CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

We have, {tex}2x - y - 2 = 0{/tex} or {tex}x = {{y+2}\over2} {/tex}
When y = 0, we have {tex}x = {{0+2}\over2} = 1{/tex}
When x = 0, we have y = -2.
Thus, we obtain the following table giving coordinates of two point on the line represented by the equation {tex}2x - y - 2 = 0{/tex} and its graph is shown below.

x	1	0
y	0	-2

Now we have, {tex}\begin{array}{l}4x+3y-24=0\Rightarrow y=\frac{24-4x}3\\\end{array}{/tex}
When y = 0, we have x = 6
When x = 0, we have y = 8
Thus, we obtain the following table giving coordinates of two points on the line represented by the equation {tex}4x + 3y - 24 = 0{/tex} and its graph is shown below.

x	6	0
y	0	8

Also we have {tex}y + 4 = 0{/tex}
Clearly, y = - 4 for every value of x.
So, let E(2, -4) and F(0, -4) be two points on the line represented by y + 4 = 0. Plotting these points on the same graph and drawing a line passing through them, we obtain the graph of the line represented by the equation y + 4 = 0 as shown in Figure.

From Fig. we have {tex}\begin{array}{l}\bigtriangleup PQR\\\end{array}{/tex} having vertices P(3,4), Q(-1,-4) and R(9, -4).

Also, PM = 8 and QR = 10.
{tex}\therefore \quad \text { Area of } \triangle P Q R = \frac { 1 } { 2 } ( \text { Base } \times \text { Height } ){/tex}
{tex}\Rightarrow \quad \text { Area of } \triangle P Q R = \frac { 1 } { 2 } ( Q R \times P M ) = \frac { 1 } { 2 } ( 10 \times 8 )sq.\ units{/tex}
{tex}\Rightarrow \quad \text { Area of } \triangle P Q R = 40 \mathrm { sq } .units.{/tex}

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Suno aagr ch 14 me ogive or missing frequency me choice aaye to kon sa kro ge

Posted by Divanshi Singla 7 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Divanshi Singla 7 years, 8 months ago

Why ogive

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????Shubham Sihag?????? 7 years, 8 months ago

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????Shubham Sihag?????? 7 years, 8 months ago

Ogive

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Bhoomika Chadha 7 years, 8 months ago

Ogive

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All formuls of ch areas related to circles

Posted by Avnik Kaur 7 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

????Shubham Sihag?????? 7 years, 8 months ago

Issi app me revision notes me given hai sare formule

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Astha Kumari 7 years, 8 months ago

Find in your book

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Find the series of the polynomial t square -15 and verify the relationship between them

Posted by Subi Varsha 7 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Keshav Bindal 7 years, 8 months ago

Verification:- Sum=√15+(-√15)=0=-b/a. Product=√15(-√15)=-15=c/a

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Keshav Bindal 7 years, 8 months ago

Not series, zeroes. t^2 - 15 = t^2 - √15 = (t + √15)(t - √15) = t=√15 or -√15

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Three consecutive positive integer are such that the sum of the square of the first and product of the other two is 46 find the integers

Posted by Vikas Jadrmakunti 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let the integers be x, x + 1 and x + 2. Then,
x² + (x + 1)(x + 2) = 46
{tex}\Rightarrow{/tex} x² + (x² + 2x + 1x + 2) = 46
{tex}\Rightarrow{/tex} 2x² + 3x + 2 = 46
{tex}\Rightarrow{/tex} 2x² + 3x + 2 - 46 = 0
{tex}\Rightarrow{/tex} 2x² + 3x - 44 = 0
{tex}\Rightarrow{/tex} 2x² + 11x - 8x - 44 = 0
{tex}\Rightarrow{/tex} x(2x + 11) - 4(2x + 11) = 0
{tex}\Rightarrow{/tex} (x - 4)(2x + 11) = 0
{tex}\Rightarrow{/tex} x - 4 = 0 [{tex}\because{/tex} x is an integer {tex}\therefore{/tex} 2x + 11 {tex}\ne{/tex} 0]
{tex}\Rightarrow{/tex} x = 4
{tex}\therefore{/tex} x + 1 = 4 + 1 = 5
And, x + 2 = 4 + 2 = 6
Hence, required numbers are 4, 5 and 6.

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1÷2a + 2x = 1÷2a + 1÷b + 1÷2x find x value

Posted by M Raja Gana Reddy Rukumini 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

{tex}\frac{1}{2a + b + 2x}{/tex} = {tex}\frac{1}{2a}{/tex} + {tex}\frac{1}{b}{/tex} + {tex}\frac{1}{2x}{/tex}

{tex}\Rightarrow{/tex} {tex}\frac{1}{2a + b + 2x}{/tex} - {tex}\frac{1}{2x}{/tex} = {tex}\frac{1}{2a}{/tex} + {tex}\frac{1}{b}{/tex}
{tex}\Rightarrow{/tex}{tex}\frac { 2 x - 2 a - b - 2 x } { ( 2 a + b + 2 x ) ( 2 x ) }{/tex} = {tex}\frac{b + 2a}{2a \times b}{/tex}

{tex}\Rightarrow{/tex} {tex}\frac { - ( 2 a + b ) } { ( 2 a + b + 2 x ) 2 x }{/tex} = {tex}\frac{b + 2a}{2ab}{/tex}
{tex}\Rightarrow{/tex}{tex}\frac { - 1 } { 4 a x + 2 b x + 4 x ^ { 2 } }{/tex} = {tex}\frac{1}{2ab}{/tex}

{tex}\Rightarrow{/tex} {tex}4x^2 + 2bx + 4ax = -2ab{/tex}
{tex}\Rightarrow{/tex} {tex}4x^2 + 2bx + 4ax + 2ab = 0{/tex}

{tex}\Rightarrow{/tex} {tex}2x(2x + b) + 2a(2x + b) = 0{/tex}
{tex}\Rightarrow{/tex} (2x + b)(2x + 2a) = 0

{tex}\Rightarrow{/tex} x = -{tex}\frac{b}{2}{/tex} or x = -a

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Q. A sum of Rs.280 is to be used to award four prizes.If each prize after the first is Rs.20 less than its preceding prize,find the value of each of the prizes.

Posted by Aryan Yadav 7 years, 8 months ago

CBSE > Class 10 > Mathematics