No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 2 answers

Payal Kansyakar 4 years, 5 months ago

Let the possible root 3+root5 are rational in the form of p by q and q not equal to 0 Root 3+root5=p/q

Kanishka Sree Muthusamy 4 years, 5 months ago

Let as assume on contrary that : √3 + √5  is a rational number.  Then there exists co - prime integers p and q such that   ⇒  √3 is a rational number .  But this contradicts the fact that √3  is  irrational. So, our assumption is wrong. Hence, √3  + √5  is  irrational.
  • 2 answers

Denish Kotia 4 years, 6 months ago

Using Euclid's Division Lemma a=bq+r Where, 0<_ r<b a=72, b=13 72=13×5+7 a=13, b=7 13=7×1+6 a=7, b=6 7=6×1+1 a=6, b=1 6=1×6+0 Therefore, HCF of 72 and 13 is 1.

Shashank Sivaram 4 years, 6 months ago

The HCF (72, 13) by Euclid's algorithm/theorem is: a = bq + r (0<_r<b) 72 = 13 x 5 + 7 (a = 72, b = 13) 13 = 7 x 1 + 6 (a = 13, b = 7) 7 = 6 x 1 + 1 (a = 7, b = 6) 6 = 1 x 6 + 0 (a = 6, b = 1) So, HCF (72, 13) is 1.
  • 2 answers

Yash Phougat 4 years, 6 months ago

No...

Shashank Baghel 4 years, 6 months ago

No because 6^n= (2^n*3^n) hence there are exist no pair of 2^n*5^n factors.
  • 1 answers

Ritika Ritika 4 years, 6 months ago

Very good,that can be an example for others
  • 1 answers

Sia ? 4 years, 6 months ago

Please ask question with complete information.

  • 2 answers

Mahira Srivastava 4 years, 6 months ago

Here is the sol : 1. Sum of the zeroes -1+7=6 2. Product of zeroes -1×7=-7 So the formula is , X² - (sum of zeroes)x + product of zeroes So the answer is X²-6x-7

Payal Rajawat 4 years, 6 months ago

Alpha = -b/a = -1 Beta = c/a = 7 Quadratic polynomial. = x^2 + x + 7
  • 1 answers

Sia ? 4 years, 6 months ago

Step 1: Draw segment AB of length 7.6 cm using a ruler.
Step 2: Draw a ray AC having an acute angle with line AB.
Step 3: Mark 13 equidistant points on ray AC, A1​,A2​,A3​,...,A13​
Step 4: Join A13​ to B
Step 5: Draw A5​P parallel to A13​B.
Point P divides AB in the ratio 5:8. Measuring the lengths, we get AP=2.9 cm and PB=4.7 cm.

  • 2 answers

Yogita Mina 4 years, 6 months ago

4 zeros

Lakshay Sharma 4 years, 6 months ago

We know that √2 and -√2 are the zeroes of p(x) Therefore ...... (x - √2) and (x + √2) are the factors of p(x) It means product of factor also a factor = X² - 2 = g(x) Devide p(x) by g(x) We Get - q(x) = 2x² - 3x +1 By using slitting the middle term method ------ q(x) = 2x² - 3x + 1 = 0 = 2x² - 2x -x + 1 = 0 = 2x( x -1) -1 (x-1) = 0 = (2x-1) (x-1) = 0 Other two zeroes are ----- i) (2x-1) =0 = x = ½ ii) (x-1) = 0 x = 1 Hope its help you .........
  • 1 answers

Muskan Singh 4 years, 6 months ago

Gfgfd
  • 1 answers

Mahira Srivastava 4 years, 6 months ago

( Root 2x + 3 ) ( 2root2x-1) = 0
  • 2 answers

Krishnakumar Lavanya 4 years, 6 months ago

Answer: 72

Sia ? 4 years, 6 months ago

1008 = 2*2*2*2*3*3*7
1080=2*2*2*3*3*3*5
hcf is common factors of both the numbers
hcf(1008,1080) = 2*2*2*3*3=72

  • 3 answers

Shubh Madheshiya 4 years, 6 months ago

-३

Vijay N 4 years, 6 months ago

-3

Sandesh Singh 4 years, 6 months ago

-3
  • 3 answers

V. Parthasarathi Vasudevan 4 years, 6 months ago

5.

Yuvraj Singh 4 years, 6 months ago

Gffjk?

Shubh Madheshiya 4 years, 6 months ago

745=225×3+70 225=70*3+15 70=15*4+10 15=10*1+5 10=5*2+0 5is HCF of 225and725
  • 1 answers

Shubh Madheshiya 4 years, 6 months ago

CosA=√1-4/9 =√5/9
  • 2 answers

Laxminarayan Bainsla 4 years, 6 months ago

Hello From where are you

Laxminarayan Bainsla 4 years, 6 months ago

First find alpha and beta. By the formula which is . Alpha =-b+√b^2-4ac/2a. And for beta =-b-√b^2-4ac/2ac Then put the value of alpha and beta in your question
  • 0 answers
  • 0 answers
  • 1 answers

Adithya Dev A 4 years, 6 months ago

s = 2/3 - 1/4 = 8 - 3/12 = 5/12.// p = 2/3 * -1/4 = -2/12.// Therefore, p(x) = k (x^2 - sx + p) = k (x^2 - 5/12 x - 2/12) = k (12x^2 - 5x - 2).// According to the relation between zeroes and coefficients in quadratic polynomial, s = -b/a. 5/12 = -(-5)/12 = 5/12// p = c/a. -2/12 = -(2)/12 = -2/12//
  • 3 answers

Amrit Raj 4 years, 6 months ago

Let the quadratic polynomial be =ax²+bx+c also, $ and & are zeroes of given polynomial so, Since, $+&=-b/a =) √2+1+1/√2+1=-b/a =) 2√2=-b/a also, $•&=c/a =) √2+1×1/√2+1=c/a =) 1 =c/a So we get a=1 b=-2√2 C=1 Hence the required polynomial is X²-2√2x+1=0 ans.

Adithya Dev A 4 years, 6 months ago

S = √2 + 1. P = 1/√2 + 1. Therefore, polynomial p(x) = k (x^2 - Sx + P) = k (x^2 - (√2 + 1)x + 1/√2 + 1 = k [(√2 + 1) x^2 - (3 + 2√2) x + 1]//

Sia ? 4 years, 6 months ago

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App