CBSE > Class 09 > Mathematics | CBSE Board | Homework Help

Solution:- since, x=√2a y=√3b z=c So, x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx) Now, (√2a)³+(√3b)³+(c)³-3•√2a•√3b•c =(√2a+√3b+c)(2a²+3b²+c²-√6ab-√3bc-√2ca).

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Verify that : x³+y³=(x+y)(x²-xy+y²)

Posted by Hasini Thakkalapally 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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Find the correct alternative abb_ _ab_b_bb aa

Posted by Som Badmash 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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Find the value of x if ( 6 by 5) ^x multiply(5/6)^2x

Posted by Raj Wardhan 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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2 upon root5 + root3 +1 upon root2 + root3 minus 3 upon root5 + root2

Posted by Mohit Rajpurohit 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sahil Goswami 6 years, 5 months ago

2upon root5 +root3+1upon root2+root3-3upon root5+root2=2upon root8+1upon root5-3upon root7=2+1-3 upon root8+root3+root7=root20

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Rationalize the denominator of two under root 3 + 5 under root 7 upon under root 5 + under root 6? How we can rationalize it?

Posted by Pratyush Panwar 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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If x=[ (2p+3q)^1/2+(2p-3q)^1/2] /[(2p+3q)^1/2-(2p-3q)^1/2],find the value of 3qx^2-4px+3q

Posted by Nonu Kkr 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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1.272727.......=1.27

Posted by Rahinish Rahinish 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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Can anyone give me tips to practice maths.plzz

Posted by Pradhyumn Thapliyal 6 years, 5 months ago

CBSE > Class 09 > Mathematics

4 answers

Shambhoo Prasad Jhariya 6 years, 5 months ago

practise

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Pradhyumn Thapliyal 6 years, 5 months ago

Plss

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Pradhyumn Thapliyal 6 years, 5 months ago

Plzz dedo

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Suby Mahajan 6 years, 5 months ago

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Find x + y = -14 & xy=84

Posted by Ritik Singh 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Surya Jatt? 6 years, 5 months ago

X=-112,y=98

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ANSWER

Find the rational number between -2and5

Posted by Ritik Singh 6 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Sia ? 6 years, 5 months ago

Given numbers are -2 and 5.
A rational number between - 2 and 5 is {tex}\frac{1}{2}[-2+5]=\frac{3}{2}{/tex}
A rational number between {tex}\frac{3}{2}{/tex} and 5 is {tex}\frac{1}{2}\left[\frac{3}{2}+5\right]=\frac{1}{2}\left[\frac{3+10}{2}\right]=\frac{13}{4}{/tex}
Therefore, two rational numbers between -2 and 5 are {tex}\frac{3}{2} {/tex}and {tex}\frac{13}{4}.{/tex}

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Diya Sony 6 years, 5 months ago

-2 = -20/10 5. = 50/10 Some rational number between -2 and 5 are... -19/10, 1/10, 5/10, 49/10

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ANSWER

2.22222222

Posted by Akshay Sawant 6 years, 5 months ago

CBSE > Class 09 > Mathematics

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(399)square

Posted by Aditya Gour 6 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Deepshikha Mishra 6 years, 5 months ago

Yes yhe forst answer is right

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Yogita Ingle 6 years, 5 months ago

(399)² = (400 -1)²
= (400)² + 1² - 2 (400)(1)
= 160000 + 1 - 800
= 159200 + 1
= 159201

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Irrational number betwen1/7 and 2/7

Posted by Satbeer Singh 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Given numbers are {tex}\frac{1}{7}{/tex}and {tex}\frac{2}{7}.{/tex}
{tex}\frac{1}{7}=0.142857142857 \ldots{/tex}
{tex}\Rightarrow \frac{1}{7}=0 . \overline{142857}{/tex}
{tex}\frac{2}{7}=2 \times \frac{1}{7}=0.285714285714 \ldots{/tex}
{tex}\Rightarrow \quad \frac{2}{7}=0 . \overline{285714}{/tex}
To find irrational numbers between {tex}\frac{1}{7}{/tex}and {tex}\frac{2}{7}{/tex}, we find numbers which are non-terminating and non-repeating.
There are infinitely many such numbers lying between {tex}\frac{1}{7}{/tex}and {tex}\frac{2}{7}{/tex}.
Examples: