CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let first side =5* second side =12* third side =13* Perimeter =150 Perimeter= a+b+c 150 =(5*)+(12*)+(13*) 150 =30* Area = 1/2*base*height =1/2*24*14.5 = 12*14.5 = 174cm sq.

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Saurabh ???? 5 years, 2 months ago

Area of triangle=1/2*base*height = 1/2*24*14.5 =12*14.5 = 174 Cm square

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Gaurav Bhati 5 years, 2 months ago

Let the side of tria

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Find the area of the triangle whose the side are 18 c m 24 cm and 30 cm also' find the height corresponding to the smallest side

Posted by Sonam Kumari Paswan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

p = (18 + 24 + 30) ÷ 2 = 36 cm

area = √p(p-a)(p-b)(p-c)

area = √36(36 - 18)(36 - 24)(26 - 30)

area = √46656

area = 216 cm²

area = 1/2 (base) (height)

216 = 1/2 (18) (height)

216 = 9 height

height = 216 ÷ 9 = 24 cm
The area is 216 cm² and the corresponding height is 24 cm

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Find the area of the triangle whose sides are 42 cm' 34cm and 20 cm also ' find the height corresponding to the longest side

Posted by Sonam Kumari Paswan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

Semiperimeter (s) = (42 + 34 + 20 ) / 2
So it is = 96 / 2 = 48 cm.

Using herons formula = (√s )(√s-a )(√s-b) (√s-c)
By substituting s and a , b , c i.e the given sides.
We have √48 × √6 × √14 × √28
So √ (4 × 6 × 2) × √6 × √(7 × 2) × √(7 × 4)
Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm ²
Hence area is 336 cm²
Now height corresponding to longest side implies that base is 42 cm and area remains same
So area of triangle is 1/ 2 b × h
336 = 1/ 2 × 42 × H
HENCE H = 16 cm
So height is 16 cm .

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ANSWER

Find the area of the triangle whose base measure 24cm and the corresponding height measure 14.5 cm

Posted by Sonam Kumari Paswan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If the difference between the circumference and radius of the circle is 37 cm then using pi=22/7 .Find the circumference of circle.

Posted by Arshpreet Kaur Sandhu 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

Let r be the radius of circle.
Difference between circumference and radius of circle = 37 cm
Circumference of circle = 2r
= 2 x 22/7 x r = 44/7 x r
Now,
Difference between circumference and radius of circle = 2r - r
37 = 44/7 x r - r
37 = r(44/7-1)
37 = r(44 - 7)/7
37 = 37 / 7 x r
37 x 7/37 = r
r = 7 cm
Now , Circumference of circle = 44/7 x r
= 44/7 x 7
= 44 cm .
∴ Circumference of circle = 44 cm

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ANSWER

Proove thales formula

Posted by Radhika Shukla 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If tanA=4/5 then find the Value of cosA-sinA/cosA+sinA

Posted by Lakhan Sahu 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Samyuktha Kocherlakota 5 years, 2 months ago

Tan A =4/5=B/C CosA _ SinA /CosA+SinA=4_5/root 41/4+5/root41 1/9

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Samyuktha Kocherlakota 5 years, 2 months ago

1/9

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ANSWER

(sec A + Tan A )(1-sin A)=

Posted by Abhishek Singh Gurjar X-B Roll No.-02 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Samyuktha Kocherlakota 5 years, 2 months ago

SecA = 1/cos a,tanA=sina /cosa (1/cos a+sina /cosa)(1_sina) 1_sina)(1+sina)/cosa 1_sin^2 a/cosa Cos^2A/cosA Cosa

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Samyuktha Kocherlakota 5 years, 2 months ago

Cos A

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2009 board exam Questions

Posted by Tushar Deka 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The pairIf the zeros of quadratic polynomial ax

Posted by Dileswar Behera 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Dileswar Behera 5 years, 1 month ago

a.a.b.b

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ANSWER

Deleted exercise and questions from maths according to new syllabus

Posted by Khush Kaur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Radhika Shukla 5 years, 2 months ago

Go on to google

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ANSWER

a railway half ticket cost half the full fare but the reservation charges are the same on half

Posted by Kirtan Miyani 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find out 2(9)3

Posted by Deepu Singh 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Saurabh ???? 5 years, 2 months ago

1458

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Find the hcf of 96 and 404 by the prime factorisation method. Hence find there LCM.

Posted by Krishna Kumawat 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Dileswar Behera 5 years, 2 months ago

The decimal experssion120/3*3*3*5*5*5*5*5*5*5is

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Yogita Ingle 5 years, 2 months ago

Since, 96 = 2 × 2 × 2 × 2 × 2 × 3
and, 404 = 2 × 2 × 101
So, HCF of 96 and 404 = Product of common prime factors
= 2 × 2 = 4
LCM = 2 × 2 × 2 × 2 × 2 × 101 × 3
= 9696

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ANSWER

Find the area of triangle whose sides are x=y, 3x =y , x+y =8

Posted by Pranali Marnur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Anshul Rathor 5 years, 2 months ago

4 sq units.

