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  • 2 answers

Chandra Kumar 7 years, 8 months ago

Sure

Mr Lovely 7 years, 8 months ago

Ok
  • 1 answers

Ifra Taskeen 7 years, 8 months ago

a=1... b=1..... By distance formula v have to find the length..
  • 0 answers
  • 8 answers

Jio Vs Airtal 7 years, 8 months ago

√x²+y²

Prakhar Khatri 7 years, 8 months ago

Origin(0,0) Therefore D = x+y

Vedika Singh 7 years, 8 months ago

How can it be (0,0)???

Ifra Taskeen 7 years, 8 months ago

(0,0)

Vedika Singh 7 years, 8 months ago

√(x2-x1)square +(y2-y1)sqaure

Vedika Singh 7 years, 8 months ago

Under root in bracket x2 square minus x1 square bracket close plus y2 square minus y1 square...

Darshanaa Yadav 7 years, 8 months ago

Under root x²+y²

Manish Rajak 7 years, 8 months ago

Find the distance of a point p(x,y)from the origin
  • 3 answers

Nikhil Kaushik 7 years, 8 months ago

26 April May be according to news

Vedika Singh 7 years, 8 months ago

It will be in a week

Vicky H 7 years, 8 months ago

I guess it's not yet confirmed
  • 2 answers

Zehra Mustafa 7 years, 8 months ago

23april date to ek afwah h

Raushan Kumar Kumar 7 years, 8 months ago

23 april
  • 1 answers

Vicky H 7 years, 8 months ago

Whole root of (x2-x1)sq + (y2-y1)sq
  • 3 answers

Vedika Singh 7 years, 8 months ago

Stepwise ans........

Vedika Singh 7 years, 8 months ago

Can u giva a stepwise ans....pls...

Sachin Dhami 7 years, 8 months ago

Terms are 2,6,10,14 Common difference is 4
  • 1 answers

Sia ? 6 years, 6 months ago


Area of a circle with DO as diameter {tex}= \pi r ^ { 2 } {/tex} sq. cm
{tex}= \frac { 22 } { 7 } \times \frac { 7 } { 2 } \times \frac { 7 } { 2 }{/tex}
{tex} = \frac { 77 } { 2 }{/tex} cm2
Area of semi-circle with AB as diameter {tex}= \frac { \pi r ^ { 2 } } { 2 } {/tex}
{tex}= \frac { 22 \times 7 \times 7 } { 7 \times 2 } {/tex}
{tex}= 77 \mathrm { sq } . \mathrm { cm }{/tex}
Area of {tex}\triangle A B C = \frac { 1 } { 2 } \times 14 \times 7 = 49 \mathrm { sq.cm }{/tex}
Area of shaded region = Area of circle + Area of semi-circle - Area of {tex}\triangle{/tex}ABC
{tex}= \frac { 77 } { 2 } + 77 - 49 {/tex}
{tex}= 38.5 + 77 - 49 {/tex}
{tex}=115.5 - 49{/tex}
{tex}= 66.5 \mathrm { sq.cm }{/tex}.

  • 0 answers
  • 3 answers

Tanu Kaur 7 years, 8 months ago

The date will declare on this Monday or Tuesday

Tanu Kaur 7 years, 8 months ago

Yet not declared by cbse

Amit Kumar 7 years, 8 months ago

Dont know
  • 1 answers

Abhinav Biradar 7 years, 8 months ago

Really
  • 1 answers

Tanu Kaur 7 years, 8 months ago

1=HCF
  • 2 answers

Chandra Kumar 7 years, 8 months ago

90 per cent question will be ask from ncert

Raj Kumar 7 years, 8 months ago

No yai jaruri nahi hai ncert kafi hai
  • 1 answers

Tanu Kaur 7 years, 8 months ago

994.98743711
  • 4 answers

Chandra Kumar 7 years, 8 months ago

The date will be declare in within a week. Don't worry just focus on studies

Aman Yadav 7 years, 8 months ago

abhi nhi bataya

Someone Unknowngirl 7 years, 8 months ago

News channels are not showing anything about dates

Riya Yadav 7 years, 8 months ago

26 april yrr
  • 0 answers
  • 0 answers
  • 0 answers
  • 0 answers
  • 3 answers

Riya Rawat 7 years, 8 months ago

0

Muktinath Pandey 7 years, 8 months ago

0

Sahil Kumar 7 years, 8 months ago

0
  • 8 answers

Bhanavi Saini 7 years, 8 months ago

Are you SURE???

Nikhil Kaushik 7 years, 8 months ago

26 April

Someone Unknowngirl 7 years, 8 months ago

26 i may think also but news and website of cbse r not showing anything about dates they r only showing about the news of reconduct

Tanu Kaur 7 years, 8 months ago

R u sure

Riya Rawat 7 years, 8 months ago

The correct date is 26th April

Muktinath Pandey 7 years, 8 months ago

Right mahak

Mahak Singh 7 years, 8 months ago

26 april

Gayatri Singh 7 years, 8 months ago

No one knows the correct date .

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