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  • 2 answers

Sumit Kumar 1 year, 2 months ago

Udertroot b²-a² by b

Loveneet Sharma 1 year, 2 months ago

Solve
  • 1 answers

Rayyan Ali 1 year, 2 months ago

NEVER EXCEEDS 1
  • 2 answers

Akshra Garg 1 year, 2 months ago

It is not in the syllabus for session 2023-24

Raman Rana 1 year, 2 months ago

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  • 1 answers

Nitika Arya 1 year, 2 months ago

  Use app Login Class 10 >>Maths >>Real Numbers >>Revisiting Irrational Numbers >>Prove that 3 + 2√(5) is irrational. Question  Prove that 3+25​ is irrational. Medium Open in App Updated on : 2022-09-05 Solution  Verified by Toppr Prove 3+25​ is irrational. → let take that 3+25​is rational number → so, we can write this answer as ⇒3+25​=ba​  Here a & b use two coprime number and b=0. ⇒25​=ba​−3 ⇒25​=ba−3b​ ∴5​=2ba−3b​ Here a and b are integer so 2ba−3b​ is a rational number so 5​ should be rational number but 5​ is a irrational number so it is contradict - Hence 3+25​ is irrational.
  • 1 answers

Akshra Garg 1 year, 2 months ago

Please tell us the full question
  • 2 answers

Tirthankar Pan 1 year, 2 months ago

Intersecting lines

Aditya Kumar 1 year, 2 months ago

Intersecting lines
  • 1 answers

Akshra Garg 1 year, 2 months ago

a+2d+a+d=30 2a+3d=30 a+6d=a+3d+14 3d=14 d=14/3 2a+14=30 2a=16 a=8 Now you can form your ap
  • 2 answers

Akshra Garg 1 year, 2 months ago

x²-(sum of zeroes)x+product of zeroes x²-√5+10 is your quadratic polynomial

Aman Jaiswal 1 year, 2 months ago

x²—√5x + 10
  • 0 answers
  • 5 answers

Anuj Jangid 1 year, 1 month ago

X+Y=10 => X=10-Y ------(1) X-Y=4-------(2) From equation 1st and 2nd, 10-Y-Y=4 => -2Y=4-10 => -2Y=-6 => Y=6/2 => Y=3 Put Y=3 in equation 1st :- => X=10-3 => X=7 That's your answer.

Aditya Kumar 1 year, 2 months ago

X = 7, y=3

Vaibhav Kumar Jha 1 year, 1 month ago

Elementary method

Rk Yadav 1 year, 2 months ago

X=7,Y=3

Pandit . 1 year, 2 months ago

X+y=10 X-y=4 X=6 X+y=10 6+y=10 Y=10-6 Y=4
  • 1 answers

Akshra Garg 1 year, 2 months ago

Let 3rd vertex is x,y So,√(x²+y²)=√(x-3)²+(y-√3)² You will get your 3rd vertex
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  • 1 answers

Zaima Anjum 1 year, 2 months ago

GIVEN a3=5 => a+2d=5____[1] a7=9 =>a+6d=9_____[2] subtract eqn[2] from eqn[1] -4d=-4 d=4/4 d=1 put d=1 in eqn[1] a+2[1]=5 a=5-2 a=3 now AP is 3,4,5........
  • 2 answers
2sin²A-cosA=2 2(1-cos²A) -cos=2 2-2cos²A-cosA=2 -cosA(Cos-1) =0 -cosA=0 -cosA=cos90 A=90°

Suryansh Sirohi 1 year, 2 months ago

Something is incorrect in your question.
  • 2 answers

Lallu Tomar 1 year, 2 months ago

Qusan 1

Ashish Mandal 1 year, 2 months ago

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  • 3 answers

Lallu Tomar 1 year, 2 months ago

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Astha Gautam 1 year, 2 months ago

X ki value - 7 by the distance formula

Samrat Rajput 1 year, 2 months ago

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  • 1 answers

Nishant Sahu 1 year, 2 months ago

As we know that , Perimeter of Tri. ABC/ Perimeter of Tri. DEF =corresponding side AB / corresponding side DE Therefore the perimeter of two similar sides of triangle is same as the ratio of similar sides.
  • 1 answers

Sahana Parashetti 1 year, 2 months ago

Apply section formula let s (x,y) in parallelogram draw PS diagonal give intersect point as o let m1 is m2 is 1
  • 1 answers

Mayank Sharma 1 year, 1 month ago

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  • 3 answers

M Charith 1 year, 1 month ago

20

Saksham Acharya 1 year, 2 months ago

Let nth term of the give AP be 81 a + (n-1) d = 81 5 + (n-1) 4 = 81 (n-1) 4 =81-5 (n-1) =76/4 n-1 =19 n =19+1 n =20 Therefore 20th term of the given AP is 81

Ayesha Killedar 1 year, 2 months ago

4

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