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Yogita Ingle 5 years, 6 months ago
Monthly salary = Rs. 7000
Then money earned in the 1st year = 7000*12 = Rs. 84000
Annual increment = Rs. 500
Money earned in the 2nd year with increment =7500*12 = Rs. 90000
Now for 3rd year = 8000*12 = Rs.96000
So, here
a = Rs. 84000
d = Rs. 6000
n = 10 years
Sn = n/2{2a + (n - 1)d}
S₁₀ = 10/2{2*84000 + (10 - 1)6000}
= 5{168000 + 54000}
= 5*222000
= Rs.1110000
0Thank You