Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Naresh Kumar 6 years, 7 months ago
- 0 answers
Posted by Swastik Gupta 6 years, 7 months ago
- 1 answers
Posted by Manik Jain 6 years, 7 months ago
- 2 answers
Posted by ?☺???Hrishi Khapekar???☺? 6 years, 7 months ago
- 1 answers
Posted by Aditya Singh 6 years, 7 months ago
- 3 answers
Posted by Rounak Kumar Choudhary 6 years, 7 months ago
- 2 answers
Posted by Abhishek Sonkar 6 years, 7 months ago
- 3 answers
Manisha Singh 6 years, 7 months ago
Santoshi Verma 6 years, 7 months ago
Posted by Awanish Kumar 6 years, 7 months ago
- 1 answers
Posted by Sanjay Mapari 6 years, 7 months ago
- 1 answers
Posted by Anjali Lily 6 years, 7 months ago
- 2 answers
Laxmi Singh 6 years, 7 months ago
Posted by Kapil Gyanani 6 years, 7 months ago
- 0 answers
Posted by Vrund Thakkar 6 years, 7 months ago
- 2 answers
Posted by Ilma Saifi 6 years, 7 months ago
- 0 answers
Posted by Lakhvir Singh 6 years, 7 months ago
- 1 answers
Posted by Kittu Thakur 6 years, 7 months ago
- 2 answers
Posted by Sneha Yadav 6 years, 7 months ago
- 1 answers
Posted by Manmeet Singh Sethi 6 years, 7 months ago
- 0 answers
Posted by C.Kumar Kumar 6 years, 7 months ago
- 0 answers
Posted by Kumar Vivek 6 years, 7 months ago
- 1 answers
Posted by T. Laxmi Chaitanya Sweety 6 years, 7 months ago
- 0 answers
Posted by Avjot Singh Mann 6 years, 7 months ago
- 1 answers
Gaurav Seth 6 years, 7 months ago
Given (x + y + 4) = 0
⇒ x + y = –4 → (1)
Cubing on both the sides, we get
(x + y)3 = –43
⇒ x3 + y3 + 3xy(x + y) = –64
⇒ x3 + y3 + 3xy(–4 ) = –64 [From equation (1)]
⇒ x3 + y3 –12xy + 64 = 0
Posted by Simran Rana 6 years, 7 months ago
- 0 answers
Posted by Akshita Atram 6 years, 7 months ago
- 4 answers
Posted by Arpita Dash 6 years, 7 months ago
- 2 answers
Posted by Sabeena Banu 6 years, 7 months ago
- 0 answers
Posted by Nitesh Kumar 6 years, 7 months ago
- 0 answers
Posted by Utkarsh Modi 6 years, 7 months ago
- 1 answers
Arpita Dash 6 years, 7 months ago
Posted by Aabeda Mansuri 6 years, 7 months ago
- 0 answers
Posted by Sumayya Ruksana 6 years, 7 months ago
- 2 answers
Gaurav Seth 6 years, 7 months ago
Radha made a picture of an aeroplane with coloured paper as shown in figure. Find the total area of the paper used.

Ans. Area of triangular part I: Here, Semi-perimeter
= 5.5 cm
Therefore, Area = 
= 
=
= 

Area of triangular part II = Length x Breadth 
Area of triangular part III (trapezium): 
=
(AB + DC)
=
(1 + 2) 
= 
=

Area of triangular parts IV & V:

Total area = 2.4825 + 6.2 + 1.299 + 9 

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide