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Ask QuestionPosted by Prajakta Gedam 5 years, 3 months ago
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Posted by Noor Samina 5 years, 3 months ago
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Posted by Sunita Kamal 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
(a - b) (a + b) = a2 - b2
(5 - √5)(5 + √5) = 52 - √5 2
= 25 - 5
= 20
Posted by Sachin Singh 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
Axiom 1: If a ray stands on a line, then the sum of two adjacent angles so formed is 180.
Axiom 2: If the sum of two adjacent angles is 180°, then the non-common arms of the angles form a line.
Posted by Abhishek Jangid 5 years, 3 months ago
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Shakti Sarkar 5 years, 3 months ago
Posted by Komal Oberoi 5 years, 3 months ago
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Hema Addapaka 5 years, 3 months ago
as per cbse guidelines
question paper consists of
1m M.C.Qs 20 questions 1 x 20 = 20
2m 6 questions 2 x 6 = 12
3m 8 questions 3 x 8 = 24
4m 6 questions 4 x 6 = 24 total - 20m + 12m + 24m + 24m = 80m
Posted by Deepika Jangid 5 years, 3 months ago
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Sia ? 5 years, 3 months ago
We have,
{tex}\left(16^{-\frac{1}{5}}\right)^{\frac{5}{2}}{/tex} = {tex}16^{-\frac{1}{5} \times \frac{5}{2}}{/tex} [as (am)n= am×n ]
= {tex}16^{-\frac{1}{2}}{/tex}
= {tex}\frac{1}{16^{\frac{1}{2}}}{/tex}
= {tex}\frac{1}{\left(4^{2}\right)^{\frac{1}{2}}}{/tex}
= {tex}\frac{1}{4}{/tex}.
Posted by Shivansh Pandey 5 years, 3 months ago
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Subhashis Bhagat 5 years, 3 months ago
Posted by Shubham Mehta 5 years, 3 months ago
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Sia ? 5 years, 3 months ago
For solutions go here: https://mycbseguide.com/ncert-solutions.html
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Bikas Maji 5 years, 3 months ago
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Ashish Jha 5 years, 3 months ago
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