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Ask QuestionPosted by Muskan Singh ✍✍ 5 years, 7 months ago
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Lucifer?? Morningstar?? 5 years, 7 months ago
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Yogita Ingle 5 years, 7 months ago
3x+2y=0 ........... (i)
x-5y=17 ........... (ii)
Multiply equation (ii) by 3
3x - 15y = 51 ........... (iii)
Subtract (i) from (iii), we get
3x - 3x -15y -2y = 51
-17y = 51
y = -51/17
y = -3
Put y = -3 in (i) , we get
3x +2 (-3) =0
3x - 6 = 0
3x = 6
x = 2
Posted by Rajesh Ram 5 years, 7 months ago
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Yogita Ingle 5 years, 7 months ago
Here, divisor = 9828 and dividend = 14742.
Using Euclid’s Division Algorithm,
a=bq+r
Where the value of r lies between 0 and b.
Here, a = 14742, b = 9282
If r = 1, then
14742 = 9282 × 1 + 4914
If r = 0, then
14742 = 4914
Hence, the HCF of both 14742 and 9282 will be 4914
Posted by Pooja Sahu 5 years, 7 months ago
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Meghna Thapar 5 years, 7 months ago
An algorithm is a set of instructions designed to perform a specific task. This can be a simple process, such as multiplying two numbers, or a complex operation, such as playing a compressed video file. In computer programming, algorithms are often created as functions.
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Yogita Ingle 5 years, 7 months ago
((3•5x2) - x) - 28 = 0
Step 2 :
Trying to factor by splitting the middle term
Factoring 15x2-x-28
The first term is, 15x2 its coefficient is 15 .
The middle term is, -x its coefficient is -1 .
The last term, "the constant", is -28
Step-1 : Multiply the coefficient of the first term by the constant 15 • -28 = -420
Step-2 : Find two factors of -420 whose sum equals the coefficient of the middle term, which is -1 .
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -21 and 20
15x2 - 21x + 20x - 28
Step-4 : Add up the first 2 terms, pulling out like factors :
3x • (5x-7)
Add up the last 2 terms, pulling out common factors :
4 • (5x-7)
Step-5 : Add up the four terms of step 4 :
(3x+4) • (5x-7)
Which is the desired factorization
Equation at the end of step 2 :
(5x - 7) • (3x + 4) = 0
Posted by Lucifer?? Morningstar?? 5 years, 7 months ago
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Yogita Ingle 5 years, 7 months ago
Let 1 woman can finish the embroidery work in 'x' days and 1 man can finish it in 'y' days.
A woman's one day work = 1/x
and a man's one day work = 1/y
A.T.Q.
2/x + 5/y = 1/4 and
3/x + 6/y = 1/3
Let 1/x = a and 1/y = b
Now, 2a + 5b = 1/4 _(1)
and 3a + 6b = 1/3 _(2)
Multiplying _(1) by 3 and _(2) by 2 and subtracting
6a + 15b = 1/4
6a + 18b = 1/3
___________
0 + 3b = 1/4 - 1/3
=> 3b = 1/12
=> b = 1/(12×3)
=> b = 1/36
Putting b = 1/36 in _(1)
2a + 5(1/36) = 1/4
=> 72a + 5 = 36/4
=> 72a + 5 = 9
=> 72a = 9 - 5
=> 72a = 4
=> a = 4/72
=> a = 1/18
Now, a = 1/x = 1/18
=> x = 18
And, b = 1/y = 1/36
=> y = 36
So, 1 woman can finish the embroidery work in 18 days and 1 man can finish the work in 36 days.
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