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  • 1 answers

Preeti Dabral 4 years, 4 months ago

On a graph paper, draw a horizontal line XOX' and a vertical line YOY' as the x-axis and they-axis respectively.
{tex}3x + y - 11 = 0{/tex} {tex}\Rightarrow{/tex}{tex}y = (11 -3x){/tex}. ...(i)
Putting {tex}x = 2{/tex} in (i), we get {tex}y = 5{/tex}.
Putting {tex}x = 3{/tex} in (i), we get {tex}y = 2{/tex}.
Putting {tex}x = 5{/tex} in (i), we get {tex}y = -4{/tex}.

x 2 3 5
y 5 2 -4

On the graph paper, plot the points {tex}A (2, 5), B(3, 2)\ and\ C(5, -4).{/tex}
Join AB and BC to get the graph line ABC.
Thus, the line ABC is the graph of the equation {tex}3x + y - 11 = 0{/tex}.
{tex}x - y - 1 = 0{/tex} {tex}\Rightarrow{/tex}{tex}y = (x - 1){/tex} . ...(ii)
Putting {tex}x = -3{/tex} in (ii), we get {tex}y = -4{/tex}.
Putting {tex}x = 0{/tex} in (ii), we get {tex}y = -1{/tex}.
Putting {tex}x = 3{/tex} in (ii), we get {tex}y = 2{/tex}.

x -3 0 3
y -4 -1 2

On the same graph paper as above, plot the points {tex}P(-3, -4)\ and\ Q(0, -1){/tex}. The third point {tex}B(3,2){/tex} is already plotted.
Join PQ and QB to get the graph line PQB.
Thus, line PQB is the graph of the equation {tex}x - y - 1 = 0{/tex}.
The two graph lines intersect at the point {tex}B(3,2){/tex}. {tex}x = 3, y = 2{/tex} is the solution of the given system of equations.
The region bounded by these lines and the y-axis has been shaded.


On extending the graph lines on both sides, we find that these graph lines intersect the y-axis at the points Q(0, -1) and R(0,11).

  • 2 answers

Preeti Dabral 4 years, 4 months ago

<section> </section>

Aditya Anand 4 years, 4 months ago

Good
  • 3 answers

Armaan Armaan 4 years, 4 months ago

3

Aditya Anand 4 years, 4 months ago

3

Asmit Jha 4 years, 4 months ago

Threee
  • 1 answers

Preeti Dabral 4 years, 4 months ago

7429 is expressed as 17 × 19 × 23 as a product of its prime factors. Let's prime factorise the number 7429 to find its prime factors. Thus, 7429 is expressed as 17 × 19 × 23 as a product of its prime factors.

  • 0 answers
  • 2 answers

Shiva Devotee 4 years, 4 months ago

If x and y are complementry angle then x+y=90

Bhavya Rajput 4 years, 4 months ago

X+Y=90° Is x+y is complementary angles Therefore, x+y=90°(while adding complementary angles we must get 90°)
  • 2 answers

Bhavya Rajput 4 years, 4 months ago

abx2−(a2+b2)x+ab=0 x=−b±b2−4ac​​/2a x=−(−a2−b2)±(−a2−b2)2−4abab​​/2ab x=b/a​ , a/b​

Akash Yadav 4 years, 4 months ago

X=a/b, b/a
  • 1 answers

Akash Yadav 4 years, 4 months ago

(6,20)
  • 1 answers

Devan Nandan 4 years, 4 months ago

123tgdu
  • 1 answers

Keerthivasan Pb 4 years, 4 months ago

step-1:By substituting 1 in the equation we get a=-8 Step-2:By using quadratic formula and substituting the values:a=-8,b=5,c=3 We get the roots 1 and -3/8
  • 1 answers

Gpulla Array 4 years, 4 months ago

i dont see no other multiple choice questions
  • 1 answers

Jhansi Naga Sri 4 years, 4 months ago

Alpha+ Beta =1/4 Alpha×Beta=-1/8 P(x) = x^2-(Alpha+Beta)x+Alpha×Beta=0 x^2-(1/4+ -1/8)x + 1/4× -1/8=0 x^2-1/8x + -1/32=0 32x^2-4x-1/32=0 32x^2-4x-1=0 4(8x^2-x-1) =0 8x^2-x-1=0 So, 8x^2- x- 1 is the required quadratic equation
  • 1 answers

Swaroop Karoshi 4 years, 4 months ago

It is not irrational if we add 3+2 we get 5 so 5 is rational
  • 0 answers
  • 5 answers

Swaroop Karoshi 4 years, 4 months ago

1200+1200+12=2412

V A N S H 4 years, 4 months ago

2412

Dhruv Singh 4 years, 4 months ago

2412

Dali Sahu 4 years, 4 months ago

2412

Janvi Verma 4 years, 4 months ago

No sorry this is the right Ques. 12000+1200+12
  • 4 answers

Shiva Devotee 4 years, 4 months ago

100

Arya Anand 4 years, 4 months ago

100

Dali Sahu 4 years, 4 months ago

100

Janvi Verma 4 years, 4 months ago

100
  • 0 answers
  • 0 answers
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