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  • 1 answers

Harshita Dashoni 2 years, 3 months ago

Zero polynomial is a constant polynomial whose coefficients are all equal to 0. Zero of a polynomial is the value of the variable that makes the polynomial equal to zero. Therefore, zero of the zero polynomial is any real number
  • 1 answers

Vanshkumar Goyal 2 years, 3 months ago

Monomial Binomial Trinomial
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  • 1 answers

Bhagyaa Kriplani 2 years, 3 months ago

terminate and repeating decimal
  • 2 answers

Sonali Singh 2 years, 2 months ago

Thanks a lot 😃😃😃🫂

Harshita Dashoni 2 years, 3 months ago

The given polynomial is Q(r)=px^2+5x+r It is also given that (x-2) and (x-1/2)are the factor of Q(x) which means that Q (2)=0 and Q(1/2) =0 Let us first substitute Q(2)=0 in Q(x)=px^2+5x+r as shown below : =Q(r)=px^2+5x+r =Q(2)=p(2)^2+5(2)+r = 0=p(4)+10+r = 0=4p+10+r =4p+r=-10 ...........(1) Now substitute Q(1/2)=0in Q(x)=px^2+5x+r as shown below: =Q(x)=px^2+5r+r =Q(1/2)=p(1/2)+5(1/2)+r = 0 =p/4+5/2+r = 0 =p+5(2)+r(4)/4 = 0 =p+10+4r = p+4r= -10 ...........(2) Now subtracting the equations (1) and (2) we get = (4p - p) +(r -4r) = -10+10 = 3p - 3r =0 = 3p = 3r = p = r Hence p = r is proved
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Pooja Soni 2 years, 3 months ago

Yes
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Shilpa Jain 2 years, 3 months ago

(1/x)= (1000/125)

(1/x)1/3 = ((10/5)3)1/3

hence, 

(1/x)​​​​​​​1/3 = 10/5= 2​​​

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Bhawna Tandon 2 years, 3 months ago

Divide both equations (LHS and RHS )by xy New set of eqs will b 6/y+3/x=6 2/y+4/x=5 Put 1/x=a,1/y=b >>6b+3a=6 2b+4a=5 Solve for a and b a=1,b=1/2 >> x=1,y=2
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Shravani Hatwar 2 years, 3 months ago

0.474747474747.....~
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Bhawna Tandon 2 years, 3 months ago

area =root3/4*a^2 9 root3=root3/4 a^2 36=a^2 a=6cm
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Abhay Avinash Khanke 2 years, 3 months ago

Estimated to 41.1421
  • 1 answers

Sonali Singh 2 years, 3 months ago

Put the formula of root( a+ root b)^3. And then you have your answer and remember the rules for squaring an irrational number.
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Sonali Singh 2 years, 3 months ago

P(x)=1/2
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