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  • 2 answers

Arun Patel 5 years, 5 months ago

number having countable number after decimal are terminating eg, 1.2, 1.323332, 2.675 ect and numbers having uncountable number after decimal are non terminating eg 12.2327648...., 2.984875....., 3.666666.....
non-terminating, non-repeating decimal is a decimal number that continues endlessly, with no group of digits repeating endlessly. Decimals of this type cannot be represented as fractions, and as a result are irrational numbers. ... Non-terminating, non-repeating decimals can be easily created by using a pattern.
  • 1 answers

Soumyajit Kundu 5 years, 5 months ago

0
  • 5 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

Yes

Anushka ?? 5 years, 5 months ago

Ek baar read jaroor kar lena

Study Lover ?‍? ?‍? 5 years, 5 months ago

No,the question will not be ask from plus(+) boxes.It is clearly written in pg no (7).

Anushka ?? 5 years, 5 months ago

Sanket are u here

Anushka ?? 5 years, 5 months ago

Kahi se bhi aa sakte h
  • 5 answers

Ash Greninja 5 years, 5 months ago

No solutions

? Pranali.A.P ? 5 years, 5 months ago

Ok ,no problem

Anushka ?? 5 years, 5 months ago

U are right meri maths thodi weak h mujhe samajh nahi aata

? Pranali.A.P ? 5 years, 5 months ago

No solution

Anushka ?? 5 years, 5 months ago

I think infinite many
  • 1 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

Available in this app
  • 4 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

Let faster pipe takes x min to fill the cistern. To fill the cistern slower pipe take (x+3) min. In one minute the faster pipe filled the cistern= 1/x In  3 1/13= 40/13 min the faster pipe filled the cistern= 40/13 × (1/x) = 40/13x In  3 1/13= 40/13 min the slower pipe filled the cistern= 40/13 × (1/x+3) = 40/13(x+3). ATQ 40/13x +  40/13(x+3) = 1 40/13 [ 1/x + 1/(x+3)] = 1 40 [ (x +3+x) / x(x+3)] =13 40(2x +3)  =13 x(x+3)] 80x + 120 = 13x² +39x 13x² +39x -80x -120= 0 13x² - 41x -120= 0 13x² - 65x +24x -120= 0 13x(x -5) + 24(x -5)= 0 (13x +24)(x -5)= 0 (13x +24)= 0  or  (x -5)= 0 x =- 24/13  or x = 5 Time cannot be in negative.so, 5 min

? Pranali.A.P ? 5 years, 5 months ago

3 , 1/13 hai

? Pranali.A.P ? 5 years, 5 months ago

Vo 3 1 upon 2 hai

Lucifer?? Morningstar?? 5 years, 5 months ago

Together in ke baad samjh nhi arha
  • 4 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

K=16

? Pranali.A.P ? 5 years, 5 months ago

Vo X hai

? Pranali.A.P ? 5 years, 5 months ago

Sorry its my mistake

Anushka ?? 5 years, 5 months ago

1 x 2 h kya ya fir 1into 2 h
  • 5 answers

Anushka ?? 5 years, 5 months ago

Thik h gussa kyu ho aata h mujhe

Lucifer?? Morningstar?? 5 years, 5 months ago

Khud se nikalo itna v nhi kr skti

Anushka ?? 5 years, 5 months ago

And x kya mila

Anushka ?? 5 years, 5 months ago

Thanks and hiiiii

Lucifer?? Morningstar?? 5 years, 5 months ago

Multiply eq (1) by 3 and eq (2) by 2...... 6x+18y=36...(3). 6x-30y=60...(4) subtract eq (3) from eq(4) .... -48y=24 => y=-1/2
  • 1 answers

Gaurav Seth 5 years, 5 months ago

Given The first term of two aps are equal and the ratios of their common difference is 1:2.if the 7th term of first ap and 21th term of second ap are 23 and 125 respectively. find two aps.

According to question we have

So a7 = 23

Now a + 6d = 23

Or a = 23 – 6d------------------1

Also a21 = 125

Now a + 20b = 125------------2

Or 23 – 6d + 20 b = 125 (from 1)

20 b – 6d = 102

10 b – 3d = 51  

Now according to question d/b = 1/2  

Now d = 1x and b = 2x (for some positive value x)

Now 10 b – 3d = 51

       10(2x) – 3 (x) = 51

        17 x = 51

     Or x = 3

Therefore d = 3, b = 6

Put d = 3 in equation 1 we get

So a + 6(3) = 23

Or a = 23 – 18

Or a = 5

Therefore first A.P is 5,8,11-------and  

Second A.P is 5,11,17-------

  • 2 answers
=k(x²+(alpha+beta)x+alpha beta)

Lucifer?? Morningstar?? 5 years, 5 months ago

D=b²-4ac and x=-b±√D/2a
  • 1 answers

Namrata Jindal 5 years, 5 months ago

4 places of decimal. Because 1250 = 2*5^4 So degree of 5 is greater i.e. 4
  • 1 answers

