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  • 1 answers

Harsh Gupta 4 years, 5 months ago

Can u pls write ur ques again .
  • 2 answers

Somya Jaiswal 4 years, 5 months ago

N=40

Simran Rathore 4 years, 5 months ago

a=11 d=8-11= -3 an=-150 n=? an=a+(n-1)d -150=11+(n-1)(-3) -150/-3=11+n-1 50=11+n-1 50-11=n-1 39+1=n n=40
  • 2 answers

Kyira Singh 4 years, 5 months ago

1/7

Gagandeep Singh 4 years, 5 months ago

1/7
  • 4 answers

Gagandeep Singh 4 years, 5 months ago

In a leap year only 2 days are extra , so these 2 days could be Monday, Tuesday Tuesday, Wednesday Wednesday, Thursday Thursday, Friday Friday , Saturday Saturday, Sunday Sunday , Monday Out of these, there is only 1 favourable outcome i.e. Saturday , Sunday So probability =1/7

Arnav Kadam 4 years, 5 months ago

2/7

Shyam Singh Bangari 4 years, 5 months ago

2/7

Shyam Singh Bangari 4 years, 5 months ago

2 by 7
  • 5 answers

Ankita Sharma 4 years, 5 months ago

2

Mallika Mondal 4 years, 5 months ago

2

Abhishek Singh 4 years, 5 months ago

2

Abhishek Singh 4 years, 5 months ago

2

Prathyush Patne 4 years, 5 months ago

2
  • 3 answers

Anchal Bhati 4 years, 5 months ago

Taking L.H.S (1 - cos^2 ) cosec^2 = ( sin^2 ) cosec^2 = sin^2 × 1/ sin^2 = 1

Mayank Choudhary 4 years, 5 months ago

Sin square ×1/sin square

Vridhi Sharma 4 years, 5 months ago

Sin square ×1/sin square teta
  • 1 answers

Akshat Goyal 4 years, 5 months ago

they both have 55 marbles.so, ram has x no. of marbles and shyam has 55-x no. of marbles. both of lost 5 marbles each so now, no. of marbles Ram has=x-5 no. of marbles Shyam has = 55 - x - 5 = 50 - x now, (x - 5)(50 - x)= 164 50x - x^2 - 250 + 5x = 164 -x^2 + 55x - 250 = 164 -x^2 +55x -414=0 -(x^2 -55x + 414)= 0 x^2 - 55x +414 = 0 x^2 - 46x - 9x - 414 = 0 x(x - 46) -9(x - 46) = 0 (x - 46 )(x - 9) = 0 x = 46,9 so, the no. of marbles Ram and shyam had to start with are 46 and 9 marbles respectively or vice versa.
  • 4 answers

Kyira Singh 4 years, 5 months ago

If possible root 5 is rational no. 5=p/q( where q not equal 0 ,, p/q having no factors other than 1) Squaring both sides 5=P2/q2 P2=5q2....1 P2 is divisible by5 P is also divisible by 5 Putting p=5 in 1 (5m)2=5q2 25m2=5q2 5m2 =q2 q2 is divisible by 5 q is also divisible by 5 5 is common factors of p and q This is contradiction So,our assumption is wrong Root 5 is irrational no.

Rohit Singh 4 years, 5 months ago

Let us assume the given number be rational and we will write the given number in p/q form ⇒5− 3 ​ = q p ​ ⇒ 3 ​ = q 5q−p ​ We observe that LHS is irrational and RHS is rational, which is not possible. This is contradiction. Hence our assumption that given number is rational is false ⇒5− 3 ​ is irrational

Akshit Kaktwan 4 years, 5 months ago

I know anwer but can't type sorry

Shyam Singh Bangari 4 years, 5 months ago

soory
  • 5 answers

Ankita Sharma 4 years, 5 months ago

Ganit

Mayank Choudhary 4 years, 5 months ago

Maths full form is math आए गा tabi hoga Safal????

Anthony Samson 4 years, 5 months ago

N43445

Mallika Mondal 4 years, 5 months ago

????

Mallika Mondal 4 years, 5 months ago

MATHS full form is meri aatma tujha hamesa satayegi
  • 1 answers

Sejal Modanwal 4 years, 5 months ago

What is the question
  • 1 answers

Anthony Samson 4 years, 5 months ago

Hi
  • 1 answers

Sia ? 4 years, 5 months ago

Please ask question with complete information.

