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Ilu Ahirwar 8 years, 6 months ago
Coordinate of vertex P {tex}(1, \sqrt{3}) {/tex}, Q {tex}(0,0){/tex} and R{tex}(2,0){/tex}.
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Ilu Ahirwar 8 years, 6 months ago
{tex}4 \sqrt{81}-83\sqrt{216}+155\sqrt{32}+\sqrt{225}{/tex}
by solving, we get
{tex}4 \sqrt{9^2}-83\sqrt{6^2*6}+155\sqrt{4^2*2}+\sqrt{15^2}{/tex}
{tex}4 *9-83*6\sqrt{6}+155*4\sqrt{2}+15{/tex}
{tex}36+15-498\sqrt{6}+620\sqrt{2}{/tex}
{tex}51-498\sqrt{6}+620\sqrt{2}{/tex}.
Posted by Harsh Raj 8 years, 6 months ago
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Yash Gupta 8 years, 6 months ago
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Ilu Ahirwar 8 years, 6 months ago
Sol. {tex}1\over \sqrt{7}-\sqrt{3}{/tex}* {tex}\sqrt{7}+\sqrt{3}\over \sqrt{7}+\sqrt{3}{/tex}
{tex}\sqrt{7}+\sqrt{3} \over (\sqrt{7})^2- (\sqrt{3})^2{/tex} ....({tex}(a^2-b^2)=(a-b)(a+b){/tex})
{tex}\sqrt{7}+\sqrt{3} \over 7-3{/tex}
{tex}\sqrt{7}+\sqrt{3} \over 4{/tex}.
Kajal Lanjhiyana 8 years, 6 months ago
Posted by Sarthak Agarwal 8 years, 6 months ago
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Anubhav Negi 8 years, 6 months ago
1Thank You