we get x=2, y=2

Neha Kumari 6 years, 3 months ago

Let ABCD is a parallelogram
  • 1 answers

Diksha? 6 years, 3 months ago

At first find out the curved surface area of the hemispherical bowl by using the formula 2 pie r^2, taking r=5.25cm. Then multiply the area by 0.16( standard in rupees)
  • 0 answers
  • 1 answers

Yogita Ingle 6 years, 3 months ago

11x+15y+23=0
11x+15y= -23. (equ.1st)

7x-2y-20=0
7x-2y=20. (equ.2nd)

11x+15y=-23
7x-2y = 20

multiply by (2) in equ. 1st &( 15) in equ. 2nd we get.

22x+30y= -46. ( equ. 3rd)
105x-30y= 300. (equ. 4th)
_____________
127x=254

X=254/127
X = 2.

put the value of X in equ. 2nd

7x-2y=20
7(2)-2y =20. (X=2)
14-2y =20
-2y=20-14
-2y= 6
y= 6/-2
y=-3.

Your answer => X = 2 , Y= -3.

  • 3 answers

Jay Darji 6 years, 2 months ago

Common difference

Vidyotma Singh 6 years, 3 months ago

Common difference of a.p d=a2-a1

Akhifa Sheik 6 years, 3 months ago

Common difference
  • 4 answers

Dr Chhavi 6 years, 3 months ago

It was so simple.thank you guys

Vidyotma Singh 6 years, 3 months ago

Sin(45+A)-cos(45-A) =sin(90-(45+A))-cos(45-A) =cos(45-A)-cos(45-A) =0

Yogita Ingle 6 years, 3 months ago

  sin(45° + A) - cos(45° - A)

=  sin(45° + A) - sin[90° - (45° - A)]

= sin(45° + A) - sin(90° - 45° + A)

= sin(45° + A) - sin(45° + A)

= 0.

Vidyotma Singh 6 years, 3 months ago

?hmm...
  • 2 answers

Surender Kumar 6 years, 3 months ago

4,12

Rehan Shaikh 6 years, 3 months ago

K= 4 and k= 12
  • 6 answers

Santosh Kumar 6 years, 3 months ago

Jasjs

Surender Kumar 6 years, 3 months ago

39/14

Surender Kumar 6 years, 3 months ago

Thanks

Pk . 6 years, 3 months ago

Sorry for being late....

Pk . 6 years, 3 months ago

39/14

Rehan Shaikh 6 years, 3 months ago

Plz reply
  • 2 answers

Queen_ Of _My _Heart 6 years, 3 months ago

X is an variable

Prabhat Kumar 6 years, 3 months ago

X is a any type of integar
  • 3 answers

Nita Sharma 6 years, 3 months ago

U can find the method in 8 class maths book

Queen_ Of _My _Heart 6 years, 3 months ago

Better to search on goggle

Pratyush Jhala 6 years, 3 months ago

Yes
  • 1 answers

Kanan Soni 6 years, 3 months ago

roots are:--- x=√2,. -1/3√2
  • 2 answers

___ Alone _____ 6 years, 3 months ago

Yll meko ankesh bro ki yaad aari h..???

___ Alone _____ 6 years, 3 months ago

??...
  • 2 answers

Kumar Suman 6 years, 3 months ago

Take LHS (AD^2)and solve

Pk . 6 years, 3 months ago

Consider every side as 'a 'unit and then apply Pythagoras theorem
  • 2 answers

Pk . 6 years, 3 months ago

Sin{(b+c)/2}=sin{(180-a)/2} =Sin(90-a/2)=cos a/2

Prashuk Jain 6 years, 3 months ago

a+b+c=180°. abc is a triangle b+c=180°-a taking rhs sin(b+c/2) sin(180-a/2) sin(180/2-a/2) sin(90-a/2) cos(a/2)
  • 2 answers

Pk . 6 years, 3 months ago

1.33333333333333333333333.......................

Akhifa Sheik 6 years, 3 months ago

1.33
  • 4 answers

Sachi Chanani 6 years, 3 months ago

0

Pk . 6 years, 3 months ago

0

Aadya Singh ? 6 years, 3 months ago

Zero

Geeta Wadhwa 6 years, 3 months ago

cos^2 72° - sin^2 18° cos^2 (90-72) - sin2 18 Sin2 18- sin2 18 = 0
  • 1 answers

Akhifa Sheik 6 years, 3 months ago

Diagram toh nhi kar sakti... Given: abcd is a rectangle circumscribing a circle. Ab = dc Ad=bc Ye do eq. One h.....reason (opposite sides of rectangle r equal) To PT: abcd is a sq. Proof: Tangents frm an external points to the circle are equal. Therefore,ap=as.......eq 2 Bp=bq...........eq 3 Dr=ds.......eq 3 Cr=cq.........eq 4 By adding these equations Ab+bp+dr+cr=as+bq+ds+cq Ab+bp+dr+cr=as+ds+bq+cq Ab+dc=ad+bc Ab+ab=ad+ad(from eq 1) 2ab=2ad Ab=ad Hence proved
  • 2 answers

Tk Kumawat 6 years, 3 months ago

1/2{4(5-7)+7(7-2)+9(2-5) 1/2{-8+35-27} 1/2×0 =0

Dev Dayal Tyagi 6 years, 3 months ago

1/2[4(5-7)+7(7-2)+9(2-5)]=0
  • 0 answers

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