No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Meenakshi Kasi 5 years, 2 months ago

150
  • 1 answers

Sharan M 5 years, 2 months ago

Very good ?
  • 0 answers
  • 2 answers

Ahmad Aashique 5 years, 2 months ago

Your basic concept must be clear, then u prepare for maths quiz

Seema Choudhary 5 years, 2 months ago

U must know the basics
  • 1 answers

Souvik Dan 5 years, 2 months ago

3cotq=4 then cotq=4/3 now, putting the value of cotq in a right angled triangle we get hypotenuse =5 [by pythagoras theorem] now find the value of cosq and sinq cosq=4/5 , sinq =3/5 now putting this value n the equation we get, =>4*4/5-3/5//2*4/5+3/5 =>16/5-3/5//8/5+3/5 [multipling 4*4/5 in numerator and 2*4/5 in denomiator] =>13/5 //11/5 =>13/5*5/11 =>13/11
  • 2 answers

Sejal Thakur 5 years, 2 months ago

???

Yogita Ingle 5 years, 2 months ago

Let the present age of Nuri  =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10                       ………..(1)

Ten years later,

Age of Nuri  =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10                           ………..(2)

X–3y=−10                        ………..(1)

Subtracting equation (1) from equation (2)  we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age  of Nuri =50 years and age of Sonu =20 years

  • 4 answers

Sejal Thakur 5 years, 2 months ago

Who are to say this question are wrong

Sejal Thakur 5 years, 2 months ago

Woh are you?

Neha Kakkar ?? 5 years, 2 months ago

Okay.

Sejal Thakur 5 years, 2 months ago

This question wrong
  • 1 answers

Malaika Sharma 5 years, 2 months ago

2×1=2 2×2=4 2×3=6 2×4=8 2×5=10 2×6=12 2×7=14 2×8=16 2×9=18 2×10=20
  • 1 answers

Payal Kundarä 5 years, 2 months ago

By using distance formula √( X2 -X1)² + (Y2 -Y1)²
  • 1 answers

Ram Kushwah 5 years, 2 months ago

2x²+5px+7q=0

Let the roots are a and 1/a

Product of roots=a*1/a=1

so 7q/2=1

So q=2/7

  • 2 answers

Anshuman Omm 5 years, 2 months ago

SinA=TanA *CosA

Anshuman Omm 5 years, 2 months ago

SinA =TanA/cosA
  • 3 answers

Riya Philip 5 years, 2 months ago

Join betternation.xyz This is a site where u can have a lot of friends and fun ? ? ?

Adarsh Awasthi 5 years, 2 months ago

Ghanta lala

Sonu Jha 5 years, 2 months ago

THANKS FOR SUBSCRIBING THE CHANNEL.?????
  • 0 answers
  • 5 answers

Mahendra Pal 5 years, 2 months ago

Three digit number are100 to 999 105,112,119.......994 Ans:128

Anshul Agarwal 5 years, 2 months ago

128

Arpit Bhardwaj 5 years, 2 months ago

By Euclid divisor lemma -: 999 / 7= 142*7+5 Here 999 is a divident 7 is quoent 142 is divisor 5 is reminder So 7 number is 999-5= 994 (You know that higest nois 3 digit is 999 )

Krishan Rangi 5 years, 2 months ago

128

Riya Sharma 5 years, 2 months ago

The first 3-digit number which is divisible by 7 is 105 The last 3-digit number which is divisible by 7 is 994 The list of 3-digit numbers divisible by 7 are 105, 112, 119,…..994 which forms an A.P Consider a formula T(n) = a + (n – 1)d Where a = 105 d = 7 T(n) = 994 994 = 105 + (n – 1)7 889 = 7n – 7 7n = 896 n = 128 ∴ There are 128 3-digits number which are divisible by 7
  • 5 answers

Shubham Saxena ???? 5 years, 2 months ago

X= 4 ,, y = 2

Kruti Sojitra 5 years, 2 months ago

2(4)+3y=14,3y=14-6,3y=12,y=12/3=4

Anshul Agarwal 5 years, 2 months ago

3-1

Satyam Verma 5 years, 2 months ago

Y=2

Khumpui Debbbarma 5 years, 2 months ago

Ansew
  • 3 answers

Malaika Sharma 5 years, 2 months ago

Let us assume 3+root 5 to be rational.It means that it can be written in the form of p/q where p and q are coprime and q is not equal to zero L.H.S *p/q=3+root5 *p/q-3=root5 L.H.S i.e.p/q-3 is rational but R.H.S i.e. root 5 is irrational So our assumption is wrong Therefore 3+root5 is irrational.

Anshul Agarwal 5 years, 2 months ago

Hence proved

Riya Sharma 5 years, 2 months ago

Let us assume that 3+5​ is a rational number. Now, 3+5​=ba​ [Here a and b are co-prime numbers] 5​=[(ba​)−3] 5​=[(ba−3b​)] Here, [(ba−3b​)] is a rational number. But we know that 5​ is an irrational number. So, [(ba−3b​)] is also a irrational number. So, our assumption is wrong. 3+5​ is an irrational number. Hence, proved.
7.3
  • 0 answers
  • 0 answers
  • 1 answers

Riya Sharma 5 years, 2 months ago

x,y}={2,3
  • 3 answers

Yogita Ingle 5 years, 2 months ago

Let a and d be the first term and common difference of AP

nth term of AP

an​=a+(n−1)d

∴a3​=a+(3−1)d=a+2d

a7​=a+(7−1)d=a+6d

Given a3​+a7​=6

∴(a+2d)+(a+6d)=6

⇒2a+8d=6

⇒a+4d=3....(1)

Also given

a3​×a7​=8

∴(a+2d)(a+6d)=8

⇒(3−4d+2d)(3−4d+6d)=8       [Using (1)]

⇒(3−2d)(3+2d)=8

⇒9−4d2=8

⇒4d2=1

⇒d2=1/4

⇒d=± 1/2

When d=1/2

a=3−4d=3−4×(1/2) ​=3−2=1

When d=−1/2

a=3−4d=3+4×(1/2) =3+2=5

When a=1 & d=21​

S16​=216​[2×1+(16−1)×21​]=8(2+215​)=4×19=76

When a=5 & d=−21​

S16​=216​[2×5+(16−1)×(−21​)]=8(10−215​)=4×5=20

Thus, the sum of first 16 terms of the AP is 76 or 20.

Dharanyaa Senthamizh 5 years, 2 months ago

Triangle

Mayank Singh 5 years, 2 months ago

1.33

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App