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Let the numbers be x n y According to the question, X+ Y = 27 X= 27-Y.........(1) Again XY = 182 Putiing the value of equation (1) Y ( 27- Y) = 182 27Y - Y ^2= 182 - Y^2 + 27Y - 182 = 0 - ( Y^2 - 27Y + 182 ) = 0 Solving this we will get X= 13 n Y = 14

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Jitender Shaw 7 years, 9 months ago

Let the number be x and y. :. x + y = 27 x = 27 - y Putting the value of x in another equation. xy = 27 (27 - y) y = 182 27y - y × y = 182 y × y - 27 y + 182 = 0 y × y - 13y - 14y + 182 = 0 y( y - 13) - 14(y - 13) = 0 (y - 14) (y - 13) = 0 :: y - 14 = 0. y - 13 = 0 y = 14. y = 13 :. The two numbers are 14 and 13.

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Palak Dhingra 7 years, 9 months ago

13,14

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Shanaya Dabas 7 years, 9 months ago

13 and 14

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The line segment joining the points A(2,1) B(5,-8) is trisected at the points P and Q such that P is nearer to A. If P also lie's on line give by 2z-y+k=0 find the value of K

Posted by Farheen Saifi 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Mayank Bhunia 7 years, 9 months ago

Find the value of p then put it in the given equation

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The ratio of the sums of first m and n terms of an AP is m square : n square . Solve the the ratios of mth and nth is (2m-1):(2n-1)

Posted by Ujjwal Kesharwani 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Nancy Rajput 7 years, 9 months ago

It's too long sum

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Find the coordinates of point on y-axis which is nearest to the point(-2,5)

Posted by Priyansh Singh 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Cutiee Princess 7 years, 9 months ago

X= 0 Y = 5

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Xsquare+x-p(p+1) find the roots

Posted by Arman Chugh 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Cutiee Princess 7 years, 9 months ago

X^2 + X - P^2 +P Put the value - b+-√b^2- 4ac \ 2a Take a = 1 b= 1 N c= p^2+ p

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let d be the HCF of 24 and 36 dind two number a and b such that d is equal to 24a add 36b

Posted by Saksham Agarwal 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Satyam Anand 7 years, 9 months ago

a=1 and b= -1

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Aayush Patel 7 years, 9 months ago

A=-1&b=1

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Prove that root2 is rational

Posted by Thara Binu 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Let us find the square root of 2 by long division method as shown below:

{tex}\Rightarrow{/tex} {tex}\sqrt{2}{/tex} = 1.4142135.
Clearly, the decimal representation of{tex}\sqrt{2}{/tex} is neither terminating nor repeating. Hence, it is not a rational number.

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4+8(-5)-(-5)+3(5)-3+5(1)2=?

Posted by Gaurav Rawat 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Nishant Verma 7 years, 9 months ago

-9

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Nancy Rajput 7 years, 9 months ago

1Thank You

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If two eqilateral triangle are similar prove that they are congruent

Posted by Anurag Mishra 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Given :
ar {tex}\triangle \mathrm{ABC}{/tex} = ar {tex}\Delta \mathrm{PQR}{/tex}
{tex}{/tex}To prove: {tex}\triangle \mathrm{ABC} \cong \triangle \mathrm{PQR}{/tex}
Since,
ar {tex}\triangle A B C=\text { ar } \triangle P Q R{/tex} (given)
{tex}\frac{{\Delta ABC}}{{ar\Delta PQR}} = 1{/tex}
{tex}\Rightarrow{/tex} {tex}\frac{{A{B^2}}}{{P{Q^2}}} = \frac{{B{C^2}}}{{Q{R^2}}} = \frac{{C{A^2}}}{{P{R^2}}} = 1{/tex}
[Using Theorem of area of similar Triangles]
{tex}\Rightarrow{/tex} AB = PQ, BC = QR & CA = PR
Thus, {tex}\triangle \mathrm{ABC} \cong \triangle \mathrm{PQR}{/tex}

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Find the 7th term from the end of the ap 7,10,13,.......184

Posted by Vishwajeet Anand 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Rudra Bhardwaj 7 years, 9 months ago

We have, a = 7, d = 3, an = 184, n = ? Formula an=a+(n-1)d 184=7+(n-1)3 184-7=(n-1)3 177/3=(n-1) 59=(n-1) n=59+1 n=60 According to the question, We have= a=7, d=3, n=7th, Formula an=a+(n-1)d an=7+(7-1)3 an=7+(6)3 an=7+18 an=25

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Nancy Rajput 7 years, 9 months ago

166

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If two equilateral triangle are similar prove that they are congruent

Posted by Anurag Mishra 7 years, 9 months ago

CBSE > Class 10 > Mathematics