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Rajan Kumar Pasi 5 years, 6 months ago
Q. {tex}\huge {\frac{\cot\ 54^\circ}{\tan\ 36^\circ}+\frac{\tan\ 20^\circ}{\cot\ 70^\circ} -2=?}\\{/tex}
Sol:
| {tex}\huge {=> \ \frac{\cot\ 54^\circ}{\tan\ 36^\circ}+\frac{\tan\ 20^\circ}{\cot\ 70^\circ} -2}\\.\\ \huge {=> \ \frac{\tan\ 36^\circ}{\tan\ 36^\circ}+\frac{\tan\ 20^\circ}{\tan\ 20^\circ} -2}\\.\\ \huge {=> \ 1+1 -2}\\.\\ \huge {=> 0}\\.\\{/tex} | {tex}\Large {\Bigg( {\because\ \cot \ \theta=\tan\ (90^\circ-\theta)\\ \therefore \cot\ 54^\circ=\tan\ (90^\circ-54^\circ)=\tan\ 36^\circ\\ and,\ \cot\ 70^\circ=\tan\ (90^\circ-70^\circ)=\tan\ 20^\circ\Bigg)\\}}{/tex} |
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Gaurav Seth 5 years, 6 months ago
It tells us about the divisibility of integers. It states that any positive integer ‘a’ can be divided by any other positive integer ‘ b’ in such a way that it leaves a remainder ‘r’.
Euclid's division Lemma states that for any two positive integers ‘a’ and ‘b’ there exist two unique whole numbers ‘q’ and ‘r’ such that , a = bq + r, where 0≤r<b.
Here, a= Dividend, b= Divisor, q= quotient and r = Remainder.
Hence, the values 'r’ can take 0≤r<b.
Posted by Arya Jadav 5 years, 6 months ago
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Gaurav Seth 5 years, 6 months ago
3-2√6x+2=0
3-√6x-√6x+2=0
√3*√3
-√3x*√2x-√3x*√2x+√2*√2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
x=√2/√3
Therefore the equation has two equal roots; √2/√3
Posted by Azim Anshari 5 years, 6 months ago
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Gaurav Seth 5 years, 6 months ago
Equation of line: y =mx+c
m is the slope
Given :
Convert it into the general form given above
Compare it with general form
So, m =
Thus the slope of the given equation is
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Divya Banjara 5 years, 6 months ago
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