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  • 3 answers

Harshit Bhatnagar 2 years, 11 months ago

A Mathematics teacher asks students to collect the marks of Mathematics in Half yearly exam. She instructed to all the students to prepare frequency distribution table using the data collected. Ram collected the following marks (out of 50) obtained in Mathematics by 60 students of Class IX21, 10, 30, 22, 33, 5, 37, 12, 25, 42, 15, 39, 26, 32, 18, 27, 28, 19, 29, 35,31, 24, 36, 18, 20, 38, 22, 44, 16, 24, 10, 27, 39, 28, 49, 29, 32, 23, 31, 21,34, 22, 23, 36, 24, 36, 33, 47, 48, 50, 39, 20, 7, 16, 36, 45, 47, 30, 22, 17.

Harsh Tehlan 2 years, 11 months ago

60

Aman Pathan 2 years, 11 months ago

42
  • 0 answers
  • 3 answers

Harsh Tehlan 2 years, 11 months ago

Ppppppppppppppooooooooooooooooooooooorrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrnnnnnnnnnnnnnnnnnnnnn

Param Sidhu 2 years, 11 months ago

Given perimeter =20cm Hence each side =20/4=5cm Let ABCD be a rhombus where AC and BD are diagonals There in ∆ABC area is : {AB+BC+CA=5+5+6=16 Hence semiperimeter is 16/2=8cm} Now using Hero's Formulas: →√{s(s-a)(s-b)(s-c)} →√{8(8-5)(8-5)(8-6)} →√(8*3*3*2) →√(16*9) →√144 →12cm² Since area of rhombus is 2 times the area of triangle 2*12cm² 24cm². Hence the area of rhombus is 24cm² when its perimeter is 20cm and one of its diagonal is 6cm Thanks...... [Tip : Always draw a diagram of geometrical problems whether finding area or solving problems in geometrical,,,,] PARAM SIDHU

Param Sidhu 2 years, 11 months ago

Given perimeter =20cm Hence each side =20/4=5cm Let ABCD be a rhombus where AC and BD are diagonals There in ∆ABC area is : {AB+BC+CA=5+5+6=16 Hence semiperimeter is 16/2=8cm} Now using Hero's Formulas: √{s(s-a)(s-b)(s-c)} √{8(8-5)(8-5)(8-6)} √(8*3*3*2) √(16*9) √144 12cm² Since area of rhombus is 2 times the area of triangle 2*12cm² 24cm² Hence the area of rhombus is 24cm² when its perimeter is 20cm and one of its diagonal is 6cm Thanks...... [Tip : Always draw a diagram of geometrical problems whether finding area or solving problems in geometrical,,,,] PARAM SIDHU(name)
  • 4 answers

Brajesh Prajapati 2 years, 10 months ago

Heron formula is √s-a, s-b s-c a+b+c\2

Ridhima Khitta 2 years, 10 months ago

By dividing that rectangle into triangle and then taking out area simple

Param Sidhu 2 years, 11 months ago

When we construct a diagonal in rectangle we get two congruent triangles and area of congruent triangle are equal in measure so if you get area of one triangle formed after constructing a diagonal the atea of rectangle would be two times the area of that triangle or just multiply area of that triangle with 2 you will get area of rectangle

Tanishka Panchal 2 years, 11 months ago

It is used when you draw one diagonal then you get two triangle then find the area of both triangle and add the area
  • 1 answers

Param Sidhu 2 years, 11 months ago

625=5*5*5*5 →625=5^4 Hence =5^x-3(2x-3)=625→5^x-3(2x-3)=5⁴ (equal base will get canceld we will remaining with powers only) →x-3(2x-3)=4 →x-6x+9=4→-5x=4-9→-5x=-5→x=-5/-5→→x=1 Therefore the required value of x is 1
  • 3 answers

Jaiditya Sinha 2 years, 10 months ago

X = 20

Harshit Bhatnagar 2 years, 11 months ago

3x=56+4 3x=60 x=60/3 x=20

Shubh Sharma 2 years, 11 months ago

3X=56+4 3X=60 X=60/3 X=20
  • 1 answers

Sree Ranga K 2 years, 11 months ago

Hi
  • 4 answers

Jaiditya Sinha 2 years, 10 months ago

2√2

Sandhya Prajapati😘😘 2 years, 11 months ago

3

Dhatri Garg 2 years, 11 months ago

If x^2 is 2 then x= sqrt2 then x^3 = (sqrt2)^3= 2sqrt2

Krish Chaurasiya 2 years, 11 months ago

X3
  • 1 answers

Sandhya Prajapati😘😘 2 years, 11 months ago

78/99,79/99,80/99,81/99,82/99,83/99,84/99,85/99,86/99,87/99
  • 2 answers

Rithish B 2 years, 11 months ago

2/5

Sandhya Prajapati😘😘 2 years, 11 months ago

Answer is 7
  • 3 answers

Sanket ... 2 years, 11 months ago

Hi Diksha

Diksha Laniya🐥 2 years, 11 months ago

Hiii

Sanket ... 2 years, 11 months ago

Total surface area of the room=2(lh+lb+hb)m 2 =2[9×6.5+9×8+8×6.5]m 2 =365m 2 Area of the door =l×b=2×1.5=3m 2 Area of the windows=l×b=1.5×1=1.5m 2 ∴ Surface area of walls=TSA of room −Area of door−Area of windows =365−3−1.5=360.5m 2 Cost of whitewashing per square meter=Rs. 6.40 ∴ Cost of whitewashing the walls=Rs. 6.40×360.5 =Rs. 2307.2.
  • 1 answers

