CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Ask questions which are clear, concise and easy to understand.

Ask Question

B+cx= c

Posted by Rohit Borana Borana 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

2x=3y=12z Then prove that 2(x+2y)/xy

Posted by Yashraj Yadav 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

,show that 38 and 45 are prime numbers

Posted by Krishna Gupta 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Kumar 7 years, 5 months ago

38 is divisible by 2 and 45 is divisible by 5 that's why it is not prime no.

1Thank You

ANSWER

If two positive integers p and q are written as p = a²b³ and q = a³b ; a, b are prime numbers, then verify : LCM(p, q) *HCF(p, q).

Posted by Aarti Kushwah 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

LCM(p,q) = a³b³
and HCF(p,q) = a²b
LCM(p,q) {tex}\times{/tex} HCF(p,q) = a³b³ {tex}\times{/tex} a²b

{tex}\begin{array}{l}\mathrm{LCM}(\mathrm p,\mathrm q)\;\times\mathrm{HCF}(\mathrm p,\mathrm q)\;=\mathrm a^5\mathrm b^4\;-----(1)\\\mathrm{and}\;\mathrm{pq}=\mathrm a^2\mathrm b^3\;\times\mathrm a^3\mathrm b=\mathrm a^5\mathrm b^4\;------(2)\\\mathrm{from}\;\mathrm{eq}^\mathrm n\;(1)\;\mathrm{and}\;(2)\\\mathrm{LCM}(\mathrm p,\mathrm q)\;\times\mathrm{HCF}(\mathrm p,\mathrm q)\;\;=\mathrm{pq}\\\\\end{array}{/tex}

0Thank You

ANSWER

if we add 1 to the numerator and subtract 1 from denominator of fraction reduces to 18 dumps 1 by 2 if we only add 1 to the denominator what is the fraction?

Posted by Saloni Patidar 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which sample paper is best for study for math in 10 board

Posted by Suraj Jat 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Mahanta Bhagat 7 years, 5 months ago

NCERT

0Thank You

ANSWER

Slve for x. 1by x plus 2 by 2x_3 =1by x _ 2.

Posted by Lakshay Sharma 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

gauri spends 0.75 of her salary every month.if she earn rupees 12000 per month ,in how many months will she save rupees 39000?

Posted by Shiva Pathak 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Ranjeet Chauhan 7 years, 5 months ago

2.4375

0Thank You

ANSWER

Find the zeros of polynomial x3 - 5x2 - 2x+24 if it is given that the product of its two zeros is12

Posted by Sujal Singh 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let {tex} \alpha , \beta , \gamma{/tex} be the zeroes of polynomial f(x) = x³ - 5x² - 2x + 24 such that {tex} \alpha\beta{/tex} = 12.
{tex} \alpha + \beta + \gamma = - \left( - \frac { 5 } { 1 } \right) = 5{/tex} ................ (i)
{tex} \alpha \beta + \beta \gamma + \gamma \alpha = \frac { - 2 } { 1 } = - 2{/tex}
and, {tex} \alpha \beta \gamma = - \frac { 24 } { 1 } = - 24{/tex}
Putting, {tex} \alpha \beta = 12{/tex} in {tex} \alpha \beta \gamma = - 24{/tex}, we get
{tex} 12 \gamma = - 24{/tex}
{tex} \Rightarrow \gamma = - \frac { 24 } { 12 } = - 2{/tex}
Putting {tex} \gamma= -2{/tex} in eq.(i), we get
{tex} \alpha + \beta - 2 = 5{/tex}
{tex} \Rightarrow \quad \alpha + \beta = 7{/tex}
Now, {tex} ( \alpha - \beta ) ^ { 2 } = ( \alpha + \beta ) ^ { 2 } - 4 \alpha \beta{/tex}
{tex} \Rightarrow \quad ( \alpha - \beta ) ^ { 2 } = 7 ^ { 2 } - 4 \times 12{/tex}
{tex} \Rightarrow \quad ( \alpha - \beta ) ^ { 2 } = 1{/tex}
{tex} \Rightarrow \quad \alpha - \beta = \pm 1{/tex}
Thus, we have
{tex} \alpha + \beta= 7{/tex} and {tex} \alpha - \beta = 1 {/tex} or, {tex} \alpha + \beta= 7{/tex} and {tex} \alpha - \beta= -1{/tex}
CASE I: When {tex} \alpha + \beta= 7{/tex} and {tex} \alpha - \beta= 1{/tex}
Solving {tex} \alpha + \beta= 7{/tex} and {tex} \alpha - \beta= 1{/tex} , we get
{tex} \alpha = 4{/tex} and {tex}\beta= 3{/tex}
CASE II: When {tex} \alpha + \beta= 7{/tex} and {tex} \alpha - \beta= -1{/tex}
Solving {tex} \alpha + \beta= 7{/tex} and {tex} \alpha - \beta= -1{/tex} , we get
{tex} \alpha = 3{/tex} and {tex}\beta= 4{/tex} .
Hence, the zeros of the given polynomial are 3, 4 and - 2 or 4,3 , -2.