Arun Patel 5 years, 5 months ago

R1 = 1/16, R2 = 1/10 and R3 = 1/20 so when tey work together R = R1 +R2 + R3 R = 1/16 + 1/10 + 1/20 =( 20 + 32 + 16)/320 = 68/320 so the time taken to finesh the work is 320/68 = 4. 705 minutes approx here you are using rate of work topic
  • 2 answers

Arun Patel 5 years, 5 months ago

sum of AP = n{ 2a + (n-1)d}/2 = 10{2a + (10 - 1)100}/2 so 16500 = 5 {2a + 900} 3300 = 2a + 900 3300 -900 =2a 2400 =2a 2400/2 =a a = 1200 so he saved Rs 1200 in the first year 1650 - 900 = 2a 7

? Pranali.A.P ? 5 years, 5 months ago

Second installment= a + 100 Third installment = a+100+100 The sum of his saving every years Sn=n/2[2a+(n-1)d] a=first term for the given A.P d=common difference of the given A.P n= number of terms n=10 S10 =10/2[2(a)+(9)(100)] 16500=5[2a+(9)(100)] 16500 =10a=4500 16500-4500=10a 12000=10a a=12000/10 Solving for a 10a=12000 a=12000/10 a=1200
  • 5 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

Give my answer

Lucifer?? Morningstar?? 5 years, 5 months ago

a1000–A1000 = a+999d–A-999d = a-A=100 using eq(1)

? Pranali.A.P ? 5 years, 5 months ago

Two APs have the same common difference. The difference between their 100th terms is 100, what is the difference between their 1000th terms? BE/BTech at Thapar Institute of Engineering & Technology. 100 Solution Let the difference be d And the first term of AP1 be a1 And AP 2 be a2 100th term of AP1 is a1+99d……(.1) 100th term of AP2 is a2+99d……(2) As per ques eq1 - eq2=100 i.e a1-a2=100 Now 1000th term of AP1 is a1+999d……(.3) 1000th term of AP2 is a2+999d……(4) Eq3-eq4=100 i.e a1-a2=100 So answer remains constant=100

? Pranali.A.P ? 5 years, 5 months ago

Answer is 100

Lucifer?? Morningstar?? 5 years, 5 months ago

Let the first term be a and A of two APs respectively. a100–A100=100=> a+99d–A–99d=100 => a–A=100...(1)
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

Here, a = 20, d = 15 (As payment increases by Rs. 15) and S(n) = 3 We know that, S(n) = n/2[2a + (n - 1)d] Putting all the values, we get ⇒ 3250 = n/2[2 × 20 + (n - 1) (15)] ⇒ 3250 × 2 = n[40 + 15n - 15] ⇒ 6500 = n[25 + 15n] ⇒ 1300 = n[5 + 3n] ⇒ 3n² + 5n - 1300 = 0 ⇒ 3n² + 65n - 60n - 1300 = 0 ⇒ n(3n + 65) - 20(3n + 65) = 0 ⇒ (n - 20) (3n + 65) = 0 ⇒ n = 20, - 65/3 (As n can't be negative) ⇒ n = 20 Hence, men will take 20 months to clear the loans. Read more on Brainly.in - https://brainly.in/question/1598066#readmore
  • 1 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

16+8=7p³ => p=³√24/³√7
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

To calculate probability, you will need to divide the number of events, or what you want to calculate, by the number of possible outcomes, or how many total options there are.
  • 0 answers
  • 0 answers
  • 1 answers

Yogesh Lakhwani 5 years, 5 months ago

Just divide the number 2105 by 33. 

The remainder left after division is the answer. 

  • 0 answers
  • 1 answers

Gaurav Seth 5 years, 5 months ago

actorize the equation  

Compare the equation with ax²  + bx  + c  = 0
We get
a = 1 ,b=-2 c= -8
To factorize the value we have to find two value which
sum is equal to b                      =-2
and product is  a x c  = 1 x -8    = -8

 

2 and -4 are such number which

sum is 2-4        = - 2
product is 2*-4 = - 8

So we can write middle term -2 x  = 2 x – 4 x 
We get
x²+2x-4x-8=0
x (x + 2)-4(x + 2) = 0
(x+2) (x-4)          = 0
First zero
x + 2                  = 0
x                        = -2
Second zero
x-4                   = 0
x                      = 4
sum of zero                -2 + 4    = 2
product of zero           2 x -4     = -8

For a equation ax² + bx  + c  = 0 , if  zeroare α and β ,

Plug the values of a , b and c we get
Sum  of zeros              -b/a     = -(-2/1)           = 2
Product of zeros          c/a      =-8/1               = -8

  • 2 answers

Shubhang Shrivastav 5 years, 5 months ago

Every root number is irrrational.

Meghna Thapar 5 years, 5 months ago

The square root of 2 is "irrational" (cannot be written as a fraction) ... because if it could be written as a fraction then we would have the absurd case that the fraction would have even numbers at both top and bottom and so could always be simplified.

  • 1 answers

Yogyta Sharma 5 years, 5 months ago

Because we can't write it on the form of a/b and they are non terminating
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

(0,0) is the required point lies on the perpendicular bisector of the lines segment
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

Dependent linear equation A1/A2=B1/B2=C1/C2 ,Double the equation ,x-5y=6 2x-10y=12

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