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  • 1 answers

Yogita Ingle 5 years, 6 months ago

Monthly salary = Rs. 7000
Then money earned in the 1st year = 7000*12 = Rs. 84000
Annual increment = Rs. 500
Money earned in the 2nd year with increment =7500*12 = Rs. 90000
Now for 3rd year = 8000*12 = Rs.96000
So, here
a = Rs. 84000
d = Rs. 6000
n = 10 years
Sn = n/2{2a + (n - 1)d}
S₁₀ = 10/2{2*84000 + (10 - 1)6000}
= 5{168000 + 54000}
= 5*222000
= Rs.1110000

 

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Stranger?♋ Things 5 years, 6 months ago

When two equations have the same slope but different y-axis, they are parallel. Since the two equations never intersect, the system has no solutions.
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Moksh Prajapati 5 years, 1 month ago

Thanks

Rajesh Sharma 5 years, 6 months ago

3BaCl2 +Al2(SO4)3= 3BASO4+2AlCl3

Sandli __Thakur_✍?✍? 5 years, 6 months ago

3BaCl2+Al2(SO4)3=3BaSO4+2AlCl3
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Rajesh Sharma 5 years, 6 months ago

Irrational

Sandli __Thakur_✍?✍? 5 years, 6 months ago

It is irrational if it is going on...and on....

Sandli __Thakur_✍?✍? 5 years, 6 months ago

Irrational number.........
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Vidisha Modi 5 years, 6 months ago

I want my answer just now only
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Karunesh Kumar Mishra 5 years, 6 months ago

Let we assume that 2-√3 is R.N Therefore, it can be written as 2-√3=p/q => 2-√3= p/q => p - 2q/q = √3 since, p and q are integer Therefore, p/q is R.N Therefore, p - 2q/q is also a R.N Therefore, √3 is also a R.N But we know that √3 is irrational number Here is a contradiction So, we finally say that 2 - √3 is irrational number
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꧁༒ Shaurya༻ 5 years, 6 months ago

What I'm don't understand
  • 3 answers

Sowndaryaa Lakshmi V 5 years, 6 months ago

Hi

꧁༒ Shaurya༻ 5 years, 6 months ago

Which chapter please tell

Anushka ???? 5 years, 6 months ago

Of which subject
  • 1 answers

Sowndaryaa Lakshmi V 5 years, 6 months ago

Hi rithu baath tho karlo yaar mujse. Baath hi nHi karte ho aap mujse
  • 1 answers

Shravani ? 5 years, 6 months ago

You should first have to assume that √5 is rational √5=p/q that is p=√5q Squaring on both side p2=5q2 P2/5=q2 :.P2is divisible by 5 :.p is also divisible by 5 P=5 are for some integer=r Squaring on both side p2= 25r2 Then it became 25r2=5q2 r2=5q/25 r2=q2/5 Again q2 is divisible by 5 And q is also divisible by 5 Then we have to write reason that 5 is coom factor and p&q are co-prime. This codradiction has arise because of our incorrect assumption so we consider that root 5 is irrational number .
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Jhalak Biswas 5 years, 6 months ago

Let "a" and "b" any two positive integers. Then their exist unique integers "q" and "r" such that a=bq+r , 0 ,is smaller than the value = "r'',which is smaller than the value of "b"
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Rajesh Sharma 5 years, 6 months ago

52.083333333.....

Jagdish Prasad ???? 5 years, 6 months ago

52.08333333.....
  • 3 answers

Pk . 5 years, 6 months ago

??

Pk . 5 years, 6 months ago

{✓(q^2-p^2)}/q

Bishwadip Raj 5 years, 6 months ago

Good question.
  • 1 answers

Pk . 5 years, 6 months ago

Yeah

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