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What is the formula of LCM

Posted by Anvi Pundir 5 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Abhishek Singh Gurjar X-B Roll No.-02 5 years, 2 months ago

This is the formula for LCM- Product of AB /HCF of AB = LCM

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Ajin Ajin 5 years, 2 months ago

Sorry LCM is 12

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Ajin Ajin 5 years, 2 months ago

Least common multiple for example 6 , 12 LCM is 6

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Pranali Marnur 5 years, 2 months ago

Product of AB /HCF of AB = LCM

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What do you mean by chord

Posted by Aayushmaan Rana 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sarthak Pampatwar 5 years, 2 months ago

A chord means a line joining two points of the circle without joining to the centre

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Kotadiya Kalpesh 5 years, 2 months ago

A chord is a secant line or just secant . In another word chord is line segment joining two pointson any curve, for instance,an ellipsis.

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ANSWER

(cosec A -secA )(cot A-Tan A)=(cosec A+secA )(SecA cosecA -2 )

Posted by Kavita Goel 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Rohit Kumar 5 years, 2 months ago

LHS:- (cosecA-secA)( cotA-tanA) => (1/sinA-1/cosA)(cosA/sinA-sinA/cosA) => (cosA-sinA/sinAcosA)(Cos^2A-sin^2A/sinAcosA) => (cosA-sinA)(cosA+sinA)(cosA-sinA) /(sinAcosA)^2 => (cosA-sinA)^2(cosA+sinA)/(sinAcosA)^2 => (cos^2A+sin^2A-2cosAsinA)(cosA+sinA)/(sinAcosA)^2 => (1-2cosAsinA)/(cosAsinA) (cosA+sinA)/(cosAsinA) (since cos^2A+sin^2A=1) => (1/cosAsinA-2cosAsinA/cosAsinA)(cosA/cosAsinA+sinA/cosAsinA) => (secAcosecA-2)(cosecA+secA) Hence, LHS=RHS

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ANSWER

Root 3 and -root 3 are the zeroes of f(x) = xcube + 13x square + 32x+2 find its other zeroes.

Posted by Pranathi M 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Plz koi channel btayo jha muje maths ka new syllabus k according pdhne ko mile

Posted by Khush Kaur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Harman Preet 5 years, 2 months ago

Vedantu

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Rishabh Sharma 5 years, 2 months ago

You can consider YouTube channel Easy maths https://www.youtube.com/user/akashchauhancsit It will provide best study

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#Abhisht Singh 5 years, 2 months ago

Cbse classes

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The length of a rectangular Park is i twice its breath and its perimeter is 840 m find the area of the park

Posted by Sonam Kumari Paswan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Pooja Choudhary 5 years, 2 months ago

Let breadth of rectangular park = x m

Therefore, length of park = 2x m

Perimeter = 840 m

2×(Length+Breadth) = 840

2×(x+2x)=840

2×3x = 840

6x = 840

x=840/6

x= 140 m

Length = 2x = 2×140 = 280 m

Breadth = x = 140 m

Area = length × breadth

= 280 × 140

= 39200 m²

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ANSWER

The perimeter of a rectangular plot of land is 80 m and its breath 16 m find the the end area of the plot

Posted by Sonam Kumari Paswan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Pooja Choudhary 5 years, 2 months ago

Let length = x m

Breadth = 16 m

Perimeter = 80 m

2 × ( l + b ) = 80

2 × ( x + 16 ) = 80

x+16 = 80/2

x+16 = 40

x = 40-16 = 24

Length = 24 m

Area = length × breadth

= 24×16

= 384 m²

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ANSWER

If x = p tan θ + q sec θ and y = p sec θ + q tan θ then prove that 2 2 2 2 x − y = q − p . .

Posted by Mirza Shahid 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Solve by cross multiplication (a-b)x+(a+b)y= a^2-2ab-b^2 (a+by)+(x+y)=(a^2+b^2)

Posted by Aayush Singh 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If An=5n-2 then find S4

Posted by Swati Telang 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditya Kumar 5 years, 2 months ago

First find A1 Next find A4 Now, we have A=A1, L=A4 and N=4 By putting these values in formula of Sn=n/2 (a+l) we will get S4= 42

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Aditya Kumar 5 years, 2 months ago

S4=42

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ANSWER

a fraction becomes 1 by 3 if 1 is subtracted from both its numerator and denominator if 1 is added to both the numerator and denominator it becomes 1 by 2 find the fraction

Posted by Shweta Zine 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditya Kumar 5 years, 2 months ago

Let numerator be n, and denominator be d a to q (n-1) /(d-1) =1/3 after solving it we will get 3n-d=2 --------------------(i) now, (n+1) /(d+1) =1/2 after solving it we will get d-2n=1 --------------------(ii) Adding both eqn, we get n=3 By putting value of n =3 in any one eqn we get, d=7 So the fraction, n/d=3/7

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Aditya Kumar 5 years, 2 months ago

Fraction = 3/7

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ANSWER

In the given figure, if PQRS is a parallelogram and AB || PS, then prove that OC || SR.

Posted by Ramana Kishore 5 years, 2 months ago

CBSE > Class 10 > Mathematics