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Ask QuestionPosted by Aradhana Hota 5 years, 4 months ago
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? Pranali.A.P ? 5 years, 4 months ago
Posted by Namitha Namitha 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
Given that (a-b) x + (a + b)y = a2 - 2ab - b2 -------------(1)
(a+b) x+ (a+b)y = a2 + b2 -------------(2)
Substracting (2) from (1) we get
-2bx = -2ab
=2b2 x = a + b
Subsitute x in equation (2) we get y = - 2ab / ( a + b).
Posted by Vishal Verma 5 years, 4 months ago
- 5 answers
Posted by Ladli Verma 5 years, 4 months ago
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Satabdi Mandal 5 years, 4 months ago
Posted by Aaly Alie 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
sin 30°=1/2=>sin^2 30°=1/4
cos 45°=1/root 2=>cos^2 45°=1/2
tan 60°=root 3=>tan ^2 60°=3
So, 2 sin ^2 30°-3cos^2 45° +tan^2 60°
=>2(1/4)-3(1/2)+3
=>1/2-3/2+3
=>(1-3+6)/2
=>4/2
=>2
Posted by Riya Kumari 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
The given equations are:
x + 2y + 1 = 0 …….(i)
2x – 3y – 12 = 0 …….(ii)
Posted by Bharti Kumari 5 years, 4 months ago
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Virus Hacker 5 years, 4 months ago
Posted by Jahnavi Kumari 5 years, 4 months ago
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Posted by Shibil Habeeb 5 years, 4 months ago
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Posted by Tannu Choudhary 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
d1 = 7 - 3 = 4
And d2 = 10 - 7 = 3
3 ,7 ,10 is not an A.P.
Mr__Priyanshu ❤️______ __ 5 years, 4 months ago
Posted by Prakash Vyas 5 years, 4 months ago
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? Pranali.A.P ? 5 years, 4 months ago
Posted by Nikita Sharma 5 years, 4 months ago
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Posted by Ronak Miracle 5 years, 4 months ago
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Hanuman Prasad 5 years, 4 months ago
? Pranali.A.P ? 5 years, 4 months ago
Posted by Muskan Sokhal 5 years, 4 months ago
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Fallen Warrior 5 years, 4 months ago
Fallen Warrior 5 years, 4 months ago
Posted by Tanunav Arora Futela 5 years, 4 months ago
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Tanunav Arora Futela 5 years, 4 months ago
? Pranali.A.P ? 5 years, 4 months ago
Posted by Sunita Sirawag 5 years, 4 months ago
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? Pranali.A.P ? 5 years, 4 months ago
Posted by Arvind Choudhary 5 years, 4 months ago
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Posted by Rudranath Patel 5 years, 4 months ago
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? Pranali.A.P ? 5 years, 4 months ago
Posted by Gaurav Kumar Aryan 5 years, 4 months ago
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Deepika Shah 5 years, 4 months ago
Himangshu Das 5 years, 4 months ago
Posted by Aaradhana Kumar 5 years, 4 months ago
- 5 answers
Gaurav Seth 5 years, 4 months ago
We know that, the diagonals of a rhombus are perpendicular bisector of each other.
Given, AC = 16 cm and BD = 12 cm [let]
∴ AO = 8cm, SO = 6cm
and ∠AOB = 90°
In right angled ∠AOB,
Posted by Vaishnavi Belapurkar 5 years, 4 months ago
- 2 answers
Posted by Ankit Kumar 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
Let speed of boat in still water be x km/h and speed of stream be y km/h.
Speed upstream= (x - y) km/h
Speed downstream= (x + y) km/h

On subtracting, we get,

On solving, we get,

Speed of boat in still water = 8 km/h
And, Speed of stream = 3 km/h
Posted by Jaya Shree Meenakshi 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
Euclid division lemma:-
a=bq+r
First find the HCF of 693 and 567,
693=567(1)+126
567=126(4)+63
126=63(2)+0
HCF of 693 and 567 is 63.
Now find the HCF of 63 and 441,
441=63(7)+0
The HCF of 63 and 441 is 63.
Therefore, the HCF of 441,567 and 693 is 63.
Posted by Ankita Chhabra 5 years, 4 months ago
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Posted by Anitha Joseph 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Q: Use Euclid's division lemma to show that the cube of any positive integer is of the form 9m,9m+1 or 9m+8
Let x be any positive integer. Then, it is of the form 3q or, 3q + 1 or, 3q + 2.
So, we have the following cases :
Case I : When x = 3q.
then, x3 = (3q)3 = 27q3 = 9 (3q3) = 9m, where m = 3q3.
Case II : When x = 3q + 1
then, x3 = (3q + 1)3
= 27q3 + 27q2 + 9q + 1
= 9 q (3q2 + 3q + 1) + 1
= 9m + 1, where m = q (3q2 + 3q + 1)
Case III. When x = 3q + 2
then, x3 = (3q + 2)3
= 27 q3 + 54q2 + 36q + 8
= 9q (3q2 + 6q + 4) + 8
= 9 m + 8, where m = q (3q2 + 6q + 4)
Hence, x3 is either of the form 9 m or 9 m + 1 or, 9 m + 8.
Posted by Høñéy Khäñ 5 years, 4 months ago
- 1 answers

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? Pranali.A.P ? 5 years, 4 months ago
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