0Thank You

ANSWER

Hey, I couldn't find the answer to this question "Tell me how genius u r.solve this question. Q. solve for x and y. x + root y=7 and root x + y =11 . "

Posted by Saket Saurabh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The nth term of the AP is 6n+2. Find the common difference

Posted by Priya Shah 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 5 months ago

1Thank You

ANSWER

Class 10th cbse me jitne questions syllabus me rahte hai vo usi me se aata hai

Posted by Ranjeet Chauhan 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Yes, you can check the syllabus here : https://mycbseguide.com/cbse-syllabus.html

0Thank You

ANSWER

2-7

Posted by Niharika Sharma 7 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Arohi . 7 years, 5 months ago

Are you just checking does it work or you are a kid.

1Thank You

Priya Kumari 7 years, 5 months ago

-5

0Thank You

ANSWER

मैटरिक्स क्या ह

Posted by Education All Sub 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which sample paper for 10 th maths exam

Posted by Suraj Jat 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Akshata Kondi 7 years, 5 months ago

Cbse 8question paper

4Thank You

ANSWER

d/dx (x^2 sin 1/x)

Posted by P A 5 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If 2br root 3 and minus 2 by root 3 are the zeroes of the polynomial 15x4-41x2+28 then find the remaining zeroes of the polynomial

Posted by Vedish Vedish 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If p of x

Posted by Amit Mane 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The sum of two number is 9 the sum of reciprocal is 1/2

Posted by Viki Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Mr. Shashank 7 years, 5 months ago

6 & 3

1Thank You

ANSWER

Solve each of the following systems of equations by using the method of cross multiplication 3x-2y+3=0 4x+3y-47=0

Posted by Saurabh Singh Saurabh Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Mr. Shashank 7 years, 5 months ago

X=5 & Y=6

0Thank You

ANSWER

3x-2y+3 =0 4x+3y- 47=0

Posted by Saurabh Singh Saurabh Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Mr. Shashank 7 years, 5 months ago

X=5 & Y =6

0Thank You

ANSWER

Using prime factorisation method find the hcf and limits of 30,72 and432 also show that hcf*lcm is not equal to product of three numbers

Posted by Sujal Singh 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

{tex}30 = 2 \times 3 \times 5{/tex}
{tex}{72=8×9=2}^3\times3^2{/tex}
{tex}{432=16×27=2}^4\times3^3{/tex}
Therefore, HCF = 2 {tex}\times{/tex} 3 = 6
LCM {tex}= 2^4 \times 3^3 \times 5 = 2160{/tex}

0Thank You

ANSWER

Ex:3.c

Posted by Saurabh Singh Saurabh Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Anwaya Kumar Nayak 7 years, 5 months ago

Which chapter

2Thank You

ANSWER

3x square + 6x - 2 solve by compeleting square method

Posted by Yug Dangi 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Which of the following numbers are perfect squares give reasons 6241

Posted by Mohd Rizwan 7 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is the product of the three zeros of a cubic 2 x cube minus 7 x square + 8 x + 5

Posted by Manaswi Gawande 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Alpna Suthar 7 years, 5 months ago

0Thank You

ANSWER

ABC and AMP are two right triangles, right angled at B and M respectively. Prove that 1-ΔABC.~ΔAMP. 2- CA/PA = BC/MP.

Posted by Ruthi Lalawmpuii 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given: In the figure, ABC and AMP are two right triangles, right angled at B and M respectively,

To prove:

{tex}\triangle {/tex}ABC {tex} \sim {/tex} {tex}\triangle {/tex}AMP
{tex}\frac{{CA}}{{PA}} = \frac{{BC}}{{MP}}{/tex}

Proof:

In {tex}\triangle {/tex}ABC {tex} \sim {/tex} {tex}\triangle {/tex}AMP
{tex}\angle{/tex}ABC = {tex}\angle{/tex}AMP (1) ........ [Each equal to 90^o]
{tex}\angle{/tex}BAC={tex}\angle{/tex}MAP (2).........[Common angle]
In view of (1) and (2)
{tex}\triangle {/tex}ABC {tex} \sim {/tex} {tex}\triangle {/tex}AMP ..........AA similarity criterion
{tex}\triangle {/tex}ABC {tex} \sim {/tex} {tex}\triangle {/tex}AMP.........Proved above in(i)
{tex}\therefore {/tex} {tex}\frac{{CA}}{{PA}} = \frac{{BC}}{{MP}}{/tex}.........Corresponding sides of two similar triangles are proportional.

0Thank You

ANSWER

Which sample paper is best for 10 th exam

Posted by Suraj Jat 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Reddy 7 years, 5 months ago

Google

0Thank You

ANSWER

Ex-6.3-Q-10

Posted by Ruthi Lalawmpuii 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Reddy 7 years, 5 months ago

Send the correct information

1Thank You

ANSWER

Elemenation method 1) x+y = 7, 5x+ 2y = 7

Posted by Ayush Kashyap 7 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

A. Tiwari 7 years, 5 months ago

x+y=7...... (1) 5x+2y=7....... (2) ------------------------- Equation (1)×5 Equation (2)×1 {By elimination method} We'll get 5x+5y=35......... (3) 5x+2y=7...........(4) --------------------------------- [On subtracting equation 3 and 4] We'll get, 3y=28 y=28/3 On putting the value of y in equation (1) x+y=7 x+(28/3)=7 x=7-28/3 x=(-7/3)

1Thank You

Ayush Kashyap 7 years, 5 months ago

Please answer me

2Thank You

ANSWER