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Ask QuestionPosted by Sunita Rajput 4 years, 4 months ago
- 1 answers
Posted by Stuti Singla 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
(5x/100)+(10y/100)=200
=> 5x+10y=20000
=> x+2y=4000 -(1)
x+y=2800 -(2)
=> 0+y=1200 (on substraction)
x=2800-1200=1600
Therefore, no. of boys= 1600
and no. of girls = 1200.
Posted by Soumya Vashishtha 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
Let the fixed charge be Rs x and
The charges for per km be Rs y
Therefore
x + 12 y = 89 ......... eqn 1
And
x + 20 y = 145 ........eqn 2
1 - 2
x + 12 y - x - 20 y = 89 - 145
8 y = 56
y = 7
Therefore x + 20 (7) = 145
x + 140 = 145
x = 5
Now , for 30 km
x + 30 y = 5 + 30 * 7
= 5 + 210
= 215
Posted by Krish Bansal 4 years, 4 months ago
- 1 answers
Dhana Lakshmi S 4 years, 4 months ago
Posted by Manish Yadav 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
The maximum no. of marbles a packet can hold would be the HCF of the nos. i.e. 30
Posted by Akanksha Kumari 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
Factorizing the denominator, we get,
8 = 2×2×2 = 23
Since, the denominator has only 2 as its factor, 17/8 has a terminating decimal expansion.
Posted by Prashant Ambani 4 years, 4 months ago
- 0 answers
Posted by Khushi Tanwar 4 years, 4 months ago
- 1 answers
Preeti Dabral 4 years, 4 months ago
Step-by-step explanation:
Solution :-
Let the tens place digit be x.
And the units place digit be y.
According to the Question,
⇒ xy = 18
⇒ y = 18/x .....(i)
And, (10x + y) - 63 = 10y + x
⇒ 9x - 9y = 63
⇒ x - y = 7 .... (ii)
Putting y's value in Eq (ii), we get
⇒ x - 18/x = 7
⇒ x² - 18 = 7x
⇒ x² - 7x - 18 = 0
⇒ x² - 9x + 2x - 18 = 0
⇒x(x - 9) + 2(x - 9) = 0
⇒ (x - 9) (x + 2) = 0
⇒ x - 9 = 0 or x + 2 = 0
⇒ x = 9, - 2 (As x can't be negative)
⇒ x = 9
Putting x's value in Eq (i), we get
⇒ xy = 18
⇒ 9y = 18
⇒ y = 18/9
⇒ y = 2
Number = 92
Hence, the required number is 92.
Posted by Anjali Nanda 4 years, 4 months ago
- 2 answers
Swati Chaudhary 4 years, 4 months ago
Posted by Sarita Panda 4 years, 4 months ago
- 1 answers
Preeti Dabral 4 years, 4 months ago
By Euclid’s division algorithm,
HCF of 468 and 222 is
468 = (222 x 2) + 24 ----------------------(1)
222 = (24 x 9) + 6 ------------------------(2)
24 = (6 x 4) + 0
So the HCF of 468 and 222 is 6.
Now we have to write 6 as 468x + 222y
6 = 222 - (24 x 9) --------------- [ from (2) ]
Now write 24 as (468 – 222 x 2) -------------- [ from (1) ]
⇒ 6 = 222 - {(468 – 222 x 2) x 9
= 222 - {468 x 9 – 222 x 2 x 9}
= 222 - (468 x 9) + (222 x 18)
= 222 + (222 x 18) - (468 x 9)
= 222[1 + 18] – 468 x 9
= 222 x 19 – 468 x 9
= 468 x -9 + 222 x 19
So HCF of 468 and 222 is (468 x -9 + 222 x 19) in the form 468x + 222y.
Posted by Stuti Singla 4 years, 4 months ago
- 0 answers
Posted by Vivek Rana 4 years, 4 months ago
- 3 answers
Posted by A.P.Daiwik Daiwik 4 years, 4 months ago
- 3 answers
Posted by Queeen? Queen Queen 4 years, 4 months ago
- 2 answers
Posted by Ritik Varshney 4 years, 4 months ago
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Posted by Novah Shaji 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
Given A = 2n + 13 and B = n + 7 and since n is a natural number A > B.
A = 2(n + 7) - 1
A = 2B - 1
On dividing throughout with B,
A/B = 2 - (1/B)
B is always an integer => 1/B can never be an integer => A/B also can't be an integer
Since A/B is not an integer we can conclude that A and B cannot have any integer in common. Therefore HCF of A and B is 1.
Posted by Sunil Kumar 4 years, 4 months ago
- 1 answers
Posted by Krish Kadia 4 years, 4 months ago
- 1 answers
Sia ? 4 years, 4 months ago
So, first term = a = 3
Common difference = d = 3
Last term = Tn = 111
Let number of terms be n.
Now, Tn = a + (n-1)d
So, 111 = 3 + (n-1)×3
So, 108 = 3×(n-1)
So, 108/3 = n-1
So, n-1 = 36
So, n = 37
Thus, number if terms is 37.
Posted by Anamika Singh 4 years, 4 months ago
- 0 answers
Posted by Muskaan Fayaz 4 years, 4 months ago
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Posted by Aparna Sharma 4 years, 4 months ago
- 1 answers
Posted by Aadiii Verma 4 years, 4 months ago
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Shubhi Sharma 4 years, 4 months ago
Posted by Anjali Sisodiya 4 years, 4 months ago
- 1 answers
Posted by Shivam Prajapati 4 years, 4 months ago
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Posted by Ishika Taneja 4 years, 4 months ago
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Posted by Deivalakshmi.C Deivalakshmi.C 4 years, 4 months ago
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Sia ? 4 years, 4 months ago
Posted by Sathika Loganathan 4 years, 4 months ago
- 2 answers
Diya Udeesh 4 years, 4 months ago
Venkid Varma 4 years, 4 months ago
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Rahul Jagrat 4 years, 4 months ago
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