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Yogita Ingle 5 years, 6 months ago
Given equations are
2x+y-5=0
3x+2y-8=0
By cross multiplication rule,
{tex}\displaystyle\frac{x}{-8+10}=\frac{y}{-15+16}=\frac{1}{4-3}{/tex}
{tex}\displaystyle\implies\frac{x}{2}=\frac{y}{1}=\frac{1}{1}{/tex}
{tex}\implies\;x=2\;\text{and}\;y=1{/tex}
{tex}\therefore\textbf{The solution is x=2 and y=1 }{/tex}
Posted by Kannu Bhardwaj 5 years, 6 months ago
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Helper . 5 years, 6 months ago
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Yogita Ingle 5 years, 6 months ago
Given: x2 + 32x – 273 = 0
We can rewrite the given equation as
⇒ x2 + 39x - 7x – 273 = 0
⇒ x( x + 39) 7 7(x +39) = 0
⇒ ( x +39)(x - 7) = 0
∴ Factors of the given quadratic equation are ( x + 39) and (x - 7)
Posted by Piyush Javia 5 years, 6 months ago
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Yogita Ingle 5 years, 6 months ago
X + y = 5 ( equation 1 )
2x - 3y = 4 ( equation 2 )
Now,
multiplying (eq.1) by 2 and subtracting (eq.2) from ( eq.1 )
(2x + 2y = 10) - (2x - 3y = 4 )
=> 2x + 2y - 2x + 3y = 6
=> 5y = 6
=> y = 6/5
Putting the value of y in ( eq.1 )
=> x+ y = 5
=> x + 6/5 = 5
=> x = 5 - 6/5
=> x = 19/5
Posted by Piyush Javia 5 years, 6 months ago
- 1 answers
Yogita Ingle 5 years, 6 months ago
X + y = 5 ( equation 1 )
2x - 3y = 4 ( equation 2 )
Now,
multiplying (eq.1) by 2 and subtracting (eq.2) from ( eq.1 )
(2x + 2y = 10) - (2x - 3y = 4 )
=> 2x + 2y - 2x + 3y = 6
=> 5y = 6
=> y = 6/5
Putting the value of y in ( eq.1 )
=> x+ y = 5
=> x + 6/5 = 5
=> x = 5 - 6/5
=> x = 19/5
Posted by Sidrah Sanaullah 5 years, 6 months ago
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Yogita Ingle 5 years, 6 months ago
Net sown area is the area sown with crops but it is counted once.
GCA and NSA helps in calculating cropping intensity..
Posted by Gulfam Hasan 5 years, 6 months ago
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Yogita Ingle 5 years, 6 months ago
formula is a=bq+r
a=38220,b=195
38220=196*195+0
Therefore remainder =0
Hence,
Hcf of 196 and 38220 is 195
Posted by Maskoor Alam Alam 5 years, 6 months ago
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Sandli Thakur✍?✍?(Helping Hand)? 5 years, 6 months ago
Posted by Aman Singh 5 years, 6 months ago
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Maskoor Alam Alam 5 years, 6 months ago
Posted by Aman Singh 5 years, 6 months ago
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Sunita Garg 5 years, 6 months ago
Given
2x2+5x+3 =2x2+2x+3x+3
=2x(x+1) +3(x+1)
=(x+1) (2x+3)
Thus
2x2+5x+3= (x+1) (2x+3)
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Kyōka ( Demon Snow ) 5 years, 6 months ago
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