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Gaurav Seth 5 years, 5 months ago
Given The first term of two aps are equal and the ratios of their common difference is 1:2.if the 7th term of first ap and 21th term of second ap are 23 and 125 respectively. find two aps.
According to question we have
So a7 = 23
Now a + 6d = 23
Or a = 23 – 6d------------------1
Also a21 = 125
Now a + 20b = 125------------2
Or 23 – 6d + 20 b = 125 (from 1)
20 b – 6d = 102
10 b – 3d = 51
Now according to question d/b = 1/2
Now d = 1x and b = 2x (for some positive value x)
Now 10 b – 3d = 51
10(2x) – 3 (x) = 51
17 x = 51
Or x = 3
Therefore d = 3, b = 6
Put d = 3 in equation 1 we get
So a + 6(3) = 23
Or a = 23 – 18
Or a = 5
Therefore first A.P is 5,8,11-------and
Second A.P is 5,11,17-------
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Yogesh Lakhwani 5 years, 5 months ago
Just divide the number 2105 by 33.
The remainder left after division is the answer.
Posted by Sathiya Sathiya 5 years, 5 months ago
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Gaurav Seth 5 years, 5 months ago
actorize the equation

Compare the equation with ax² + bx + c = 0
We get
a = 1 ,b=-2 c= -8
To factorize the value we have to find two value which
sum is equal to b =-2
and product is a x c = 1 x -8 = -8
2 and -4 are such number which
sum is 2-4 = - 2
product is 2*-4 = - 8
So we can write middle term -2 x = 2 x – 4 x
We get
x²+2x-4x-8=0
x (x + 2)-4(x + 2) = 0
(x+2) (x-4) = 0
First zero
x + 2 = 0
x = -2
Second zero
x-4 = 0
x = 4
sum of zero -2 + 4 = 2
product of zero 2 x -4 = -8
For a equation ax² + bx + c = 0 , if zeroare α and β ,
Plug the values of a , b and c we get
Sum of zeros -b/a = -(-2/1) = 2
Product of zeros c/a =-8/1 = -8
Posted by Naveen Mk 5 years, 5 months ago
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Meghna Thapar 5 years, 5 months ago
The square root of 2 is "irrational" (cannot be written as a fraction) ... because if it could be written as a fraction then we would have the absurd case that the fraction would have even numbers at both top and bottom and so could always be simplified.
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Arun Patel 5 years, 5 months ago
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