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  • 1 answers

Jyotica Bisht 7 years, 8 months ago

By using Euclid's division lemma a=bq+r where 0<=r136 170 =136×1+34 136 =34×4+0 So, HCF of 136 & 170 is 34 Now,255 and 34 255 >34 255=34×7+17 34=17×2+0 So,HCF of 255 & 34 is 34 Therefore, HCF of 136,170 and 255 is 34
  • 4 answers

Satyam Kumar 7 years, 8 months ago

Combination of all rational and irational number is known as real number.

Vikram Singh 7 years, 8 months ago

Numbers whose square are positive and it can be expressed in number line are called real numbers

Likhitha Dinttakurthy 7 years, 8 months ago

Collection of all kinds of numbers. Eg. Natural number , whole number etc

Xavier Hembrom 7 years, 8 months ago

Collection rational and irrational numbers
  • 1 answers

Abhijit Gorai 7 years, 8 months ago

I think both
a9
  • 0 answers
  • 1 answers

Ankit Sharma 7 years, 8 months ago

Me
  • 1 answers

Vikram Singh 7 years, 8 months ago

In Reality i dont know bt i beleive it would be clear after summer vacations :)
  • 0 answers
  • 2 answers

Demon King 7 years, 8 months ago

Ok all the best tum sab Ko ache se parna

Demon King 7 years, 8 months ago

Koi nhi
  • 0 answers
  • 3 answers

Anupam Garg 7 years, 8 months ago

2×22/7×r

Monisha Ishu 7 years, 8 months ago

22÷7

Abdan Ali 7 years, 8 months ago

22_7
  • 0 answers
  • 4 answers

Ash Ketchup 7 years, 8 months ago

Least common multiple

Alok Kumar 7 years, 8 months ago

Least common multiple

Abhishek Reddy 7 years, 8 months ago

Least common multiple

Parthiv Pandey 7 years, 8 months ago

Lowest common multiple
  • 1 answers

Parthiv Pandey 7 years, 8 months ago

1
  • 0 answers
  • 0 answers
  • 1 answers

Ridhima Mittal 7 years, 8 months ago

इंग्लिश
  • 1 answers

Anupam Garg 7 years, 8 months ago

LCM×HCF=sum of two numbers
  • 0 answers
  • 1 answers

Dipanshi Kataria 7 years, 8 months ago

It's highest common factor
  • 1 answers

Abhishek Mishra 7 years, 8 months ago

It is released now U can see it on www.cbse.nic.in
  • 0 answers
  • 1 answers

Sia ? 6 years, 5 months ago

Here, a = 5
l = 45
S = 400
We know that
{tex}S = \frac{n}{2}(a + l){/tex}
{tex} \Rightarrow 400 = \frac{n}{2}(5 + 45){/tex}
{tex} \Rightarrow 400 = \frac{n}{2}(50){/tex}
{tex} \Rightarrow 400 - 25n{/tex}
{tex} \Rightarrow n = \frac{{400}}{{25}}{/tex}
{tex} \Rightarrow n = 16{/tex}
Hence, the number of terms is 16.
Again, we know that
l = a + (n - 1)d
{tex} \Rightarrow {/tex} 45 = 5 + (16 - 1)d
{tex} \Rightarrow {/tex} 45 = 5 + 15d
{tex} \Rightarrow {/tex} 40 = 15 d
{tex} \Rightarrow d = \frac{{40}}{{15}} = \frac{8}{3}{/tex}
Hence, the common difference is {tex}\frac{8}{3}{/tex}.

  • 0 answers

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