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  • 0 answers
  • 3 answers

Manisha Saini 6 years, 1 month ago

Thanks
You have always to convert the Tan and Cot in sin or cos
Hiii
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  • 1 answers

Pragati Jain 6 years, 1 month ago

Whose chapter
  • 2 answers

Aadya Singh 6 years, 1 month ago

LHS - Tan 45 × cos 60 = 1×1/2 = 1/2
RHS - sin 60 × cot 60 = √3/2 × 1/√3 = 1/2 ..
LHS = RHS...So, it's prove..

Akash Gautam 6 years, 1 month ago

Mai bataoun
  • 3 answers

Kashyap Anurag 6 years, 1 month ago

And l is the lower limit

Kashyap Anurag 6 years, 1 month ago

Biggest value is f1 and and its dowmward value is f2 and f1's upper value is f0

Jai Nanda 6 years, 1 month ago

F1
  • 2 answers

Rajat Bharti 6 years, 1 month ago

answer p=7 and k=7/4

Pragati Jain 6 years, 1 month ago

2*25-5p-15=0 50-15=5p 35/5=p P=7 Put eq^n 2 7x^2+7x+k=o D=o 49-28k=0 49/28=k 7/4=k
  • 6 answers

Vankit Vankit 6 years, 1 month ago

1/3πh(R2+r2+rR)

Aadya Singh 6 years, 1 month ago

CSA - πl( R+r)...

Aadya Singh 6 years, 1 month ago

*TSA ?‍♀

Aadya Singh 6 years, 1 month ago

CSA - πl(R + r) + π(R2 + r2 )

Aadya Singh 6 years, 1 month ago

Sorry...it's volume of frustum of cone..

Aadya Singh 6 years, 1 month ago

1/3πh ( R2 + r2 Rr)
  • 2 answers

Vankit Vankit 6 years, 1 month ago

What are you asking

Arsh Anuj 6 years, 1 month ago

What I have to do....?
  • 2 answers

??Geetha Sree ?? 6 years, 1 month ago

It depends on you. It isn't mandatory. But u can if u want.

Vankit Vankit 6 years, 1 month ago

No. It is not compulsory
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  • 2 answers

Ajay ???? 6 years, 1 month ago

This method is not in syllabus

Vanaja Rajaraman 6 years, 1 month ago

Ak007
  • 6 answers

Ansh Ika 6 years, 1 month ago

Ad ye achanak se change kse aaya

Singh Rahul 6 years, 1 month ago

5x^2 - 2ax + (a^2-b^2)=0

Dr.Ravi _♥️??? ....... 6 years, 1 month ago

What helps u need just ask whatever possible i will do.....but i think u urself more advanced knowledgeable

Ansh Ika 6 years, 1 month ago

U will help me? really why

Dr.Ravi _♥️??? ....... 6 years, 1 month ago

Kezia what helps or advice u need ask me ...

Ansh Ika 6 years, 1 month ago

Which question
  • 12 answers

Ansh Ika 6 years, 1 month ago

Meri baat buri lge to bura manna

♛ ❝Ѕυнαɴα❞ ♛ 6 years, 1 month ago

???

Ansh Ika 6 years, 1 month ago

Remember my name..the next cbse india topper... ANSHIKA

Ansh Ika 6 years, 1 month ago

Sorry mje kisi ki weakness ka majak nhi udana chahiye...well answer is 42..sry bro

Ansh Ika 6 years, 1 month ago

Itni kamjoor?

Ruby Sanger 6 years, 1 month ago

Mathss kamjorr haaa thodiii?

Ansh Ika 6 years, 1 month ago

What's ur class miss or mister?

Deepika .. 6 years, 1 month ago

Merko shayd aata h ... Answer theek h kya mera ??

Ruby Sanger 6 years, 1 month ago

Kisiii koo nhii ataa kyaaa?

Deepika .. 6 years, 1 month ago

Shayd yhi answer h...mere tajurbe k hisab se ???baki iske liye to meko bhot pdhaiii krni pdegi??

Deepika .. 6 years, 1 month ago

42

Diksha ? 6 years, 1 month ago

Ni ata?
  • 2 answers

Diksha ? 6 years, 1 month ago

Itna wierd kyu behave krte ho??

Diksha ? 6 years, 1 month ago

Hua kya?
  • 1 answers

Shruti Gupta 6 years, 1 month ago

On solving it through long divison method, you get -14 as remainder.
  • 1 answers

Aadya Singh 6 years, 1 month ago

Sin theta = 1/2
=> Sin theta = sin 30
=> theta = 30 ..
3 × cos 30 - 4× cos cube 30
=> 3× (√3/2) - 4(√3/2) 3
=> 3√3/2 - 4 × 3√3/8
=> 3√3/2 - 3√3/2 => 0
Now, RHS = LHS...So, it's prove..
  • 3 answers

Abhi Mittal 6 years, 1 month ago

127

Yogita Ingle 6 years, 1 month ago

Since,Remainders are 8 and 4

In the given question,

Greatest required number = H.C.F of (1659 - 8) and (2037 - 5)

                                           = H.C.F of 1651 and 2032

                                           = 127

Janvi Aggarwal 6 years, 1 month ago

Remainders are 8 and 4 1659-8=1651 2036-4=2032 HCF of 1651 and 2032 is 127 =>the greatest no. is 127

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