  • 5 answers

Raja Kumar 4 years, 5 months ago

1/2

Sayyaparaju Sahithi 4 years, 5 months ago

Sin30°=1/2

Somil Kamra 4 years, 5 months ago

1/2

Khushi 4 years, 5 months ago

sin30°=1/2

Suraj Gupta 4 years, 5 months ago

1/2
Wtf
  • 2 answers

Oav Papadahandi 4 years, 5 months ago

Yt?

Oav Papadahandi 4 years, 5 months ago

Hiii
  • 3 answers

Khushi 4 years, 5 months ago

Hello!! Mallika?? main bmms me padhti hu

Mallika Mondal 4 years, 5 months ago

Ap konsa school main ho khushi thank you for my answer

Khushi 4 years, 5 months ago

⇒Let side of bigger square is x m. And side of smaller square is y m. According to given condition, x² + y²=260...(1) And 4x–4y=24 ⇒4(x–y)=24 ⇒x–y=6 ⇒x=6+y...(2) Putting values of (2)and (1) ⇒(6+y)2+y²=260 ⇒36+y²+12y+y²=260 ⇒2y²+12y–224=0 ⇒y²+6y–112=0 ⇒y²+14y–5y–112=0 ⇒y(y+14)–8(y+14)=0 ⇒(y–8)(y+14)=0 ⇒y–8=0,y+14=0 ⇒y=8, y=–14 Putting the values of y in(1) ⇒x=6+y =6+8=14 Hence, sides of squares are 14 m and 8m.
  • 1 answers

Akshit Kaktwan 4 years, 5 months ago

If a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio
  • 5 answers

Goon Singhal 4 years, 5 months ago

101.2

Sayyaparaju Sahithi 4 years, 5 months ago

225×45÷100

Suraj Gupta 4 years, 5 months ago

101.25

Divyanka Kirola 4 years, 5 months ago

225*45/100

Aman Gupta 4 years, 5 months ago

101.25 bro
  • 5 answers

Mallika Mondal 4 years, 5 months ago

Hello

Mallika Mondal 4 years, 5 months ago

Ish mai photo kich ka question bheja nhi ja sakta

Aman Gupta 4 years, 5 months ago

??

Aman Gupta 4 years, 5 months ago

Are yrr pic walla method kyo nhi diya hai? Kitta koi likhega

Aman Gupta 4 years, 5 months ago

Hi
  • 5 answers

Ankit Kumar Yadav 4 years, 5 months ago

Google kar l9

Palak ? 4 years, 5 months ago

Right✔?➡ Ananya

Ankita Verma 4 years, 5 months ago

Curved surface area of cylinder= 2πrh Total surface area of a cylinder= 2πr(r+h)

Ananya Dogra 4 years, 5 months ago

Kyu book ni hai kya us main se dekhlo

Mallika Mondal 4 years, 5 months ago

T.S.A of a cube = 6a square
  • 1 answers

Mallika Mondal 4 years, 5 months ago

What is these question's answer
  • 1 answers

Sia ? 4 years, 5 months ago

Please ask question with complete information.

  • 1 answers

Ananya Dogra 4 years, 5 months ago

Plz send question paper latest
  • 4 answers

Aman Gupta 4 years, 5 months ago

Area=π®^2 ... Circumstance=2π®

N . 4 years, 5 months ago

Area or perimeter

Alice Badodiya 4 years, 5 months ago

How?

Manpreet Sharma 4 years, 5 months ago

Some question papers are locked please open all paper
  • 4 answers

Shivani Kumari 4 years, 5 months ago

X=3. Y=2

Aman Gupta 4 years, 5 months ago

X=3 Y=2

Somesh Smruti 4 years, 5 months ago

3X+Y=11 - X-Y=5 = 2X=6 So X=6/2=3 Put value of x and the value of Y will be 2 ..... This is done by elimination method

Atul Kushawha 4 years, 5 months ago

You can do it by elimination method Let X+Y=5 be 1st eqn. And 3X+Y=11 be 2nd eqn. Subtract eqn. 2 from 1 This became 2X=6 X=3 Put value of X in eqn.1 Y=2

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