Aastha Costin 2 years, 10 months ago

Histogram graph ,pie graph,bar graph , Double bar graph
  • 2 answers

Krishna Patel 2 years, 11 months ago

3+2√2

Ani Sha 2 years, 11 months ago

3+2√2
  • 2 answers

Sanket ... 2 years, 11 months ago

Good job ???????

Harshita Drall 2 years, 11 months ago

I don't know
  • 1 answers

Aditya Shokeen 2 years, 11 months ago

Quadrilateral becf is a parallelogram
  • 4 answers

Mànyà Jain 2 years, 11 months ago

(a+b)²=a²+b²2ab

Khushi ^_^ 2 years, 11 months ago

(a-b)²=a²+b² -2ab

Khushi ^_^ 2 years, 11 months ago

(a+b)²=a²+b²+2ab

Shreya Yadav 2 years, 11 months ago

N
  • 3 answers

Subhra Mishra 2 years, 10 months ago

(12)^2 × (17)^2 {12×17}^2 {204}^2 41616

Harshita Drall 2 years, 11 months ago

I don't know

Raiput Aaditya 2 years, 11 months ago

Aaj Tak hai Jaan hai january month the other family members of the other family members of the citizen of the other hand the citizen of which are the other hand the citizen of India Today the other hand the wildcats held and the citizen and the wildcats the wildcats held Stanford law school the citizen of India Today conclave the citizen of which are both well and that the other family the other hand the other family the best of which are you doing recently the other hand if you are not in the citizen of which were and the wildcats the other day that I have to be able to do it in the citizen of the other hand I have been working on it again the other day that I have to be the other hand the other family the best way to get the citizen of India Today the other day and night and night and I have a great time in mumbai dobara of the wildcats held and the citizen of the other hand the citizen of India Today conclave the wildcats held the other day and the wildcats the other family and friends of the citizen of which are the other hand the other family the best of which are both well I have to be able to be the first the other day and night and the wildcats the other hand the wildcats held and the citizen of the other day and the wildcats their and I have a great time in the wildcats held the other hand the other family and friends of the wildcats held and the citizen of India Today the other day and night and the wildcats the other hand the other day I have a Little bit more about your help in the wildcats held the other family members and the citizen of which are you doing this to be a good time to be able to get to be able the citizen of India and the other day that I will be the first the other hand the citizen of the other family members of which are the other hand the wildcats held and the citizen of which are both well and that is the other family members to be able and willing I have to be the first the citizen of the other day and I have been a Little bit more about this to the other hand the other family members and I am a good morning please find my resume for me to do it for me and the other hand if you doing today my siste and I have to be a good time
  • 2 answers

Mànyà Jain 2 years, 11 months ago

Greece

Mr. King 2 years, 11 months ago

France
  • 1 answers

Ishita Sirse 2 years, 11 months ago

It's not a polynomial because polynomials contain variables with non negative exponents and rational variable and √ is irrational
  • 1 answers

Sanket ... 2 years, 11 months ago

√2×√2 = 2
  • 1 answers

Sanket ... 2 years, 11 months ago

AD || BC and BD is a transversal. ∴ ∠ADB = ∠CBD [ ∵ Alternate interior angles are equal] ⇒ ∠ADP = ∠CBQ Now, in ∆APD and ∆CQB, we have AD = CB [Opposite sides of a parallelogram ABCD are equal] PD = QB [Given] ∠ADP = ∠CBQ [Proved] ∴ ∆APD ≅ ∆CQB [By SAS congruency] (ii) Since, ∆APD ≅ ∆CQB [Proved] ⇒ AP = CQ [By C.P.C.T.] (iii) Since, AB || CD and BD is a transversal. ∴ ∠ABD = ∠CDB ⇒ ∠ABQ = ∠CDP Now, in ∆AQB and ∆CPD, we have QB = PD [Given] ∠ABQ = ∠CDP [Proved] AB = CD [ Y Opposite sides of a parallelogram ABCD are equal] ∴ ∆AQB = ∆CPD [By SAS congruency] (iv) Since, ∆AQB = ∆CPD [Proved] ⇒ AQ = CP [By C.P.C.T.] (v) In a quadrilateral ∆PCQ, Opposite sides are equal. [Proved] ∴ ∆PCQ is a parallelogram.

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