No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question

    • Posted by Manas Pratim Talukdar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Aryan Kumar 6 years, 1 month ago

    Let ABCD be a square. Let the diagonals AC and BD intersect each other at a point O. To prove that the diagonals of a square are equal and bisect each other at right angles, we have to prove AC = BD, OA = OC, OB = OD, and AOB = 90º. In ABC and DCB, AB = DC (Sides of a square are equal to each other) ABC = DCB (All interior angles are of 90) BC = CB (Common side) ABC = DCB (By SAS congruency) AC = DB (By CPCT) Hence, the diagonals of a square are equal in length. In AOB and COD, AOB = COD (Vertically opposite angles) ABO = CDO (Alternate interior angles) AB = CD (Sides of a square are always equal) AOB = COD (By AAS congruence rule) AO = CO and OB = OD (By CPCT) Hence, the diagonals of a square bisect each other. In  AOB and COB, As we had proved that diagonals bisect each other, therefore, AO = CO AB = CB (Sides of a square are equal) BO = BO (Common) AOB = COB (By SSS congruency) AOB = COB (By CPCT) However,AOB + COB = 180 (Linear pair) 2 AOB = 180º AOB = 90º Hence, the diagonals of a square bisect each other at right angles.

    0Thank You

    ANSWER

    • Posted by Lahari Yellanki 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Aryan Kumar 6 years, 1 month ago

    parallelogram=opposite sides equal +opposite angles equal Step-by-step explanation: we are given that ab=cd and bc=ad join ac ac=ac in Δabc andΔcda we have ab=cd bc=ad ac=ac Δabc ≅Δcda ⇒∠a=∠c  ∠b=∠d hence proved Read more on Brainly.in - https://brainly.in/question/8401070#readmore

    0Thank You

    ANSWER

    • Posted by Sm Nandu 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Anushka Chaudhary 6 years, 1 month ago

    Option c

    0Thank You

    ANSWER

    • Posted by Kalwa Sushmitha 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Md Anowar Haque 6 years, 1 month ago

    Option d

    0Thank You

    ANSWER

    • Posted by Karan Arora 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Aryan Kumar 6 years, 1 month ago

    Vertex B of ABC is located outside the circle with centre O. Side AB intersects chord CE at point E and side BC intersects chord AD at point D with the circle. We have to prove that ABC = [AOC – DOE] Join OA, OC, OE and OD. Now AOC = 2AEC [Angle subtended by an arc at the centre of the circle is twice the angle subtended by the same arc at any point in the alternate segment of the circle] AOC = AEC …(i) Similarly DOE = DCE ….(ii) Subtracting eq. (ii) from eq. (i), [AOC – DOE] = AEC – DCE ….(iii) Now AEC = ADC [Angles in same segment in circle] ….(iv) Also DCE = DAE [Angles in same segment in circle] ….(v) Using eq. (iv) and (v) in eq. (iii), [AOC – DOE] = DAE + ABD – DAE [AOC – DOE] = ABD Or [AOC – DOE] = ABC Hence proved.

    0Thank You

    ANSWER

    • Posted by Manoj Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Yalamalli Sivakumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Avinash Jiddimani 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Tanisha Chhikara 6 years, 1 month ago

    Two terms

    0Thank You

    Rohit Maurya 6 years, 1 month ago

    Which have two variable

    0Thank You

    ANSWER

    • Posted by Ritik Singh 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Rohit Maurya 6 years, 1 month ago

    ^

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Rohit Maurya 6 years, 1 month ago

    .a(16a3-5)

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Rohit Maurya 6 years, 1 month ago

    =1/5

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Ã.P.W.B.Đ ⚡ 6 years, 1 month ago

    Lateral surface area of cone=pi×r×l =pi ×r×1 =pi×r.

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Rohit Maurya 6 years, 1 month ago

    Sorry up is wrong. ... New ans is =22/7×31 (31+31)= 6035.08 ......

    0Thank You

    Rohit Maurya 6 years, 1 month ago

    Total surface area= 4/3×31(31+31) =6035.08.....

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Rohit Maurya 6 years, 1 month ago

    Ratio of volum = 4/3×22/7×2r :4/3×22/7×r =2:1.....

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Rohit Maurya 6 years, 1 month ago

    Ratio of these volume = ||r×r×h:||r×r×h =22/7×3×3×4:22/7×4×4×3= 3:4

    0Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Aryan Kumar 6 years, 1 month ago

    Brainly.in What is your question? Secondary School Math 5 points A hemispherical tank is emptied by a pipe at the rate of 5 litres per minute how long will it take to half empty the tank if it is meter in diameter Ask for details Follow Report by Ankitkarn1177 02.01.2018 ankitkarn1177 what answer Log in to add a comment Answers Me · Beginner Know the answer? Add it here! santy2 santy2 Ace We first get the volume of the hemisphere. Formulae =2/3 pie r3 The radius =1/2m=0.5m Volume=2/3 × 0.5×0.5×0.5×3.142=0.2618m3 Convert to litres: 1 cubic meter=1000 litres 1000×0.2618=261.8litres It will be emptied to half:261.8/2=130.9m3 Rate:5litres per minute. Time taken =130.9/5=26.18minutes 26.18 minutes.

