Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Ved Prakash Verma 8 years, 7 months ago
- 0 answers
Posted by Ujjwal Dubey 8 years, 7 months ago
- 4 answers
Posted by Tirth Panchal 8 years, 7 months ago
- 0 answers
Posted by Kamalavathi Balegar 8 years, 7 months ago
- 0 answers
Posted by Suraj Srivastav 8 years, 7 months ago
- 4 answers
Posted by Pr Sangwal 8 years, 7 months ago
- 0 answers
Posted by Pr Sangwal 8 years, 7 months ago
- 1 answers
Posted by Sukh Sandhu 8 years, 7 months ago
- 0 answers
Posted by Sakshi Maurya 8 years, 7 months ago
- 1 answers
Ujjwal Dubey 8 years, 7 months ago
Posted by Samandar Gurjar 8 years, 7 months ago
- 1 answers
Posted by Samandar Gurjar 8 years, 7 months ago
- 3 answers
Posted by Shivam Malik 8 years, 7 months ago
- 1 answers
Nitin Kumawat 8 years, 7 months ago
6.5-1.5=5
6.5+1.5=8
so classes are as follows
5-8
8-11
11-14
14-17
Posted by Anushka Sharma 8 years, 7 months ago
- 1 answers
Nitin Kumawat 8 years, 7 months ago
let {tex}if AB\parallel CD \; \; and \; \; CD\parallel EF{/tex}
{tex}then AB\parallel EF {/tex}
Posted by Dushyant Garg 8 years, 7 months ago
- 0 answers
Posted by Rishi Singh 8 years, 7 months ago
- 2 answers
Posted by Chanchal Sharma 8 years, 7 months ago
- 0 answers
Posted by Atul Nag 8 years, 7 months ago
- 0 answers
Posted by Nikita Sonewane 8 years, 7 months ago
- 0 answers
Posted by Anmol Raghuvanshi 8 years, 7 months ago
- 0 answers
Posted by Arshiya Kousher 8 years, 7 months ago
- 1 answers
Nitin Kumawat 8 years, 7 months ago
ratinalisation is a method by which we remove square root from denominator from any fraction.
for ex.
rationalisation of {tex}1\over \sqrt{3}{/tex}as given below
{tex}{1\over \sqrt3} \times {\sqrt3\over \sqrt3}={\sqrt3\over 3}{/tex}
Posted by H B 8 years, 7 months ago
- 0 answers
Posted by Kunika Siddhu 8 years, 7 months ago
- 0 answers
Posted by Jayant Kumar 8 years, 7 months ago
- 1 answers
Nitin Kumawat 8 years, 7 months ago
Total radiating surface=curved surface area of cylinder
{tex}=2\pi rh{/tex}
h=28m and r={tex}\frac52cm=\frac 5{200}m{/tex}
Total radiating surface={tex}2\times \frac{22}7\times\frac5{200}\times28{/tex}
{tex}=4.4m^2{/tex}
Posted by Sakshi Sakshi 8 years, 7 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Rahul Singh 8 years, 7 months ago
0Thank You