Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Little Life Love 6 years, 2 months ago
- 1 answers
Posted by Priyanshu Ekka 6 years, 2 months ago
- 0 answers
Posted by Md Zahid 6 years, 2 months ago
- 0 answers
Posted by Harsh Srivastav 6 years, 2 months ago
- 2 answers
Yogita Ingle 6 years, 2 months ago
HCF of 404 and 96
404 = 2×2×101
96 = 2×2×2×2×2×3
Common Factors = 2×2
HCF of 404 and 96 = 4
LCM of 404 and 96
404 = 2×2×101
96 = 2×2×2×2×2×3
LCM = 2×2×2×2×2×3×101 = 9696
LCM of 404 and 96 is 9696
HCF × LCM = Product of the two numbers
⇒ 4×9696 = 404×96
⇒ 38784 = 38784
LHS = RHS
Hence, it is verified.
Posted by Pankaj Tiwari 6 years, 2 months ago
- 0 answers
Posted by Shikhar Sethi 6 years, 2 months ago
- 2 answers
Posted by Venkatesan Venkatesan 6 years, 2 months ago
- 2 answers
Posted by ⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
- 28 answers
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
Posted by Yogesh Kumar 6 years, 2 months ago
- 1 answers
Posted by Ansh Pathak 6 years, 2 months ago
- 3 answers
Ram Baran 6 years, 2 months ago
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
Posted by Dinesh Kumar 6 years, 2 months ago
- 2 answers
⛩️Singh Emperor? (Believe In Study) 6 years, 2 months ago
Posted by Shagun Rajput 6 years, 2 months ago
- 1 answers
Posted by Shamsher Singh 6 years, 2 months ago
- 3 answers
Posted by Lala Ram Gurjar 6 years, 2 months ago
- 1 answers
Deepanshu Tyagi 6 years, 2 months ago
Posted by Yash Mishra 6 years, 2 months ago
- 1 answers
Chitresh Khandal 6 years, 2 months ago
Posted by Arviend Patel 6 years, 2 months ago
- 3 answers
Deepanshu Tyagi 6 years, 2 months ago
Posted by Nikita Yadav 6 years, 2 months ago
- 2 answers
Posted by Ayush Kingmaker ??? 6 years, 2 months ago
- 4 answers
Posted by Ritisha Gupta 6 years, 2 months ago
- 1 answers
Srastadutta Mishra 6 years, 2 months ago
Posted by Hridya Girish 6 years, 2 months ago
- 0 answers
Posted by Ishita Sharma 6 years, 2 months ago
- 1 answers
Shirin .Pvt 6 years, 2 months ago
Posted by sati****@***** 6 years, 2 months ago
- 1 answers
Posted by Chandan Kumar 6 years, 2 months ago
- 0 answers
Posted by Sujit Kumar 6 years, 2 months ago
- 0 answers
Posted by Tanya Jangra 6 years, 2 months ago
- 0 answers
Posted by Rohit Singh 6 years, 2 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Yogita Ingle 6 years, 2 months ago
Given: ΔABC ~ ΔPQR. &
ar ΔABC =ar ΔPQR
To Prove: ΔABC ≅ ΔPQR
Proof: Since, ΔABC ~ ΔPQR
ar ΔABC =ar ΔPQR. (given)
ΔABC / ar ΔPQR = 1
⇒ AB²/PQ² = BC²/QR² = CA²/PR² = 1
[ USING THEOREM OF AREA OF SIMILAR TRIANGLES]
⇒ AB= PQ , BC= QR & CA= PR
Thus, ΔABC ≅ ΔPQR
[BY SSS criterion of congruence]
0Thank You