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  • 1 answers

Pradum Gurjar 6 years, 2 months ago

Sn=n/2[2a+(n-1)d] S10=10/2[2a+(10-1)d] 210=5[2a+9d] By transposing 210÷5=2a+9d 2a+9d=42••••••(1) Last 15th term=50-15 =35 S35=2565 S35=35/2[2a+(n-1)d] 2565=35/2[2a+(35-1)d] 2565=35a+34d•••••(2) By elimination
  • 3 answers

Arpit Srivastava 6 years, 2 months ago

no anynew paper

Rajeshwari Bidiyasar 6 years, 2 months ago

I hope easy than last year papers

Clm Gy 6 years, 2 months ago

Not sure..but almost same like that..
  • 2 answers

Arpit Srivastava 6 years, 2 months ago

32nd term

Ayushi Rawat 6 years, 2 months ago

The answer is 32nd term
  • 2 answers

Arpit Srivastava 6 years, 2 months ago

a part of cone

Aadya Singh ? 6 years, 2 months ago

1/3πh[R2 + r2 + Rr]
  • 0 answers
  • 2 answers

Bhumika Agrawal 6 years, 2 months ago

636 is the sum of 12 terms

Mudit Bansal 5 years, 11 months ago

12 is the answer Hi are u single
  • 2 answers

Bhumika Agrawal 6 years, 2 months ago

You have to refer refresher

Riya Rathore 6 years, 2 months ago

U have to refer refresher
  • 2 answers

Bhumika Agrawal 6 years, 2 months ago

x=-1

Aadya Singh ? 6 years, 2 months ago

x = -1
  • 2 answers

Bhumika Agrawal 6 years, 2 months ago

It is not compulsory sometime is true and sometime is false

Vaani Maini 6 years, 2 months ago

No false
  • 4 answers

Vaani Maini 6 years, 2 months ago

Important seniour or significant

Diksha? 6 years, 2 months ago

Major means big. For eg. There are two arcs in a circle,the larger one will be called major arx

Ravinder Rawat 6 years, 2 months ago

Hap bhan k land

Ayush Sharma 6 years, 2 months ago

Batao na major kya hai
  • 2 answers

Yogita Ingle 6 years, 2 months ago

Given the point P(2,3).

We have to find the distance from x-axis i.e perpendicular distance from x-axis.

In the graph , we see in order to determine the perpendicular distance the point of x-axis to be taken is (2,0)

Therefore, the distance is 3-0=3.

Hence, the distance of point P(2,3) from x-axis is 3 units.

 

Chirag Sharma 6 years, 2 months ago

2
  • 0 answers
  • 1 answers

Piyush Kr.?? 6 years, 2 months ago

Don't worry about that this will be not required....
  • 4 answers

Ajay ???? 6 years, 2 months ago

Let the red balls be x Probability of not red is 18-x/18 ii) x/20= 9×(18-x)/8×18 x/20=162-9x/144 144x=20(162-9x) 144x=3240-180x 144x+180x=3240 324x=3240 x=10

Ashwani Yadav 6 years, 2 months ago

If i consider 2 balls are red then x = 8

Ashwani Yadav 6 years, 2 months ago

Your question is not clear. Because u have not mentioned which 2 balls .

Piyush Kr.?? 6 years, 2 months ago

Since, the value of x comes 10...hence the probability of the ball not to be red is 4/9 in first case.!!!!
  • 2 answers

Sshivam Tyagi 3 years ago

No its clearly written at the bottom left of the page of the optional exersices that they are not from exam point of view but its good for practice i will not even come in standard

Arjun Sharma 6 years, 2 months ago

See the cbse paper pattern has changed recently. Therefore, nobody really have an idea about What is gonna come in standard but may not be coming in basic. Therefore, my advice would be, try to attempt all the questions from ncert
  • 5 answers

Sai Samar Sinha 6 years, 2 months ago

Ya ,better bt not excellent.

Ankush Raj 6 years, 2 months ago

U should look to some reference book? also

Ankush Raj 6 years, 2 months ago

I don't think so

Dinesh Kumar 6 years, 2 months ago

Yes,but in perfect manner and also in bord

S.Abiskar Ashutosh 6 years, 2 months ago

No
  • 3 answers

Bhumika Agrawal 6 years, 2 months ago

Given positive integer A and B such that unique integer q and r satisfy a = bq + r zero equal to greater than r less than b

Riya Kumari Shah 6 years, 2 months ago

Where 0≤b<r *

Riya Kumari Shah 6 years, 2 months ago

a=bq+r, where 0 ≤ r <b
  • 6 answers

Miss. 1234 6 years, 2 months ago

hence, we conclude that 4P² + 4P is divisible by 8 for all natural number . hence, n² -1 is divisible by 8 for all odd value of n .

Miss. 1234 6 years, 2 months ago

P =3 then, 4P² + 4P = 4(3)² + 4(3) = 36 + 12 = 48 , divisible by 8

Miss. 1234 6 years, 2 months ago

P =2 then, 4P² + 4P = 4(2)² + 4(2) =16 + 8 = 24, it is also divisible by 8 .

