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  • 1 answers

..... ...... 7 years, 4 months ago

(1+√5)/2 and (1-√5)/2
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  • 1 answers

Vikram Kumar 7 years, 4 months ago

2x^2–x–6x+3=0 x(2x–1)–3(2x–1)=0 (2x–1)(x–3)=0 So:2x–1=0 OR. x–3=0 Now x=1/2 or x=3
  • 1 answers

Shweta Kumari 7 years, 4 months ago

Let 7√11/3 be rational 7√11/3= r 7√11=3r √11=3r/7. .......(1) Here is r is rational 3r is rational 3r/7 is rational Therefore √11 is rational, which is a contradiction . So our supposition was wrong 7√11/7 is irrational.
  • 1 answers

..... ...... 7 years, 4 months ago

T7= 4, d=-4 Or, a+6(-4)= 4 a= 4+24= 28
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  • 1 answers

Devesh Chaudhary 7 years, 4 months ago

17496000
  • 1 answers

Kuldeep Kuldeep Pal 7 years, 4 months ago

Fhvcnhg FL
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  • 1 answers

Dhruvrajsinh Vala 7 years, 4 months ago

Questions are based on information given in ncert books but the questions are asked in different ways.
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  • 0 answers
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Sia ? 6 years, 5 months ago

The given AP is {tex} - 3,\frac{1}{2},2,......{/tex}
Here, a = -3
{tex}d = - \frac{1}{2} - ( - 3) = - \frac{1}{2} + 3 = \frac{5}{2}{/tex}
and n = 11
a11 = ?
We have, an = a + (n - 1)d
So, {tex}{a_{11}} = - 3 + (11 - 1)\left( {\frac{5}{2}} \right){/tex}
{tex} \Rightarrow {a_{11}} = - 3 + 25{/tex}
{tex} \Rightarrow {a_{11}} = 22{/tex}

  • 2 answers

Manikant Kumar 7 years, 4 months ago

a no. of the form p/q or which could be express in the form of p/q where p and q are integers and q is not equal to 0 is known as rational no. a no. which is not of the form p/q or which could nog be expressed in the form p/q where p and q are integers and q is not equal to 0 is known as irrational no.

Abhi Gouda 7 years, 4 months ago

p/q=0 rational number p/q=/o
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Sia ? 6 years, 5 months ago

According to the question,we have,
 a=9. Therefore, common difference d =17-9=8
let the required number of terms be n.
Therefore, Sn=636
{tex}\Rightarrow{/tex}{tex}\frac{n}{2}{/tex}[2a+(n-1)d]=636
{tex}\Rightarrow{/tex}{tex}\frac{n}{2}{/tex}[2(9)+(n-1)8]=636
{tex}\Rightarrow{/tex}n[18+8n-8]=1272
{tex}\Rightarrow{/tex}8n2+10n-1272=0
{tex}\Rightarrow{/tex}4n2+5n-636=0
{tex}\Rightarrow{/tex}4n2+53n-48n-636=0
{tex}\Rightarrow{/tex}n(4n+53)-12(4n+53)=0
{tex}\Rightarrow{/tex}(4n+53)(n-12)=0
{tex}\Rightarrow{/tex}4n+53=0 or n-12=0
{tex}\Rightarrow{/tex}n={tex}\frac{{ - 53}}{4}{/tex} or  n=12
Since number of terms cannot neither be negative nor fraction, n=12
hence, the required number of terms is 12.

  • 2 answers

Mauli Sheth 7 years, 4 months ago

By understanding the question properly and the answering it so that after completing the paper we dont have to recheck itt

Abhishek Chaudhary 7 years, 4 months ago

By hard working
  • 4 answers

Neerja Sharma 7 years, 4 months ago

Plzz explain why......??

Durgendra Singh 7 years, 4 months ago

It is not necessary that a triangle with altitude coinciding with its median will always be an equilateral triangle.It could be an isosceles triangle also.

Mumaiz Peer 7 years, 4 months ago

No

Abhi H 7 years, 4 months ago

No
  • 1 answers

Shashank Mishra 7 years, 4 months ago

No formula will be there only we substitute the value of x and y and put into other equation
  • 4 answers

Supriya Tiwari 7 years, 4 months ago

X=1

Mumaiz Peer 7 years, 4 months ago

X=2

Sonu Kumar 7 years, 4 months ago

X=2

Aditya Singh 7 years, 4 months ago

X=1
  • 1 answers

Deepak Patel 7 years, 4 months ago

a=3 and b=6
  • 2 answers

Hemant Kumar 7 years, 4 months ago

What will be the answer

Dev Patel 7 years, 4 months ago

Substitute the value and you will get your answer
  • 1 answers

Dev Patel 7 years, 4 months ago

Substitute the value and you will get your answer
  • 0 answers
  • 1 answers

Shweta Kushwaha 7 years, 4 months ago

Ncert me zitna chapter hai bss utna hi padhna hai

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