    0Thank You

    ANSWER

    • Posted by Adithya Vardhan 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Rohit Maurya 6 years, 1 month ago

    Here, Am=1/2ac (:.m is mid point) Abm~= mbc (why) Mc=am (:.above prove ) Mb=mb (common ) \abm=\mba (:.mis the midpoint and busector of \abc) =by (sas) Then, \abm=\mcb ( by c.p.c.t ) So, Mb=mc& mb=am (:.am=bm) So, Am=bm=1/2ac...........

    0Thank You

    ANSWER

    • Posted by Pramud Kakati 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Ashu Mahto 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Pramud Kakati 6 years, 1 month ago

    1.0656666E13

    0Thank You

    ANSWER

    • Posted by Zaheen Reyaz 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Rohan Sirohi 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Neha Verma 6 years, 1 month ago

    First correct urr.. question

    0Thank You

    Neha Verma 6 years, 1 month ago

    22

    1Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Murari Sah 6 years, 1 month ago

    Given side of solid cube = 12cm Volume of big cube = A^3 = (12)^3= 1728cm^3. The cube cut into eight eqaul volume cubes. Volume of 8 cubes=1728cm^3 Volume of 1small cube=1728/8=216cm^3 Now, volume of small cube=(a)^3=216 a=6cm. Surface area of big cube (S1)=6A^2=6x12^2=864cm^2. Now surface area of small cube (S2)=6a^2=6x6^2=216cm^2. Now S1/S2=864/216=4/1=4:1

    1Thank You

    ANSWER

    • Posted by Rajvi Kantaria 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Satyam King 6 years, 1 month ago

    4root6+ 3root6 + 12root10-8root10 4+3root6+12-8root10 7root6+4root10

    1Thank You

    ANSWER

    • Posted by Sidharth Nakose 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Sachin Sharma 6 years, 1 month ago

    Please check your answer

    0Thank You

    ANSWER

    • Posted by Sushma Pandey 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Shreeya Chauhan 6 years, 1 month ago

    3(y+x)=14 y+x=14-3 y+x=11

    1Thank You

    ANSWER

    • Posted by Aryan Kumar 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Abdut Taiyeb Matcheswala 6 years, 1 month ago

    The diameter of moon is 1/4 of earth so the area of earth is 4x. For this reason ratio of earth and moon is 1:16. Because Moon is 1/4. Is equal to 4. And earth is four times of four so earth is equal to 4×4=16 so the ratio is 1:16. 1 is moon. 16 is earth

    2Thank You

    ANSWER

    • Posted by Vanshi Ka 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Vanshi Ka 5 years, 8 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Satyam King 6 years, 1 month ago

    you are gadha ho kya

    0Thank You

    Abdut Taiyeb Matcheswala 6 years, 1 month ago

    What is the meaning of this question

    1Thank You

    ANSWER

    • Posted by Dheeraj Jaat 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Abdut Taiyeb Matcheswala 6 years, 1 month ago

    . C.S.A=πrl. H=4 R=3 L=? Find L=L= √r square + h square L= √3 square + 4 square L= 9+16.=25 Because √3=9 √4=16 So L is 5. Because √5=25 Now. C.S.A. = πrl = 22/7×3×5 = 3.14×3×5 = 9.42×5 = 47.10 C.S.A of. Cone is 47.10

    1Thank You

    Yogita Ingle 6 years, 1 month ago

    Curved Surface Area = π r l
    = 3.14 × 4 × 3
    = 37.68 sq.cm

    1Thank You

    ANSWER

    • Posted by Payal Adhikari 6 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Satyam King 6 years, 1 month ago

    gadhi

    0Thank You

    ANSWER

    myCBSEguide App

    myCBSEguide

    Trusted by 1 Crore+ Students

    Install Now

    Test Generator

    Test Generator

    Create papers online. It's FREE.

    Try Now

    CUET Mock Tests

    CUET Mock Tests

    75,000+ questions to practice only on myCBSEguide app

    Install Now
    Google Play

    Download myCBSEguide App

    All Courses

    Other Websites

    CBSE Courses

    Resources

    Corporate

    NCERT Solutions

    CBSE Sample Papers

    All Content and Intellectual Property is under Copyright Protection | myCBSEguide.com ©2007-2025