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Gaurav Seth 4 years, 11 months ago

Fundamental Theorem of Arithmetic:
Fundamental Theorem of Arithmetic states that every composite number greater than 1 can be expressed or factorised as a unique product of prime numbers except in the order of the prime factors.

We can write the prime factorisation of a number in the form of powers of its prime factors.

By expressing any two numbers as their prime factors, their highest common factor (HCF) and lowest common multiple (LCM) can be easily calculated.

The HCF of two numbers is equal to the product of the terms containing the least powers of common prime factors of the two numbers.

The LCM of two numbers is equal to the product of the terms containing the greatest powers of all prime factors of the two numbers.

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Mr__Priyanshu ❤️______ __ 4 years, 11 months ago

U know how to find syllabous which is removed
Ok.

? Pranali.A.P ? 4 years, 11 months ago

Haa

Mr__Priyanshu ❤️______ __ 4 years, 11 months ago

Syllabus dekh lo remove ho gya hai
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? Pranali.A.P ? 4 years, 11 months ago

Isss me se konsa question chahiye aapko
4.1
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Mr__Priyanshu ❤️______ __ 4 years, 11 months ago

Questions hai kya hoga to dana

Deepa Kumari 4 years, 11 months ago

what does it mean

? Pranali.A.P ? 4 years, 11 months ago

What?
  • 1 answers

? Pranali.A.P ? 4 years, 11 months ago

0.17142857142
  • 2 answers

Mr__Priyanshu ❤️______ __ 4 years, 11 months ago

This topic is removed in cbse board

? Pranali.A.P ? 4 years, 11 months ago

According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers q and r which satisfies the condition a = bq + r where 0 ≤ r < b. The basis of the Euclidean division algorithm is Euclid’s division lemma. To calculate the Highest Common Factor (HCF) of two positive integers a and b we use Euclid’s division algorithm. HCF is the largest number which exactly divides two or more positive integers. By exactly we mean that on dividing both the integers a and b the remainder is zero.
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? Pranali.A.P ? 4 years, 11 months ago

Let the total Rs. be 20....... Let the cost of giant wheel be X...... Let the cost of hoopla be Y...... so it will be,........ X+Y=20....... GRAPHICALLY-------.... X+Y=20....... Y=20-X..... now putting X as 5 we get Y 15...... Putting X as 10 we will get Y 10....... putting X as 15 we will get Y 5..... Now bro you can plot these values on graph

? Pranali.A.P ? 4 years, 11 months ago

x+y=20

Savita Choudhary 4 years, 11 months ago

u may find the full ques. in book itsèlf read it propery it is written that go to section 3.1 that is first page of ch . and read the intro. u will find the answer
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Arpita Singh 4 years, 11 months ago

LHS=CosA/1-tanA+sinA/1-cotA→CosA/1-sinA/cosA+sinA/1-cosA/sinA→cosA/cosA-sinA/cosA+sinA/sinA-cosA/sinA→cos^2A/cosA-sinA+sin^2A/sinA-cosA→cos^2A-sin^2A/cosA-sinA→(cosA+sinA)(cosA-sinA)/(cosA-sinA)→cosA+sinA (HENCE PROVED)
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Shakthi .Na 4 years, 11 months ago

Draw a right angle triangle which the BC is the adjacent side and AB as a perpendicular side and AC is a hypotenuse Then the given is 45° of angle of elevation so tan A = 45° So, to find the height let AB be the height and BC be the base 100m so, BC/AC = Tan 45° Sub BC and AC and Tan 45° as h and 100 and 1 h/100 = 1 h = 100*1 h= 100
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Mr__Priyanshu ❤️______ __ 4 years, 11 months ago

Kon sa question

Mr__Priyanshu ❤️______ __ 4 years, 11 months ago

Questions
  • 2 answers

Arpita Singh 4 years, 11 months ago

Here, the A.P. will be 110,121,....,693 an=a+(n-1)d 693=110+(n-1)*11 693-110=(n-1)*11 583=(n-1)*11 n-1=583/11 n-1=53 n=54 Answer

? Pranali.A.P ? 4 years, 11 months ago

Don't know
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Yogita Ingle 4 years, 11 months ago

We can rewrite the equations as:

2x – 5y = - 4

& 2x + y = 8

For equation, 2x – 5y = - 4

First, take x = 0 and find the value of y.

