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  • 4 answers

Mohammad Arshil 3 years, 7 months ago

A)Given That Sm=Sn m/2{2a+(m-1)d}=n/2{2a+(n-1)d} m{2a+md-d}=n{2a+nd-d} 2ma+m^2d-md=2na+n^2d-nd 2ma-2na+m^2d-n^2d-md+nd=0 2a(m-n)+(m^2-n^2)d-(m-n)d=0 2a(m-n)+{(m+n)(m-n)}d-(m-n)d=0 Dividing By (m-n) in whole equation We get 2a+(m+n)d-d=0 2a+(m+n-1)d=0 Multiplying My m+n/2 In LHS And RHS m+n/2{2a+(m+n-1)d}=0×m+n/2 Thus Sm+n=0 Hence Proved

Chanchal Tanwar 3 years, 7 months ago

Hello

Rishab Kandwal 3 years, 7 months ago

(B) 1500

Navkaran Singh 3 years, 7 months ago

Hi
  • 0 answers
  • 3 answers

Ishant Sharma 3 years, 7 months ago

73%

Aditya Kumar 3 years, 7 months ago

98 percent

Chanchal Tanwar 3 years, 7 months ago

Don't lie
  • 2 answers

Ayushi Gupta 3 years, 7 months ago

Xi = 60, 80, 100, 120, 140, 160 sigmaFi = 180 Di (Xi-A) = -60, -40, -20, 0,20, 40 Ui (Di /h) = -3, -2, -1, 0, 1, 2, Sigma FiUi = -39 Let A be 120... Mean = A + (sigmaFiUi / sigmaFi) Mean = 120 + (-39/180) Mean = 120 - 0.217 =>*Mean = 119.783*

. . 3 years, 7 months ago

Mean = 112.2
  • 3 answers

Anurag Chaudhary 3 years, 7 months ago

5x²+8x-4=0 5x²+(10-2)x-4=0 5x²+10x-2x-4=0 5x(x+2)-2(x+2)=0 (5x-2)(x+2)=0 So, (x=⅖) & [x=(-2)]

Bhumika Goswami 3 years, 7 months ago

5x²+8x-4 5x²+(10-2)x-4 5x²+10x-2x-4 5x(x+2)-2(x+2) (x+2),(5x-2) x=-2,x=2/5

Ayushi Gupta 3 years, 7 months ago

5x2 + 8x - 4 = 0 5x2 + 10x - 2x - 4 =0 5x(x+2) -2(x+2) = 0 (5x-2) (x+2) = 0 X = -2, 2/5
  • 2 answers

Ishant Sharma 3 years, 7 months ago

First of all learn the spelling of integer!!

Bhumika Goswami 3 years, 7 months ago

A integer is defined as a no. That can written without a fractional components
  • 3 answers

Bhumika Goswami 3 years, 7 months ago

510= 2×5×3×17

Akash Biswa Akash Biswa 3 years, 7 months ago

510 =2×5×51

Ayushi Gupta 3 years, 7 months ago

510 = 2 × 3 × 17
6+2
  • 5 answers

Ayushi Gupta 3 years, 7 months ago

8

Piyush Aggarwal 3 years, 7 months ago

8

Sk Jangra 3 years, 7 months ago

8

Nisarga Nisarga 3 years, 7 months ago

8

Arohi Bharti 3 years, 7 months ago

Boliye
  • 3 answers

Navkaran Singh 3 years, 7 months ago

Good

Ayushi Gupta 3 years, 7 months ago

For AP^1 :- a = 63 d = 2 For AP^2 :- a = 3 d = 7 63 + (n-1) 2 = 3 + (n-1) 7 63 + 2n - 2 = 3 + 7n - 7 61 + 2n = -4 + 7n 61 + 4 = 7n - 2n 5n = 65 n = 13

Nisarga Nisarga 3 years, 7 months ago

AP¹:63,65,67 a=63 d=65-63=2 AP²:3,10,17 a=3 d=10-3=7 Given, An=An a+(n-1)d=a+(n-1)d 63+(n-1)2=3+(n-1)7 63+2n-2=3+7n-7 61+2n=7n-4 61+4=7n-2n 65=5n n=13
  • 1 answers

