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  • 3 answers

Aman Raj 8 years, 7 months ago

60

Tanmay Kumar 8 years, 7 months ago

140 degree is the answer

Aman Raj 8 years, 7 months ago

790321
  • 2 answers

Mudit Shukla 8 years, 7 months ago

889×889=790321

Aman Raj 8 years, 7 months ago

790321
  • 2 answers

Vineet Gulia 8 years, 7 months ago

Answer is: a=20/77 and b=1/77

Tanmay Kumar 8 years, 7 months ago

Can 3√5+2√3 is answer
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Tanmay Kumar 8 years, 7 months ago

29 is the answer
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Vineet Gulia 8 years, 7 months ago

2x-3x+12x+4 -1x+12x+4 11x+4
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Vineet Gulia 8 years, 7 months ago

By practising daily all that is done in the school

Gunjan Sabharwal 8 years, 7 months ago

By studying and making a good time table

Ft.Pahadi Bisht 8 years, 7 months ago

By doing maths 10 questions everyday ?
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Riddhi Tibriwala 8 years, 7 months ago

Using Pythagoras method u can
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Adeel Khan 8 years, 7 months ago

here a=8/15, b=-1/3, c=-1/5, since here (a+b+c)=0, then a³+b³+c³=3abc, therefore (8/15)³+(-1/3)³+(-1/5)³=x/75, 3 × 8/15 ×1/3 × 1/5 =x/75, 8/75 =x/75, therefore x=8
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5+5
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Sarvesh Aware 8 years, 7 months ago

10
  • 1 answers

Adeel Khan 8 years, 7 months ago

l || m if angle 1 and angle 2 are equal. angle 1 =60°, angle 2 =2/3 of 90°, angle 2= 60°, since we have angle 1 = angle 2, therefore l || m.
  • 1 answers

Mehak Gera 8 years, 7 months ago

Make arcs on each angle ND cut out all arcs .....Put them on a straight line forming a semi circle....The semi circle is an angle of 180° ...( Angles on straight line) hence proved
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Adeel Khan 8 years, 7 months ago

x=(3+2√2), then √x=√(3+2√2), √x=√(2+1+2√2), √x=√[(√2)²+(1)²+2×√2×1], √x=√(√2+1)², √x=(√2+1), therefore √x+1/√x =(x+1)/√x, √x+1/√x =(3+2√2+1)/(√2+1), √x+1/√x =(4+2√2)/(√2+1), √x+1/√x =(4+2√2)(√2-1), √x+1/√x = (4√2-4+4-2√2), √x+1/√x =2√2
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Lucky Raj 8 years, 7 months ago

x=x²-4 =2²-4 =4-4 =0 proved 2 is zeros of polynomial Again to prove -2 zeros of polynomial x=x²-4 =-2²-4 =4-4 =0 it's also proved -2 is zeros of the polynomial
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Hans Raj 8 years, 7 months ago

let us consider a right Ld iscosceles triangle ABC rt Ld at B

AB = BC=x       (Given as it is iscosceles triangle)

area = 1/2 x base x height

         =  1/2 x x = 1/2 x2 = 5000

x2=10000

x=100 m

AB = 100 m

BC = 100 m

AC2=AB2 + BC2

       = (100)2 + (100)2

      = 10000 + 10000

       = 20000

AC = 100{tex} \sqrt{2}{/tex} m

thus perimeter = AB + BC +AC = 100 + 100 + 100 {tex} \sqrt{2}{/tex} 

                       = 100(2 + {tex} \sqrt{2}{/tex}) m

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Mehak Gera 8 years, 7 months ago

Take under root of 2 and show it as the solution and the answer obtained is and irrational no. ....Hence proved

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