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Ask QuestionPosted by Vaishali Kadam 5 years, 7 months ago
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Posted by Ravinder Yadav 5 years, 7 months ago
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Posted by Kritika Singh 5 years, 7 months ago
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Yogita Ingle 5 years, 7 months ago
Follow the steps to solve the system of linear equations by using the elimination method:
(i) Multiply the given equation by suitable constant so as to make the coefficients of the variable to be eliminated equal.
(ii) Add the new equations obtained if the terms having the same coefficient are opposite signs and subtract if they are of the same sign.
(iii) Solve the equation thus obtained.
(iv) Substitute the value found in any one the given equations.
(v) Solve it to get the value of the other variable.
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Posted by Prabhanjan Badkas 5 years, 7 months ago
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Arjun Kashyap 5 years, 7 months ago
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Arjun Kashyap 5 years, 7 months ago
Posted by Rajiv Kumar 5 years, 7 months ago
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Yogita Ingle 5 years, 7 months ago
6x²-7x-3
=6x²+2x-9x-3
=2x(3x+1)-3(3x+1)
=(2x-3)(3x+1)
⇒2x-3=0 or ⇒3x+1=0
⇒x=3/2 or ⇒ x= - 1/3
α=3/2 ,β= - 1/3
⇒α+β= -b/a
⇒3/2+(-1/3)= - (-3)/6
⇒3/2-1/3=1/2
⇒7/6 =1/2
⇒αβ=c/a
⇒ 3/2(-1/3)= -7/6
⇒-1/2= -7/6
⇒1/2=7/6
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Posted by Ajeetkumar Saw 5 years, 7 months ago
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Arjun Kashyap 5 years, 7 months ago
Posted by Sukh Kang 5 years, 7 months ago
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Yogita Ingle 5 years, 7 months ago
24,30,?,60,84
30 + 12 = 42
The sequence progresses +6, +12, +18, +24, +30.
Posted by Sukh Kang 5 years, 7 months ago
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Posted by Himanshu Rathore 5 years, 7 months ago
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Vivekanand Thallam 5 years, 7 months ago
Yogita Ingle 5 years, 7 months ago
Prime factorisation of 420 = 2 × 2 × 3 × 5 × 7
Prime factorisation of 130 = 2 × 5 × 13
HCF of 420 and 130 = 2 × 5 = 10
LCM × HCF = Product of the Numbers
10 × LCM = 420 × 130
LCM = 420 × 13 = 5460
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Yogita Ingle 5 years, 7 months ago
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are intezers.
so, √5 = p/q
p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an intezer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.
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Arvind Yadav 5 years, 7 months ago
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