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Yogita Ingle 7 years, 4 months ago

Here the length of the sides of the quadrilateral is given as
AB = 26 m, BC = 27 m, CD = 7 m, DA = 24 m
Diagonal AC is joined.
Now, in triangle ADC
By applying Pythagoras theorem

<nobr>AC2=AD2+CD2</nobr><amp-mathml data-formula="\[AC^{2} = AD^{2}+CD^{2}\]" inline="" layout="container"></amp-mathml>

<nobr>AC2=242+72</nobr><amp-mathml data-formula="\[AC^{2} = 14^{2}+7^{2}\]" inline="" layout="container"></amp-mathml>

AC = 25 m

Now area of triangle ABC

Perimeter = 2s = AB + BC + CA

2s = 26 m + 27 m + 25 m

s = 39 m

By using Heron’s Formula

The area of a triangle = √ <nobr>s×(s−a)×(s−b)×(s−c) </nobr><amp-mathml data-formula="\[\sqrt{s\times (s-a)\times(s-b) \times(s-c) }\]" inline="" layout="container"></amp-mathml>

= <nobr>√ 39×(39−26)×(39−27)×(39−25)</nobr><amp-mathml data-formula="\[\sqrt{39\times (39-26)\times (39-27) \times (39-25)}\]" inline="" layout="container"></amp-mathml>

= <nobr>291.84m2</nobr><amp-mathml data-formula="\[291.84m^{2}\]" inline="" layout="container"></amp-mathml>

Thus, the area of a triangle is <nobr>291.84m2</nobr><amp-mathml data-formula="\[291.84m^{2}\]" inline="" layout="container"></amp-mathml>

Now for area of triangle ADC

Perimeter = 2s = AD + CD + AC

= 25 m + 24 m + 7 m

s = 28 m

By using Heron’s Formula

The area of a triangle = <nobr>√ s×(s−a)×(s−b)×(s−c)</nobr><amp-mathml data-formula="\[\sqrt{s\times (s-a)\times(s-b) \times(s-c) }\]" inline="" layout="container"></amp-mathml>

= <nobr>√ 28×(28−24)×(28−7)×(28−25)</nobr><amp-mathml data-formula="\[\sqrt{28\times (28-24)\times (28-7) \times (28-25)}\]" inline="" layout="container"></amp-mathml>

= <nobr>84m2</nobr><amp-mathml data-formula="\[84m^{2}\]" inline="" layout="container"></amp-mathml>

Thus, the area of a triangle is <nobr>84m2</nobr><amp-mathml data-formula="\[84m^{2}\]" inline="" layout="container"></amp-mathml>

Therefore, Area of rectangular field ABCD

= Area of triangle ABC + Area of triangle ADC

= 291.84 + 84

= 375.8 m2

  • 1 answers

Adit Shah 7 years, 4 months ago

Numder system
  • 2 answers

Ay K 7 years, 4 months ago

Please explain

Himanshi Upadhyay 7 years, 4 months ago

The area of this triangle is 1125 square.
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  • 1 answers

Shreeya Gupta 7 years, 4 months ago

(3)*5×4/5=(3)*4=81
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Anmol Prasad 7 years, 4 months ago

Area of rectangle = l×b. Area of square =s^2. Area of rhombus =1/2×product of two diagonals. Area of parallelogram =b×h. Area of trapezium =1/2×height ×sum of parallel sides
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9
  • 0 answers
  • 2 answers

Prashansa Rastogi 7 years, 4 months ago

It is-9/2

Vratika Rajesh Bawangade 7 years, 4 months ago

-9/2
  • 0 answers
  • 2 answers

Prashansa Rastogi 7 years, 4 months ago

The pair who make 180 degree is known as linear pair

Viren Jadhav 7 years, 4 months ago

Linear pair means a straight line having two angles making 180 degree is called linear pair
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Asmita Sharma 7 years, 4 months ago

Let x=23.434343....(1) Then 100x=2343.434343..(2). On subtracting 1 from 2 We get 99x= 2320 X=2320/99.
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  • 1 answers

Asmita Sharma 7 years, 4 months ago

(1) x_y=1 Y=x_1 On putting x=1 Then y=0 If x=2,y=1 If x=3, y=2 (2)2x+y=8 Y=8_2x If x=2, y=4 If x=3, y=2 If x=4,y=0 Now draw the figure by yourself through this x and y. Now AtoQ Let shaded area name ABC then base ofabc=bc=9 Height=3 Area=1/2×b×h = 13.5 sq unit answer .
  • 1 answers

#Rikki #Maggi 7 years, 4 months ago

2337xsquare
  • 4 answers

Asmita Sharma 7 years, 4 months ago

What is the answer?

Asmita Sharma 7 years, 4 months ago

X cube +27 = x cube +3 cube Ato FORMULA = (x+3)(x square _ 3x+ 9).

#Rikki #Maggi 7 years, 4 months ago

(x+3)cube

Simranjot Kaur 7 years, 4 months ago

(X+3)cube
256
  • 2 answers

Bhawani Shekhwat 7 years, 4 months ago

9

Lavesh Bisht 7 years, 4 months ago

2+2=4 so 3×3=?
  • 1 answers

Priya Raj 7 years, 4 months ago

(a+2b+5c) whole square
  • 3 answers

Asmita Sharma 7 years, 4 months ago

47/100

Suraaj Jain 7 years, 4 months ago

This is like this x = 0.47 100x = 47 x=47/100

Swati Dhull 7 years, 4 months ago

47/100

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