Miss. 1234 6 years, 2 months ago

Now, when P = 1 then, 4P² + 4P = 4(1)² + 4(1) = 4 + 4 = 8 , it is divisible by 8.

Miss. 1234 6 years, 2 months ago

We know , odd number in the form of (2P +1) where P is a natural number , so, n² -1 = (2P + 1)² -1 = 4P² + 4P + 1 -1 = 4P² + 4P

Bhumika Agrawal 6 years, 2 months ago

If n is 4 n square + 1 here b is equals to 4the possible value of r is 0 ,1 ,2 ,3 but we take odd positive integer so we take 4q + 1 and 4q + 3 case first when n is equals to 4 Cube + 1 in this case we have any square - 14 Cube + 1 ka whole square minus 1 16 square + 8 + 1 - 1 16 square + 88 cube to cube + 1 and square minus 1 is divisible by 8 second case when was 24 Cube + 2 in this case we have
  • 5 answers

Aayush Kumar Chandrawanshi 6 years, 2 months ago

please complete the question

Bhumika Agrawal 6 years, 2 months ago

???

Miss. 1234 6 years, 2 months ago

Yeah..

Bhumika Agrawal 6 years, 2 months ago

This question is incomplete

Miss. 1234 6 years, 2 months ago

for finding LCM and HCF .....there must be 2 numbers.....P is the one no. ...then, where is the other no. given in this ques??...??
  • 1 answers

Amarjit Kaur 6 years, 2 months ago

Let 1st no. = x 2nd consecutive no. =x+1 X^2 + ( x+1)^2 =313 X^2 +x^2 +2x+1=313 2X^2+2x+1-313=0 2x^2 +2x -312 = 0 2(x^2 + x -156) =0 X^2 +x-156=0 Splitting middle term X^2 +13x -12x -156 =0 X(x+13)- 12(x+13)=0 (x+13)(x-12)=0 x+13=0 or x-12=0 X= -13 or x=12 X= -13(not possible as -13 is not nature number) So, x=12 and x+1 = 13 Hope this will help u?
  • 6 answers

Bhumika Agrawal 6 years, 2 months ago

On substitution Y is equals to 20 in equation second then X is equals to 50

Bhumika Agrawal 6 years, 2 months ago

On subtracting equation first and second (X-2Y)-(X-3Y)=10+10 Y=20

Bhumika Agrawal 6 years, 2 months ago

10 year later X + 10 is equals to twice of Y + 10 X-2Y=10 is a second equation

Bhumika Agrawal 6 years, 2 months ago

X minus y is equals to thrice of Y minus 5 X minus 3 Y is equals to minus 10 is first equation

Bhumika Agrawal 6 years, 2 months ago

Let the present age of Nuri be x and Sonu be y according to condition five year later

Aayush Kumar Chandrawanshi 6 years, 2 months ago

Five years ago hai ya five years age
  • 7 answers

Ajay ???? 6 years, 2 months ago

πr^

Piyush Dawar 6 years, 2 months ago

πr^2

Bhumika Agrawal 6 years, 2 months ago

πr2

Riya Kumari Shah 6 years, 2 months ago

πr²

Jai Sree 6 years, 2 months ago

πr2

Miss. 1234 6 years, 2 months ago

πr²

Shreya Sharma?? 6 years, 2 months ago

πr2
  • 5 answers

Ajay ???? 6 years, 2 months ago

c) remain unaltered

Bhumika Agrawal 6 years, 2 months ago

(c) remain unaltered

Miss. 1234 6 years, 2 months ago

yup!!

Akshay K 6 years, 2 months ago

Ya remain unaltered

Miss. 1234 6 years, 2 months ago

c) remain unaltered
  • 1 answers

Yogita Ingle 6 years, 2 months ago

3, 4, 6, 7, 8, 14

Mean is given by: Mean={tex}\frac{Sum of observations}{total number ofobservations}{/tex}

{tex}Mean=\frac{3+4+6+7+8+14}{6}=\frac{42}{6}=7{/tex}

Thus, {tex}{\overline{x}}=7.{/tex}

Now,{tex} {\Delta}x_{1}={\overline{x}-x_{1}}=7-3=4{/tex}

{tex}|{\Delta}x_{2}|=|{\overline{x}-x_{2}}|=|7-4|=3{/tex}

{tex}|{\Delta}x_{3}|=|{\overline{x}-x_{3}}|=|7-6|=1{/tex}

{tex}|{\Delta}x_{4}|=|{\overline{x}-x_{4}}|=|7-7|=0{/tex}

{tex}|{\Delta}x_{5}|=|{\overline{x}-x_{5}}|=|7-8|=1{/tex}

{tex}{\Delta}x_{6}|=|{\overline{x}-x_{6}}|=|7-14|=7{/tex}

Sum of deviations of the variate values={tex}|{\Delta}x_{1}|+|{\Delta}x_{2}|+|{\Delta}x_{3}|+|{\Delta}x_{4}|+|{\Delta}x_{5}|+|{\Delta}x_{6}|{/tex}

=4+3+1+0+1+7=16

Therefore, the sum of deviations of the variate values is 16.

 

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