Mohit Nimje 3 years, 7 months ago

As we know 64 is the cube of 4 and 125 is the cube of 5 (64/125)^-2/3 As above statement we can write it as :- (4/5)^(3)(-2/3) To remove the negative sign of power reciprocal of 4/5 so it will become (5/4). So now we have , (5/4)^3*2/3 Now we can cut power 3 and 3 ,and then it will becomes :- (5/4)^2 And it is the answer You can also writ it 25/16 answer
  • 1 answers

Rudra Pratap Rajput 3 years, 7 months ago

Hlo
  • 5 answers

Rudra Pratap Rajput 3 years, 7 months ago

If we have a point there are two tangent

Kashish Jha 3 years, 7 months ago

A circle have two parallel tangents at a time but answer of these question is infinite

Prerna Dewangan 3 years, 7 months ago

A circle can have Infinite tangents

Sonakshi Kumari 3 years, 7 months ago

Infinite

Deeksha Gaur 3 years, 7 months ago

Two
  • 1 answers

Ayushi Gupta 3 years, 7 months ago

Perimeter = 2(l+b) According to question, 36 = 1/2 × 2[2(l+b)] Let length and breadth of rectangle be 4+x and x respectively... 36 = 1/2 × [2(4+x+x)] 36×2 = 8 + 4x 72 = 8 + 4x 72 - 8 = 4x 4x = 64 => x = 16
  • 5 answers

Ayushi Gupta 3 years, 7 months ago

10, 20, 30,40 ,50
10,20,30,40,50

Rani Kumari Rani Kumari 3 years, 7 months ago

10,20,30,40 and 50

Sonakshi Kumari 3 years, 7 months ago

10, 20, 30, 40 and 50 are the first 5 even numbers do divisible by 5.

Priyanshi Goyal 3 years, 7 months ago

10 20 30 40 50
  • 3 answers

Sonakshi Kumari 3 years, 7 months ago

5632 is the right answer, with using bodmas.

Ayush Anand 3 years, 7 months ago

2827 using bodmas

Amitaash Rao 3 years, 7 months ago

5632 ,using bodmas
  • 1 answers

Ashutosh Dixit 3 years, 4 months ago

126 = 2 X 3 X 3 X 7to prove A X B÷ H= -2-------(i) 35 = 5 X 7 so, H.C. F. of (126, 35) is = 7 according to question H = 126 X A + 35 X B 7 = 126A+35B 7 = 7(18A+5B) 1 = 18A+5B here 1 is possible if A = 2, B= -7 now put these values in eqn---(i) 2 X (-7)÷ 7 = -2, hence proved
  • 3 answers

Ayushi Gupta 3 years, 7 months ago

CSA = π × r × l 12320 = 22/7 × 56 × l l = 12320 × 7/22 × 1/56 L = 70 m H^2 = L^2 - R^2 H^2 = (42)^2 H = 42 m

Rani Kumari Rani Kumari 3 years, 7 months ago

Height of cone is 42cm

Ayush Anand 3 years, 7 months ago

The height of cone is 42 cm.
  • 2 answers

Ayushi Gupta 3 years, 7 months ago

Sn = n/2 (2a + (n-1)) Sn = n/2 ( 4 + 8n -8) Sn = n/2 (8n - 4) 90 = -2n + 4n^2 4n^2 - 2n - 90 = 0 2(2n^2 - n - 45 = 0) 2n^2 - n - 45 = 0 2n^2 - 10n + 9n - 45 = 0 2n(n-5) 9(n-5) = 0 (n-5) (2n + 9) = 0 "n" can't be negative or in fraction so.., n = 5

Aryan Pradhan 3 years, 7 months ago

We know that Sn=n/2[2a+(n-1)d] Now, 90=n/2[4+(n-1)8] 90=n/2(4+8n-8) 180=n(4+8n-8) 180=n(8n-4) 180=8n^2-4n 8n^2-4n-180=0 4(2n^2-n-45)=0 2n^2-n-45=0 2n^2-10n+9n-45=0 2n(n-5)+9(n-5)=0 2n=-9,n=-9/2 n-5=0,n=5
  • 1 answers

Janhavi ★ 3 years, 7 months ago

Gipgpigididyidoy?
  • 0 answers

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