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  • 1 answers

Khwahis Parveen 1 year, 4 months ago

S-t=3 …(i) S/3+t/2=6 …(ii) First solve equation (i) S-t=3 =S=3+t …(iii) Now substituting the value of S in equation (ii) 3+t/3+t/2=6 =6+2t+3t=36 =6+5t=36 =5t=36-6 =5t=30 =t=30/5 =t=6 Now, Equation (iii) S=3+t S=3+6 S=9 Answer:- The value of S=9 and the value of t=6
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Khwahis Parveen 1 year, 4 months ago

l=28 Sn =144 n=9 a=? By using the formula, Sn=n/2(a+l) =144=9/2(a+28) =144=9a+252/2 =144×2=9a+252 =288=9a+252 =288-252=9a =36=9a =a=36/9 =a=4

Harish Nandha 1 year, 4 months ago

Gi
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Ankit Kumar 1 year, 4 months ago

The sum of zeros= 0 Product of zeros= -1 Required quadratic polynomial= x²-(sum of zeros)x+product of zeros =X²-(0)x-1 =X²-1

Krish Gupta 1 year, 4 months ago

x²-0x+-1
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Aditya Mathur 1 year, 4 months ago

X^2 -55X +750 X^2 -30X -25X +750 X(X - 30)-25(X-30) (X-30) (X-25) X=30 X=25
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Amrit Kumar 1 year, 4 months ago

And. Y=my2+ny1/m+n=3*5+1*-3=15+(-3)=12/m+n 12/3+1=12/4=3

Amrit Kumar 1 year, 4 months ago

Or X=mx2+nx1/m+n=3*8+1*4=24+4=28/m+n=28/3+1=28/4=7

Amrit Kumar 1 year, 4 months ago

Let the point p 3:1 by the mid point formula m(x1+X2)/2and (y1+y2)/2 8+4/2=6and -3+5=2 and now 6/2=3
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Aryan Pawar 1 year, 4 months ago

2x+3y=42 -2x-35y=-32 0. -32y=10 y=10/32=5/16. -------1 Substituting y in 2x+3y=42 2x+3(5/16)=42 2x+15/16=42 (32x+15)/16=42 32x+15=672 32x=657 x=657/32
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Vandana Kumari 1 year, 4 months ago

Let 1st number be x And 2nd number be (34-x) A.T.Q., (x-3)(34-x+2) = 260 (x-3)(36-x) = 260 (36x-x²-108+3x) = 260 (-x²+39x-108) = 260 -x²+39x-368 = 0 x²-39x+368 = 0 x²-16x-23x+368 = 0 x(x-16)-23(x-16) = 0 (x-16)(x-23) = 0 (x-16) = 0 or (x-23) = 0 x = 16 or x = 23 Hence, the required numbers are 16 and 18.

Account Deleted 1 year, 4 months ago

If my answer is wrong you can do repeat with this method

Account Deleted 1 year, 4 months ago

Let no x and 34- x (X-3) (34-x+2) =260 (X-3)(36-x)=260 36x-x(square) -108+3x=260 39x-x(square)-108-260=0 {Sign changes all digit} X(square)-39x+368=0 x(square)-23x-16x+368=0 X(x-23)-16(x-23)=0 (X--23)(x-16). {factors/roots/solution} X=23,x=16 Numbers required 23 and 16
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Himanshu Dhakad 1 year, 4 months ago

Simple hai Kuch nhi krna bs simple identity use hogi (a²-b²)=(a+b)(a-b) ye wali... Saaf saaf dikh Raha hai ki 16 Likha hai mtlb 4 Ka square kyuki 4x4=16 HOTA or 9 Likha hai mtlb 3 Ka square bs khatam ...... (4x)² - (3)² = 0 ab ye identity BN gyi jisme a ki value hai 4x or b ki value hai 3 ab open krdo identity ko toh bn Jayega (4x+3)(4x-3)=0 Ab.....(4x+3)=0 ho Jayega or sath mein (4x-3)=0 bhi ho Jayega ab dono brackets ko solve krenge or X ki value nikalenge ....pehle bracket s value ayegi X=-3/4 or dusre s X=3/4
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Khwahis Parveen 1 year, 4 months ago

3)

