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  • 3 answers

Aaryan Kumar 5 years, 7 months ago

Lo

Ankit Behera 5 years, 7 months ago

Yes

Mahi Singh 5 years, 7 months ago

ya by using constructor
  • 2 answers

yada****@***** 5 years, 7 months ago

5-*

Vishal Dhawan 5 years, 7 months ago

Let assume that a and b is co prime no. such that b=not 0 Root 5 = a/b b root 5 =a Both sides square (b root 5)² = (a) 5b² =a² Since, 5 is divisible by a² and also divisible by a According to theorem 1.3 Let b = c is any integer Substituting the value a =5c 5b² =(c)² 5b² =c² Since, 5is divisible by c² and also c But contradiction fact that root 5 is irrational So root 5 is irrational
  • 4 answers

Vidhi Garg 5 years, 7 months ago

75

Tanishka Baghel 5 years, 7 months ago

75

Vibhu Singh 5 years, 7 months ago

How easy is that yrr

Anushka ???? 5 years, 7 months ago

75
  • 1 answers

Navdeep Saini 5 years, 7 months ago

No because the prime factorisation of 6 contains 2 but not 5.
  • 0 answers
  • 3 answers

Vibhu Singh 5 years, 7 months ago

_295

Barsha Mohanty 5 years, 7 months ago

295

Sejpal Dipen 5 years, 7 months ago

295
  • 1 answers

Sumit Kumar 5 years, 7 months ago

Question to pusho
  • 2 answers

Anirudh S 5 years, 7 months ago

Second number is 48 As we know that LCM×HCF=Product of two Numbers Therefore 240×12=60×a =(240×12)/60 =48

Khushdeep Kaur Lehal 5 years, 7 months ago

LCM×HCF = product of two numbers 240×12= 60× second number 240×12÷60=second number 48 = second number Your answer
  • 0 answers
  • 1 answers

Tripurari Kumar 5 years, 7 months ago

a.b=c/a=-4/2=-2
  • 5 answers

Ankit Behera 5 years, 7 months ago

Mtg, paractise all question from it To get 99%

Satish Naikar 5 years, 7 months ago

Science togeter with

Anirudh S 5 years, 7 months ago

NCERT is best practice it thorolly.

Sumit Kumar 5 years, 7 months ago

For maths only RD Sharma

S?R Ali 5 years, 7 months ago

Ncert and rd
  • 1 answers

Sia ? 4 years, 6 months ago

Please ask question with complete information.

  • 1 answers

Stranger?♋ Things 5 years, 7 months ago

Euclid
  • 2 answers

Lakshita Garg Garg 5 years, 7 months ago

The Euclid's alogorithm is a=bq+r

Navdeep Saini 5 years, 7 months ago

a=bq+r
  • 2 answers

Sujal Jhawar 5 years, 7 months ago

ATQ euclids algorithm dividend =divisor ×qoutient +remainder

Navdeep Saini 5 years, 7 months ago

The set of the statements a=bq+r
  • 2 answers

Aashish Kumar 5 years, 7 months ago

Aryabhatta

S?R Ali 5 years, 7 months ago

Euclid
  • 0 answers
  • 1 answers

Yogita Ingle 5 years, 7 months ago

Consider we have two numbers 78 and 980 and we need to find the HCF of both of these numbers. To do this, we choose the largest integer first, i.e. 980 and then according to Euclid Division Lemma, a = bq + r where 0 ≤ rb;

980 = 78 × 12 + 44

Now, here a = 980, b = 78, q = 12 and r = 44.

Now consider the divisor as 78 and the remainder 44 and apply the Euclid division method again, we get

78 = 44 × 1 + 34

Similarly, consider the divisor as 44 and the remainder 34 and apply the Euclid division method again, we get

44 = 34 × 1 + 10

Following the same procedure again,

34 = 10 × 3 + 4

10=4×2+2

4=2×2+0

As we see that the remainder has become zero, therefore, proceeding further is not possible and hence the HCF is the divisor b left in the last step which in this case is 2. We can say that the HCF of 980 and 78 is 2.

  • 1 answers

Prachi Meena 5 years, 7 months ago

Given positive integers a and b,there exist unique integers q and r satifying a=bq+r, 0_< r<b.
  • 2 answers

Navdeep Saini 5 years, 7 months ago

225=135×1+90 135=90×1+45 90=45×2+0 This implies that HCF is 45

Saisibani Behera 5 years, 7 months ago

Since 225>135 , We divided 225 by135 225÷135=90 .Since remainder is not 0 ,We divided 135 by 90 135÷90=45 .Since remainder is not 0,We divided 90 by 45 90÷45=0, Since the remainder is 0 .So as using the euclids division algorithim the H.C.F is 45
  • 2 answers

Yogita Ingle 5 years, 7 months ago

Zeros of a polynomial can be defined as the points where the polynomial becomes zero on the whole. A polynomial having value zero (0) is called zero polynomial. 

In general, If k is zero of the linear polynomial in one variable; P(x) = ax +b, then

P(k) = ak+b = 0

k = -b/a

Shambhu Bhiwania 5 years, 7 months ago

The value which at which the equation becomes zero
  • 1 answers

Yogita Ingle 5 years, 7 months ago

For the solution of this question we have to find L.C.M of 36 and 54.
L.C.M. of 36 and 54 = 2×2×3×3×3 = 108
Now,
The least number = (L.C.M. of 36 and 54) + 5
⇒ 108+5 = 113
Hence 113 is the least positive integer which on diminished by 5 is exactly divisible by 36 and 54.

  • 2 answers

Yogita Ingle 5 years, 7 months ago

Let us assume √2 is rational number.
a rational number can be written into he form of p/q
√2=p/q
p=√2q
Squaring on both sides
p²=2q²__________(1)
.·.2 divides p² then 2 also divides p
.·.p is an even number
Let p=2a (definition of even number,'a' is positive integer)
Put p=2a in eq (1)
p²=2q²
(2a)²=2q²
4a²=2q²
q²=2a²
.·.2 divides q² then 2 also divides q
Both p and q have 2 as common factor.
But this contradicts the fact that p and q are co primes or integers.
Our supposition is false
.·.√2 is an irrational number.

?Royal Thakur? 5 years, 7 months ago

Ncert example...

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