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Ask QuestionPosted by Neeraj Rajput 5 years, 4 months ago
- 1 answers
Posted by Soumya Kumari 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
An= a + (n-1)d
where, a= 41 and d = a2 -a1=38-41=-3
now, 8 = 41 + (n-1)-3
8-41=-3n+3
-33 = -3n+3
-33-3 =-3n
-36=-3n
n =12
Answer: 12 terms.
Yogita Ingle 5 years, 4 months ago
An= a + (n-1)d
where, a= 41 and d = a2 -a1=38-41=-3
now, 8 = 41 + (n-1)-3
8-41=-3n+3
-33 = -3n+3
-33-3 =-3n
-36=-3n
n =12
therefore there are 12 terms.
Posted by Amal Manoj 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
Let us assume that √2+√5 is a rational number.
A rational number can be written in the form of p/q where p,q are integers and q≠0
√2+√5 = p/q
On squaring both sides we get,
(√2+√5)² = (p/q)²
√2²+√5²+2(√5)(√2) = p²/q²
2+5+2√10 = p²/q²
7+2√10 = p²/q²
2√10 = p²/q² – 7
√10 = (p²-7q²)/2q
p,q are integers then (p²-7q²)/2q is a rational number.
Then √10 is also a rational number.
But this contradicts the fact that √10 is an irrational number.
Our assumption is incorrect
√2+√5 is an irrational number.
Hence proved.
Posted by Prabina Rani Sethy 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
The polynomial is,
Step-by-step explanation:
If and
are the roots of a quadratic equation,
Then the quadratic equation is,
Here, the given quadratic equation is,
Which having the zeroes, and
.
For finding the zeroes,
Thus, the zeroes of the given quadratic equation are 2 and 3,
(2)4 - (3)4
16 - 81
= -65
Posted by Tamanna Bhabhor 5 years, 4 months ago
- 2 answers
Posted by Bhupinder Singh Brar 5 years, 4 months ago
- 1 answers
Posted by Amrith Sagar 5 years, 4 months ago
- 0 answers
Posted by Ravi Yadav 5 years, 4 months ago
- 1 answers
Posted by Praveen Kumar Mahto 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
We are given a = 17, d = -2, Sn = 72 and we have to find n.
Using Sn = n[2a +(n -1)d]/2, we get
72 = n[2.17 +(n -1)(-2)]/2 = n(36 -2n)/2 = n(18 -n)
=> n² -18n +72 = 0 => (n -6)(n -12) = 0
=> n = 6, 12
Both values of n, being positive integers are valid. We get double answer because sum of 7th to 12th terms is zero, as some terms are positive and some are negative.
Posted by Khushi Chaurasia 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
a = 121
d = -4
let an= 0
then
an = a + (n-1)d
=> 0 = 121 + (n-1)(-4)
=> 0 = 121 - 4n + 4
=> 4n = 125
=> n = 125/4
=> n = 31.25
as n must be natural number then n= 32
32nd term is First negative number.
a32 = 121 + (31)-4
= 121 - 124 = -3
Posted by Rekha Tiwari 5 years, 4 months ago
- 3 answers
Rekha Tiwari 5 years, 4 months ago
Rekha Tiwari 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
On the trig unit circle, arc 145 is in Quadrant II
cos 145 = - cos (35)
Calculator gives -> cos 35 = 0.82
Therefor, cos 145 = - 0.82.
Posted by Prachi Mishra 5 years, 4 months ago
- 0 answers
Posted by Ujjwal Kumar 5 years, 4 months ago
- 1 answers
Swastik Kumar Tripathy 5 years, 4 months ago
Posted by Manish Lahoti 5 years, 4 months ago
- 1 answers
Dhruv Jain 5 years, 4 months ago
Posted by Sapan Prusty 5 years, 4 months ago
- 1 answers
Dhruv Jain 5 years, 4 months ago
Posted by Hoshiyar Singh 5 years, 4 months ago
- 2 answers
Posted by Mitali Kanojia 5 years, 4 months ago
- 2 answers
Dhruv Jain 5 years, 4 months ago
Posted by Mahesh.N N 5 years, 4 months ago
- 3 answers
Dhruv Jain 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
Probability for rolling two dice with the six sided dots such as 1, 2, 3, 4, 5 and 6 dots in each die.
Posted by Ayushi Singh 5 years, 4 months ago
- 4 answers
Posted by Yugant Moon 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
2x-3y+5=0
Put x = 3 and y= a
2(3) -3a+5=0
6 - 3a + 5 = 0
11 - 3a =0
3a = 11
a = 11/3
Posted by Anshul Kandpal 5 years, 4 months ago
- 1 answers
Ishita Khadpe 5 years, 4 months ago
Posted by Š&Ãś&Wàť Khäřë 5 years, 4 months ago
- 3 answers
Gaurav Seth 5 years, 4 months ago
According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers q and r which satisfies the condition a = bq + r where 0 ≤ r ≤ b.
Gaurav Seth 5 years, 4 months ago
Theorem (Euclid’s Division Lemma):
For a pair of given positive integers ‘a’ and ‘b’, there exist unique integers ‘q’ and ‘r’ such that
a=bq+ra=bq+r, where 0≤r<b0≤r<b
Explanation:
Thus, for any pair of two positive integers a and b; the relation
a=bq+ra=bq+r, where 0≤r<b0≤r<b
will be true where q is some integer.
<hr />Example:
(a) 20, 8
Let 20 = a and 8 = b
Therefore, by applying the relation a=bq+ra=bq+r, where 0≤r<b0≤r<b we get 20=8×2+420=8×2+4 (In this q=2q=2 and r=4r=4)
Posted by Samruddhi Br 5 years, 4 months ago
- 1 answers
Meghna Thapar 5 years, 4 months ago
The elimination method of solving systems of equations is also called the addition method. To solve a system of equations by elimination we transform the system such that one variable "cancels out". ... In order to solve for y, take the value for x and substitute it back into either one of the original equations. In the elimination method you either add or subtract the equations to get an equation in one variable. When the coefficients of one variable are opposites you add the equations to eliminate a variable and when the coefficients of one variable are equal you subtract the equations to eliminate a variable.
Posted by Igam Basar 5 years, 4 months ago
- 2 answers
Arav Singh 5 years, 4 months ago
Posted by Durgacharan Sahu 5 years, 4 months ago
- 1 answers
Lucifer?? Morningstar?? 5 years, 4 months ago
Posted by Tanishq Rai 5 years, 4 months ago
- 1 answers
Posted by Surya Gantla 5 years, 4 months ago
- 1 answers
Ishita Khadpe 5 years, 4 months ago

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Sushant Mishra 5 years, 4 months ago
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