CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Assume that √5 is rational, so it has of the form √5=a/b, where a and b are coprimes (both numbers have only common factor as1) √5 =a/b square both sides then 5=a^2/b^2 ie a^2 =5b^2 let it be eq1 a^2 /5=b^2 now a^2is divisible by 5 therefore a is divisible by 5 now take a=5c from eq1 we get 25c^2 =5b^2 ,5c^2 =b^2 Now c^2 =b^2/5 now b^2 is divisible by 5 by theorem 1.3 a and b have a common factor as 5 so our assumption is wrong √5 is irrational Now we have to prove 7√5 is irrational we already proved √5 is irrational Now assume 7√5 is irrational therefore 7√5 =a/b we know √5 is irrational so 7√5=a/b √5=a/7b where √5 is irrational and a/7b is rational So it is contradiction to our assumption therefore our assumption is wrong 7√5 is irrational

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Thou Thou 4 years, 7 months ago

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Find the area of the shaded region .if pq=24 cm ,pr =7 cm and 0 is the centre of the circle .

Posted by Mamta Jemore 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Sahil Singh 4 years, 7 months ago

Given, PQ=24cm PR=7cm O is the center of circle To find shaded region In ∆PQR ar(PQR)= 1/2×PR×PQ 1/2×24×7=84cm^2 we know that RQ is the hypotenuse of ∆PQR and diameter of the circle then, To find RQ RQ^2=PR^2+PQ^2 RQ^2=24^2+7^2 RQ^2=576+49 RQ^2=625 RQ=√625 RQ=25cm area of circle semicircle, 1/2πr^2 1/2π×(24)^2 by solving using the value od π we get 6875/28 Area of shaded region= Area of semicircle- Area of tirange pqr 6875/28-84=4532/28ans

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Prabhu Pachisia 4 years, 7 months ago

where is the figure?

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What is clinometer ?

Posted by Mamta Jemore 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Tofik Makrani 4 years, 7 months ago

Statistics median

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Xsquare-2x-8

Posted by Supriya Sharma 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Ayushi Agrawal 4 years, 7 months ago

x^2- 2x-8=0 x^2-4x+2x-8=0 x(x-4)+2(x-4)=0 (x+2)(x-4)=0 x+2=0 x=-2. Ans. And x-4=0 x=4. Ans.

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Jeeya Surana 4 years, 7 months ago

Xsquare-4x+2x-8 Xsquare+2x-4x-8 X(x-2)+4(x-2) (X+4)(x-2) X=-4,2

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2 square into minus 3 X + 5 equal to zero

Posted by Aman Khan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayushi Agrawal 4 years, 7 months ago

2x^2-3x=0 2x- 5x + 2x+5=0 x(2x-5)-1(2x-5)=0 (x-1)(2x-5)=0 x-1=0 x = 1 Ans. 2x-5=0 2x = 5 x=5/2 Ans.

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Find the nature of the roots of the following quadratic equations if the real roots exist find them

Posted by Aman Khan 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sriya Auromeera 4 years, 7 months ago

R u Amman from IT?

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What is the relation between a and b, if sum of the zeroes of the quadratic polynomial a x 2 + b x + c ( ? ≠ 0 ) is equal to the product of the zeroes .

Posted by Athira Sunilkumar 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Mohit Lamba 4 years, 6 months ago

Condition is c=-b

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Riya Shingh 4 years, 7 months ago

Mai tumko ans batugi tho tum muje ans bataogai Jo Mai 3 questions post ki Hu Hindi Ka uska.....?

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In figure abc and edc if we have ab=4cm and ed=3cm ce=4.2 and cd=4.8cm then the value of ca and cb are?

Posted by Anish Soni 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Shreya Bhardwaj 4 years, 7 months ago

5.2

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5+76544422

Posted by Gyani Brain 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Kukatla Ajith Kumar Yadav 4 years, 7 months ago

the total value of 5+76544422 is:-76544427

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If the arithmetic mean of the following data is 25 , find the value of K Xi-5,15,25,35,45 Fi - 3,k,3,6,2

Posted by Lakshita Vashist 4 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

312+852

Posted by Anil Routh 4 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Jeeya Surana 4 years, 7 months ago

1164

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Yogesh Thakur 4 years, 7 months ago

312852

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Ipsita Kabi 4 years, 7 months ago

1164

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Case study based questions in standard Page no 80

Posted by Diya Yadav 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ranvijay Kumar 4 years, 7 months ago

What is this

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What is the distance between the points A (Sin theta- Cos theta,0 ) and B(0,Sin theta+Cos theta)?

Posted by Kritarth Baranwal 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Gunn Bhatia 4 years, 7 months ago

= whole root (0 - sin theta + cos theta)^2 + (sin theta + cos theta - 0)^2 = whole root sin ^2 theta + cos^2 theta + sin ^2 theta + cos ^2 theta = whole root 2sin ^2 theta + 2cos ^2 theta = whole root 2(sin ^2 theta + cos ^2 theta ) = whole root 2(1) [since sin^2 theta + cos^2 theta =1] = therefore root 2 Distance is root 2

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A motorboat covers distance of 16 kilometre upstream and 24 kilometre downstream in 6 hour in the same time it covers a distance of 12 kilometre upstream and 36 kilometre downstream find the speed of the boat in in still water and that of the steam

Posted by Dilsa Hanna Mosses 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Lokireddy Anjaneyareddy 4 years, 7 months ago

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Rishita Bharadwaj 4 years, 7 months ago

Let speed of boat be x and speed of stream be y Speed of upstream= x-y and speed of downstream= x+y Case 1: T1+T2= Total time 16/x-y + 24/x+y=6 16u+24v=6 8u+12v=3......(1) Case 2: 12/x-y +36/x+y=6 12u+36v=6 2u+6v=1.......(2)

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Write all the other trigonometric ratios of<A in terms of A

Posted by Siva Ram 4 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Jeeya Surana 4 years, 7 months ago

Ratios of???

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solve for x 36x^2-12ax+(a^2-b^2)=0

Posted by Amani Aggarwal 4 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Gokul J 4 years, 7 months ago

36x2−12ax+(a2−b2)=0 Ax2+Bx+C=0 from, A=36 B=−12a C=(a2−b2) Roots of quadratic equation formula : x=2A−B±B2−4AC =2×3612a±144a2−144(a2−b2) =7212a±144b2 =7212a±12b =6a±b ⇒x=6a+b or 6a−b

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Amani Aggarwal 4 years, 7 months ago

pls reply

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Make a pie chart on the languages of nagaland

Posted by Jayant Jain 4 years, 7 months ago

CBSE > Class 10 > Mathematics