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Sia ? 3 years, 2 months ago
Initial velocity, u=20m/s
Final velocity, v=0m/s
Distance, s=50m
Using relation, v2 = u2 + 2as
02 = (20)2 + 2 × a × 50
02 = 400 + 100a
−400 = 100a
a = −400 / 100 = −4m/s2
The car's deceleration must be 4m/s2.
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Sia ? 3 years, 2 months ago
initial velocity, u = 6 m/s and final velocity, v= -4.4 m/s
time = 0.04s
thus acceleration = (v-u)/t
a =(- 4.4 - 6)/ 0.04 = -10.4/ 0.04 = -260 m/s2
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