Then, take y = 0 and find the value of x.


Now similarly solve for equation, 2x + y = 8

Plot the values in a graph and find the intersecting point for the solution.

Hence, the solution so obtained from the graph is (3,2), which is the intersecting point of the two lines.

The vertices of the formed triangle by these lines and the y - axis in the graph are A(3,2), B(0,8) and C(0,0.8).

 

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? Pranali.A.P ? 4 years, 11 months ago

Given equations are 2x+4y=10 and 3x+6y=12 now in these two equations take a1 =2 and a2 = 3 b1 = 4 and b2 = 6 c1 =10 and c2 =12 by a1/a2 =2/3 b1 /b2 = 4/6 =2/3 c1/c2 = 10/12 =5/6 when a1/a2 = b1/b2 ≠c1/c2 the two equations have no solution
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? Pranali.A.P ? 4 years, 11 months ago

⇒ Let breadth be x. Then, length will be 2x........ ⇒ Area of rectangular mango grove =800m 2.......... ⇒ x×2x=800........ ⇒ 2x 2... .... =800........ ⇒ x 2 =400................. ∴ x=±20 ⇒ x can not be negative...... ∴ x=20........ ⇒ Breadth of the rectangular mango grove =x=20m....... ⇒ Length of the rectangular mango grove =2x=20×2=40m....

Gaurav Seth 4 years, 11 months ago

Let the breadth of the rectangular mango grove be x m
So, length = ‘2’ m
According to question,
Area = 800
⇒ 2x(x) = 800
⇒ 2x2 = 800
⇒ x2 = 400
⇒ x2 – 400 = 0
⇒ x2 + 0x – 400 = 0
Here, a = 1, b = 0, c = – 400
D = b2 – 4ac
= 0 – 4(1) (–400)
= 1600
So, the given quadratic equation has real roots (∵ D > 0) and hence it is possible to design rectangular mango grove.
Now, solving the quadratic equation x2 + 0x – 400 = 0, by quadratic formula, we get,

                     

              
              
∵                is not possible
So,              
Hence, breadth of the rectangular mango grove is 20 m and length is 40 m.

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Rakshit Goyal 4 years, 11 months ago

I don't have any idea bro

Rakesh Garg 5 years ago

Mujhe nhi pta
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Mayur Chauhan 5 years ago

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/q squaring both sides √13*2=p*2/q*2 13=p*2/q*2 13q*2=p*2 13/p*2 13/p p=3r for some integer r p*2=169r*2 13q*2=169*2 b*2=13r*2 13/b*2 13/b 13 is a common factor but this is contradiction hence our supposition is wrong √13 is irrational no.
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? Pranali.A.P ? 5 years ago

Ha thik hai bye
Ok thanks for given advice

Raman Upadhyay 5 years ago

Aur ha apna number aisa kisi bhi aap par mat share kiya karo warna uske karan tumhe pareshani ho sakti hai
Sorry message

Raman Upadhyay 5 years ago

Bhai massage ya message
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Arham Sanklecha 5 years ago

Do your it self
  • 5 answers
Ok

Sumit ? 5 years ago

Ya

? Pranali.A.P ? 5 years ago

Sumit , i think aap bhi Maharashtra se ho...... I am right

? Pranali.A.P ? 5 years ago

Ha , priyanshu aap muze sister bol sakte ho

? Pranali.A.P ? 5 years ago

Kya
  • 5 answers
Ji bilkul आप मुझे भाई बोल सकती है!
Questions kaha hai

? Pranali.A.P ? 5 years ago

Priyanshu aapne mere question ka answer nhi diya
Not now Till 15 july u will ask me or i will tell you. Board exam will pospoin it .

? Pranali.A.P ? 5 years ago

Don't know
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Gaurav Seth 5 years ago

We know that:

(i) sin(90 - A) = cosA.

(ii) cotA = (1/tanA).

(iii) tan(90 - A) = cotA

Now, Coming to the question.

= > 1 + 1

= > 2.

  • 1 answers
Exercise ????

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