CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

In 52 playing cards ,find the probablity of (i)an ace Ans.total outcomes=52 Possible outcomes=4(since 4 aces) Probablity of and ace=4/52=2/26=1/13 Therefore ur ans is 1/13

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Quadratic equation formula

Posted by Rahul Kumar 6 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

*Shirin? * 6 years, 2 months ago

X=+-b√D/2a

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*Shirin? * 6 years, 2 months ago

D=b square -4ac

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Alok Goutam 6 years, 2 months ago

X = -b +_ root b^2- 4ac/ 2a

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Why are you not show solution

Posted by Muskan Malik 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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" Don't settle. Don't finish crappy books. If you don't like the menu, leave the restaurant. If you're not on the right path, get off it. "

Posted by ⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Aadya Singh ? 6 years, 2 months ago

Good morning bro..?

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Aadya Singh ? 6 years, 2 months ago

????

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___ Alone _____ 6 years, 2 months ago

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Abhinav ? 6 years, 2 months ago

Yes bro..????

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Shreya ?? 6 years, 2 months ago

????

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Tan2a=cot(90-2a)

Posted by Harsh Jain 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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A drinking glass is in the shape of a frustum of a cone of height 14cm. The diameters of its two circular enfs are 4cm and 2cm. Find the capacity of the glass.

Posted by Vaishnavi Dhandale 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Jagdish 6 years, 2 months ago

Capacity of the glass = Volume of glass =1/3×π(R^2+r^2+Rr)h = 1/3×22/7×14×(4+1+2) = 308/3 cubic centimetres

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⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago

Volume....

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Drow a right triangle in which the sides containing the right angle are 5cm and 4 cm constuct a similar triangle whose sides are 5/3 times the side of the above triangle

Posted by Abhishek Pathak 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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What's second one month

Posted by Bharat Mandal 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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3x+y=1 (2k-1)x+(k-1)y=2k+1 find the value of k

Posted by Jatin Parashar 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

ABC is a triangle, right angled at C and p is the length of perpendicular from C to AB. Then, A. pa=bc B. pc=ab C. pb=ac D. none of these Which option is correct

Posted by Sachin Dhanda 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago

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In 11 aap log kya loge?

Posted by Abhay Chauhan 6 years, 2 months ago

CBSE > Class 10 > Mathematics

12 answers

Khushi Singh 6 years, 2 months ago

Aap chaho to le shakte ho commerce ke sath option me maths.... Dhruv Science to leloge....Aage science tumhara lega??

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Aadya Singh ? 6 years, 2 months ago

Oh...mujhe nhi pta tha...?...but maine google baba se pucha to pta chal gya ????

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? ... 6 years, 2 months ago

If you want you can take both

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Sahil Singh 6 years, 2 months ago

Commerce sahi ha mane bhi Commerce hi le ha 11th mae

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Aadya Singh ? 6 years, 2 months ago

But khushi...how can you take both the subjects....???? ?...You will have to choose only one either maths or commerce...

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Khushi Singh 6 years, 2 months ago

Burai kya hai??commerce with math lene me...?

2Thank You

Sahil Singh 6 years, 2 months ago

Already in 11th class

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Abhinav ? 6 years, 2 months ago

Maths

1Thank You

Abhay Chauhan 6 years, 2 months ago

Really ?

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Abhay Chauhan 5 years, 11 months ago

Wtf

2Thank You

Khushi Singh 6 years, 2 months ago

Commerce with maths

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Aadya Singh ? 6 years, 2 months ago

Maths..

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Find the value of x by factorisation , x-1÷x=3

Posted by Rangnath Singh Yadav 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Royal ?? Chundawat 6 years, 2 months ago

X - 1/X = 3 X'2-1 = 3x (by L CM) x2-3x-1=0 Now u can find the discriminant

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Find the first positive term of A.P. -65,-58,-51...

Posted by Kavana Tn 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Jagdish 6 years, 2 months ago

For first positive term an>0 a+(n-1)d>0 -65+(n-1)7>0 -65+7n-7>0 7n>72 n>72/7 Therefore 11th term of given A.P. is postive a11=-65+(11-1)7 a11=-65+70=5

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Find a rational number between √2and√7

Posted by Aman Sharma 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Akhifa Sheik 6 years, 2 months ago

How to find it...can anyone help me

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Aadya Singh ? 6 years, 2 months ago

1.25

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Find the HCF of 36,96,120

Posted by Worlds Top10#### 6 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Jagdish 6 years, 2 months ago

36=2×2×3×3 96=2×2×2×2×2×3 120=2×2×2×3×5 Therefore HCF(36,96,120)=2×2×3=12

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Dinesh Kumar Dwivedi 6 years, 2 months ago

By Euclid's division lemma on 36 and 96 a=bq+r , where r is equal to or greater than 0 and smaller than b Since 96 is greater than 36 Therefore a= 96 and b= 36 Now, 96=36×2+24 36=24×1+12 24=12×2+0 Since 12 is the last divisore therefore 12 is HCF of 36 and 96 Now, we will take HCF of 12 and 120 By Euclid's division lemma a=bq+r, where r is equal to or greater than 0 and smaller than b Since 120 is greater than 12 Therefore a= 120 and b= 12 Now, 120=12×10+0 Since 12 is the last divisore therefore 12 is HCF of 12 and 120. Therefore HCF of 120,96 and 36 is 12

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Yogita Ingle 6 years, 2 months ago

On applying euclid's division Lemma for 36 and 96

96 = 36 ×2 + 24

Here, Remainder = 24≠0

So take new Dividend as 36 and divisor as 24.

36 = 24×1 +12

Here, Remainder = 12≠0

So take new Dividend as 24 and divisor as 12.

24 = 12×2 +0

Here, the Remainder = 0 and the last divisor is 12.

So, HCF of 36 and 96 is 12.

On applying euclid's division Lemma for 12 and 120

120 = 12 ×10 + 0

Here Remainder = 0

So , HCF of 36, 96 and 120 is 12.

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Prove that pythagoras theorem and thales theorem

Posted by Yuvraj Gupta 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the 4th term from the end of the AP 11,-8,-5,..........49

Posted by Sonu Army 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 2 months ago

Given A.P:

-11,-8,-5,.….,49

first term (a) = -11,

{tex}Common\: difference (d)\\=a_{2}-a_{1}\\=-8-(-11)\\=-8+11\\=3{/tex}

Now,

Rearranging the terms , from last to first ,we get

49,46,...,-5,-8,-11

first term (a) = 49,

d = 46-49 = -3

{tex}Fourth\:term (a_{4})=a+3d{/tex}

{tex}=49+3\times (-3)\\=49-9\\=40{/tex}

Therefore,

{tex}Fourth\:term\:the \:last \:of\\the \:A.P = 40{/tex}

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Yuvraj Gupta 6 years, 2 months ago

4th term of ap is 29

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Exercise5.4question no2

Posted by Yashoda Devi 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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If a quadrtic equation px2- 2root5px+15

Posted by Rachnanitin Sachdeva 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Rachnanitin Sachdeva 6 years, 2 months ago

Use discriminent method and take the comman and value of it is 0 & 3

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Find the roots of the quadratic equation ad²x(ax/b+2c/d)c²b=0

Posted by Lucky Kanger 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Sum of two zeroes of a polynomial of degree 4 is -1 and there product is -2 if two zeroes are √3 and √-3 .find polynomial

Posted by Bhumika Singhvee 6 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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