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Yogita Ingle 5 years, 4 months ago
a3 - b3 = (a - b) • (a2 + ab + b2)
x3 - 1 = x3 - 13 = (x - 1) • (x2 + x + 1)
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Yogita Ingle 5 years, 5 months ago
No all angles of rhombus are not equal.
All sides are congruent
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Yogita Ingle 5 years, 5 months ago
Let the smaller number = x
bigger number = 5x. -----(we need this.)
if 21 is added to both; 5x+21 = 2×(x+21)
5x + 21 = 2x + 42
5x - 2x = 42 - 21
3x =. 21
x = 21/3= 7
So the positive number is = 5×7 = 35
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Sia ? 5 years, 5 months ago
In figure,
transversal AD intersects two lines
PQ and RS at point B and C respectively.
Ray BE is the bisector of {tex}\angle BACQ{/tex}
So, {tex}\angle \mathrm{ABE}=\angle \mathrm{EBQ}=\frac{1}{2}(\angle \mathrm{ABQ}){/tex}
and ray CG is the bisector of {tex}\angle \mathrm{BCS}{/tex};
and {tex}B E \| C G{/tex}
We have to prove {tex}\mathrm{PQ} \| \mathrm{RS}{/tex}
Since {tex}\mathrm{BE} \| \mathrm{ CG}{/tex}
& line AD is a transversal
{tex}\angle \mathrm{ABE}=\angle \mathrm{BCG}{/tex} (Corresponding angles are equal)
{tex}\frac{1}{2}(\angle \mathrm{ABQ})=\frac{1}{2}(\angle \mathrm{BCS}){/tex}
{tex}\angle \mathrm{ABQ}=\angle \mathrm{BCS}{/tex}
But, these angles are the corresponding angles formed by transversal AD with PQ and RS
Posted by Akshay Kumar 5 years, 5 months ago
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Yogita Ingle 5 years, 5 months ago
Complementary Angles:
Two angles are called complementary angles, if their sum is one right angle i.e. 90°.
Each angle is called the complement of the other.
Example, 20° and 70° are complementary angles, because 20° + 70° = 90°.
Clearly, 20° is the complement of 70° and 70° is the complement of 20°.
Supplementary Angles:
Two angles are called supplementary angles, if their sum is two right angles i.e. 180°.
Each angle is called the supplement of the other.
Example, 30° and 150° are supplementary angles, because 30° + 150° = 180°.
Clearly, 30° is the supplement of 150° and 150° is the supplement of 30°.
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Namrata Jindal 5 years, 4 months ago
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