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Let N be a number such that,
N = 5( mod 16)
i.e.
N = 16x + 5
Where, x is any positive integer.
We can write,
N = 8(2x) + 5
if x = positive integer, 2x is also a positive integer.
Let 2x = y,
N = 8y + 5
Thus, N = 5(mod 8)
Hence, the remainder when the same number is divided by 8 would also be 5.
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Kuppireddy Adityareddy 4 years, 7 months ago
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