Khwahis Parveen 1 year, 4 months ago

2) The zeros of the polynomial x²-2x-3 are a)-3,1 b)-3,-1 c)3,-1 d)3,1

Khwahis Parveen 1 year, 4 months ago

1)Which of the following is a polynomial? a)x²-5x+4√x+3 b)√x+1/√x c)9x²-4x+√2 d)√2x²-3√3x+√6

Aryan Jain 1 year, 4 months ago

Jai jinendra

Aryan Jain 1 year, 4 months ago

Hi chetna
  • 2 answers

Himanshu Dhakad 1 year, 4 months ago

an=a+(n-1)d 40=5+(n-1)d 35=(n-1)d.......1 Sn=n/2(2a+(n-1)d) 180=n/2(2*5+(n-1)d) 360=n(10+(n-1)d) Using 1 equation 360=n(10+35) 360=n(45) n=360/45 n=8 Answer

Mohd Israiel Anis 1 year, 4 months ago

Answer
  • 1 answers

Himanshu Dhakad 1 year, 4 months ago

Let the number of pizzas produced on that day be X So price of each pizza(as per question) will be= (2x + 4) Rs Since it is given that total cost of production on that day is Rs.448 (Price of each pizza)*(number of pizzas produced) = 448 (2x + 4)*X = 448 2x² + 4x = 448 X² + 2x = 224 X² + 2x - 224 = 0 Now factorisation as.. (Multiply krne pr 224 or minus krne pe plus Ka 2 Toh 16-14=2 and 16*14= 224) X² + 16x - 14x - 224 = 0 X(X+16)-14(X+16)=0 (X+16)(x-14)=0 So X= 14 and X=-16 Since number of pizzas produced on that day cannot be nigative therefore number of pizzas produced are 14
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Himanshu Dhakad 1 year, 4 months ago

Kyuki Kisi bhi cheez ki agr count krenge toh wo negative nhi ho skta kbi like if you are counting number of tables then it cannot be like minus 7 tables so n is always positive

Rajiv Sharma 1 year, 4 months ago

What is resistivity
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Himanshu Dhakad 1 year, 4 months ago

Simple hai 30th term ki value poochi hai or AP de Rakhi hai....given AP mein a=10 ho Gaya or d ki value minus 3 ....ab 30th term ko likh skte hai (a+29d) ab bs value put Karo "a" ki or d ki (10+29*(-3)) solve krenge or answer hoga minus 77 Hope it will help you;)

S P Jaishwal 1 year, 4 months ago

( c) -77
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  • 2 answers

Himanshu Dhakad 1 year, 4 months ago

Dekho first 100 even natural numbers Ka sum krna hai okk toh ek AP likh k dekhte hai .....natural numbers kya hote hai like general counting 1 2 3 4...ESE numbers but even likhne hai toh AP Kuch ESI banegi.>>>2,4,6,8,9,10...... Hope you know that even number wo hote hai Jo 2 se divide ho jate hai completely so ab Hume a AP mil gayi......nikalna hai 100 natural even numbers Ka sum Sum of n terms Ka formula HOTA hai Sn=n/2(2a+(n-1)d) Yaha n ki value 100 ho jayegi kyuki 100 even numbers Ka sum krna hai or AP Jo humne banai hai usse clearly "a" ki value 2 hai or d ki value bhi 2 bs values put krke solve kr denge ....S100=100/2(2*2+(100-1)2)..............S100=50(4+99*2)......S100=50(202)......S100=10,100 answer Hope it will help you;)

S P Jaishwal 1 year, 4 months ago

11100
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S P Jaishwal 1 year, 4 months ago

Sn = n(4n+1) Sn = 4n^2 +n Sn-1 = 4(n-1)^2 +(n-1) Sn-1 = 4(n^2+1-2n) +(n-1) Sn-1 = 4n^2+4-8n +n -1 Sn-1 = 4n^2-7n -3 Sn - Sn-1 = 4n^2+ n -(4n^2-7n-3) = 4n^2+n -4n^2+7n +3 =8n +3 =TN =8n +3 T1 = 8×1+3= 11 =a T2 =8×2 +3 = 19 d = T1-T2 =19 - 11= 8 =d AP = 11, 19, 27 ,.......

Roma Jebisow 1 year, 4 months ago

1.1
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